similar to: Live data collection, analysis & update of slides ..

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 I've a machine, and users if granted permission work, but if I grant a group permissions, the user can't get access, even though both winbind and getent report that he is in that group. Examples: [CAD_BU2] ~ comment = CAD_BU ~ path = /mnt/H05/CAD_BU ~ valid users = @THG+mis_group ~ admin users = @THG+mis_group ~

Bert, Posit (formerly RStudio) has moved from RMarkdown to Quarto. They still support RMarkdown but major new features will be in Quarto. For new users a better choice would be Quarto. See https://quarto.org/docs/faq/rmarkdown.html Secondly, the OP stated he was using the VS-Code IDE, so there is no reason to point him to the Posit/RStudio IDE for this functionality which VS-Code supports very

I am struggling to get Quarto producing a list of figures from a Quarto book. Where may I find a working sample to get inspiration from? [[alternative HTML version deleted]]

A mi no me dio problemas. Intenta instalar nuevamente RCurl. > library(devtools) > install_github('likert','jbryer') Installing github repo likert/master from jbryer Downloading likert.zip from https://github.com/jbryer/likert/archive/master.zip Installing package from /tmp/RtmpJuHsLY/likert.zip arguments 'minimized' and 'invisible' are for Windows only

Hola, Puedes hacerlo sin devtools. Descargas el ZIP del repositorio, lo descomprimes, instalas el paquete que hay en CRAN para tener todas las dependencias instaladas y finalmente instalas el paquete en la versión de GitHub. tmp <- paste0(tempdir(), '/likert.zip') download.file('https://github.com/jbryer/likert/archive/master.zip', destfile=tmp,

I'm creating a stacked bar chart using the likert command in the HH package. My data are in a data frame, with two numeric variables and a categorical variable, I can't get likert to use the column containing the categorical variable as a my y axis label. Here is a quick example: library(HH) #my data are:

Hola a todos. Estoy intentando instalar el paquete likert utilizando devtools y obtengo el siguiente error library(devtools) install_github('likert','jbryer') Installing github repo(s) likert/master from jbryer Downloading likert.zip from https://github.com/jbryer/likert/archive/master.zip Error en function (type, msg, asError = TRUE) : <not set> Me pasa también con

R- Help Forum Working with the "likert" package and I can't figure out why my "bar" graphs are backwards (see attached). The percentages are place correctly but the bars are backwards. #Sample code # libraries library(likert) # create data band <- c("Band 3","Band 3","Band 3","Band 3","Band 3","Band

Gracias Oscar. Funciona perfectamente. Ya investigaré más adelante porque no funciona install_github Saludos y feliza navidad.. El 20/12/13 23:05, Oscar Perpiñan escribió: > tmp <- paste0(tempdir(), '/likert.zip') > download.file('https://github.com/jbryer/likert/archive/master.zip', > destfile=tmp, method='wget') > unzip(tmp,

has probado con: install_github('paquete",username='usuario')? 2013/12/20 Jose Luis Cañadas Reche <canadasreche en gmail.com>: > Hola a todos. > > Estoy intentando instalar el paquete likert utilizando devtools y obtengo el > siguiente error > > library(devtools) > install_github('likert','jbryer') > Installing github repo(s)

Hola, En GitHub estará siempre la última versión, pero también está el paquete en CRAN y puedes instalártelo como cualquier otro paquete ahí disponible... Saludos, Carlos Ortega www.qualityexcellence.es El 20 de diciembre de 2013, 14:54, José Luis Cañadas <canadasreche@gmail.com > escribió: > Si. Pero no funciona. En ordenador curro si funciona y tb tiene linux. > Seguiré

Si. Pero no funciona. En ordenador curro si funciona y tb tiene linux. Seguiré investigando has probado con: install_github('paquete",username='usuario')? 2013/12/20 Jose Luis Cañadas Reche <canadasreche@gmail.com>: > Hola a todos. > > Estoy intentando instalar el paquete likert utilizando devtools y obtengo el > siguiente error > > library(devtools) >

Hi everyone, I'm stuck on my dissertation which is due next week. I'm a business major student and my project is a comparative research on corporate social responsibility (CSR) between Chinese and German firms. According to my literature review, it's quite obvious that German firms have much better CSR initiatives and strategies than the Chinese ones and I wanted to test whether it was

Yo también tuve un problema parecido, en el momento que extrae el zip. Lo solucione como viene aquí: http://stackoverflow.com/questions/20408250/default-options-setting-for-unzip Saludos El 21 de diciembre de 2013, 9:00, Jose Luis Cañadas Reche < canadasreche@gmail.com> escribió: > Gracias Oscar. > > Funciona perfectamente. > Ya investigaré más adelante porque no funciona

Hi everybody, actually I wanted to search the list archive, before asking, but unfortunately I don't "get" it: $ gunzip 2018-May.txt.gz gunzip: 2018-May.txt.gz: not in gzip format It seems, that in every archive-file there is always one message in plaintext and then a big binary block. Any hint? Thanks a lot, -- kind regards, thg

I've been tweaking code for several days on and off in R, cut and pasting in from a text editor (I just leave them open all the time). I think I got something that was usable but then a powersurge tripped the fuses and unfortunately the machine I was working on doesn't have a UPS. Does R hold the command data in cache some place? I've purposefully not opened R since the crash so

I might be missing something really obvious, but is there an easy way to locate all non-unique values in a data frame? Example mydata <- numeric() mydata$id <- 0:8 mydata$unique <- c(1:5, 1:4) mydata$result <- c(1:3, 1:3, 1:3) > mydata $id [1] 0 1 2 3 4 5 6 7 8 $unique [1] 1 2 3 4 5 1 2 3 4 $result [1] 1 2 3 1 2 3 1 2 3 What I want to to be able to get some form of data output

Admit it, Rolf. Haven't you wondered if S, in a more private way, is sexier than R? OK, kidding aside, we have talked this to death. Just FYI, the conversation was stimulating for some of us and I have continued on my own and located functions I see as useful in the stringi and stringr packages to make my silly version ever less silly! LOL! -----Original Message----- From: Rolf Turner

Dear R members Could someone tell me how to simulate Likert-type data using the rnorm function. Let's say, 200*15 random numbers in a variable that goes from 1 to 4 in steps of 1 (i.e., 1, 2, 3, 4) belonging to a normal distribution? random.data <— matrix(rnorm(200 * 15), nrow = 200, ncol = 15) random.data The result cannot be reached. could one help me revise the syntax?

R- Help Forum Working with the "likert" package and find that my "bar" graphs are backwards (see attached) > summary(results) Item low neutral high mean sd 4 Q4 5 15 80 2.75 0.5501196 5 Q5 20 40 40 2.20 0.7677719 1 Q1 65 30 5 1.40 0.5982430 3 Q3 5 90 5 2.00 0.3244428 2 Q2 90 10 0 1.10 0.3077935