similar to: Ayuda para hacer una lista

Muchas fracias por la rapida contastacion Javier. Si, ya me he dado cuenta que a veces es mas limpiar y formatear que calcular. Lo que yo necesito hacer no es crear un data.frame, es crear una lista por cada grupo/condicion de muestras. Y queria hacerlo en un for loop, para que no tuviese que indicar cuantas listas necesito si no que cogiese esa informacion del usuario (y) Creo que no me

Hola Leticia Acomodar datos para analizar suele llevar más trabajo que el análisis. Yo prefiero en un data.frame colocar todos los datos, porque siempre es más fácil filtrar que agregar. Cuándo tengo el data.frame con todo, realizo un plot (datos), y muchas veces en la gráfica veo cosas que me llaman la atención, de esta forma busco algo de antemano no sospechaba. No es necesario que conozcas

Hola, que tal? Sin saber nada mas de los datos, por lo que dices, mi aprioximacion seria usar la funcion split, e.g.: splittedData <- split(myData, "variablegrupo/condicion") Esto te crearia una lista con tantos objectos como condiciones tengas. Saludos On 6/27/24 10:15, Leticia G Leon wrote: > Muchas fracias por la rapida contastacion Javier. > > Si, ya me he dado

hi all ,? i have an problem in script R . But when I execute the script R I face this error . can you help me please ???error:----------------------------------------- Error in FUN(X[[i]], ...) :?? Theme element 'text' has NULL property: margin, debugIn addition: Warning messages:1: Removed 361 rows containing non-finite values (stat_smooth).?2: Removed 361 rows containing missing values

Hi, I have a data frame like this: > dput(df) structure(list(ID = 1:8, Type = c("gmx mdrun -ntmpi 8 -ntomp 1 -s benchPEP.tpr -nsteps 10000 -resethway", "gmx mdrun -ntmpi 8 -ntomp 1 -s benchPEP.tpr -nsteps 10000 -resethway", "gmx mdrun -ntmpi 8 -s benchPEP.tpr -nsteps 4000 -resetstep 3000", "gmx mdrun -ntmpi 8 -s benchPEP.tpr -nsteps 4000 -resetstep

?? Hola. Estoy intentando ordenar el gráfico tal que las columnas se apilen en el siguiente orden: debajo, los EPI; los SemiEPI en el medio y los NoEpi arriba de todo. Estos son mis datos: > tabla.barras Rangos Clase Asistentes 1 De 45d EPI 405 2 De 1a EPI 812 3 De 2a EPI 1639 4 De 3a EPI 2202 5 De 4a EPI 1994 6 De 5a EPI

Hello, I am trying to add a less than equal to symbol in a ggplot2 legend text. See sample code below. I have tried using the expression function and \u2264. I also tried adding labels to legend.text under theme. Neither of these 3 options work. Please help, Mahesh ++++++++++++++ Extra.column=ifelse(data[,covariate]>cutpoint,1,0) Grp1 <- "\u2264 1.5" Grp2 <-

Hi I am using ggplot to visualise y for a two-factorial group (Bio: 0 and 1) x = 6 years. I was able to adapt the colour of the lines (green and red) and the linetype (solid and dashed). Challenge: my code produces now two legends. One with the colors for the group and one with the linetype for the group. Does somebody have a hint how to adapt the code to produce one legend? Group 0 = red and

Thanks Ben, Here the reproducible example. It works without notch=TRUE, but provides an error with notch=TURE Error in `geom_boxplot()`: ! Problem while converting geom to grob. ? Error occurred in the 1st layer. Caused by error in `ans[ypos] <- rep(yes, length.out = len)[ypos]`: ! replacement has length zero Run `rlang::last_trace()` to see where the error occurred. Warning message: In

I don't see anything obviously wrong here. There may be something subtle, but we probably won't be able to help without a reproducible example ... On 2024-08-16 9:24 a.m., SIBYLLE ST?CKLI via R-help wrote: > Dear community > > > > I tried the following code using geom_boxplot() and notch=TRUE. Does anyone > know if the command ?notch=TRUE? is at the wrong place in

Hola, Mira la versión de ggplot2 que estás usando por tenerla actualizada a la última... A mi me funciona introduciendo algún cambio salvo la última línea cuando cambias el tema... #----------- Lines <- " id Rangos Clase Asistentes 1 45d EPI 405 2 1a EPI 812 3 2a EPI 1639 4 3a EPI 2202 5 4a EPI 1994 6 5a EPI

Dear community I tried the following code using geom_boxplot() and notch=TRUE. Does anyone know if the command ?notch=TRUE? is at the wrong place in my special code construct? Without notch=TRUE the code provides the planned ggplot. Kind regards Sibylle Code: MS1<- MS %>% filter(QI_A!="NA") %>% droplevels() MS1$Jahr<-as.factor(MS1$Jahr) MS1s <-

Hello everybody, I have experience coding with R, but am brand new to R Shiny. I am trying to produce an application that will allow users to upload their own dataset, select columns they want an ANOVA analysis run on, and generate graphs that will allow users to view their results. However, I am getting the following error: *"Argument is of length zero."* Being new to Shiny, I am

Dear community Using after_stat() I was able to visualise ggplot with standard deviations instead of a confidence interval as seen in the R help. p1<-ggplot(data = MS1, aes(x= Jahr, y= QI_A,color=Bio, linetype=Bio)) + geom_smooth(aes(fill=Bio, ymax=after_stat(y+se*sqrt(length(y))), ymin=after_stat(y-se*sqrt(y))) , method = "lm" , formula = y ~ x +

?s 16:27 de 18/07/2024, SIBYLLE ST?CKLI via R-help escreveu: > Hi > > I am using ggplot to visualise y for a two-factorial group (Bio: 0 and 1) x > = 6 years. I was able to adapt the colour of the lines (green and red) and > the linetype (solid and dashed). > Challenge: my code produces now two legends. One with the colors for the > group and one with the linetype for the

Hi! This is probably completely off base, but your ymin and y max setup lines are different. One uses sqrt(y), while the second uses sqrt(length(y)). Could that play a part, please? Thank you Erin Hodgess, PhD mailto: erinm.hodgess at gmail.com On Sun, Aug 11, 2024 at 10:10?AM SIBYLLE ST?CKLI via R-help < r-help at r-project.org> wrote: > Dear community > > > > Using

If I follow your question, you want redundant aesthetics. Ggplot normally notices correlated aesthetic mapping variables and merges the legends, so the most likely answer is that your data are not fully correlated in all rows. I have also seen this where data are drawn from different dataframes for different layers since it is hard to merge factors, but I don't see that here. You are using

?s 17:43 de 18/07/2024, Rui Barradas escreveu: > ?s 16:27 de 18/07/2024, SIBYLLE ST?CKLI via R-help escreveu: >> Hi >> >> I am using ggplot to visualise y for a two-factorial group (Bio: 0 and >> 1) x >> = 6 years. I was able to adapt the colour of the lines (green and red) >> and >> the linetype (solid and dashed). >> Challenge: my code

That's not really a reprex Sibylle.? I did try to use it to see if I could work out what you were trying to do and help but there is so much in there that I suspect is distraction from the notch issue and its error message. Please can you give us something stripped of all unecessary things and tell us what you want? Something like data that we can read as a tribble() or from a dput() of

Hi, I want to plot grouped bars to compare 95% confidence interval estimates from two models. Each bar represents a 95% confidence interval estimate of a coefficient from one of the two models. Each group represents confidence interval estimates of the same coefficient from the two models. I think such a bar plot will nicely present whether 95% confidence interval estimates of the same