similar to: Customise Plot tick label on time series plot using date series

?s 05:11 de 13/01/2023, roslinazairimah zakaria escreveu: > Hi, > > I would like to customise my date series on the plot. I tried this: > > dt_ts <- ts(dt) > autoplot(dt_ts[,2]) + ylab("Charge counts") + xlab("Daily") > > but the label is not the date series. > > Tqvm for any help given. > > >> dput(dt) > structure(list(time

Hi R-Help, data at bottom I've been struggling with a problem where I need to order based on 1) the Frequency "Freq" and 2) keeping each group of 3 of the same type together "Var2" but I want across all groups it to go "high to low" based on the earn factor. Thank you! structure(list(Var1 = structure(c(1L, 3L, 2L, 1L, 2L, 3L, 1L, 3L, 2L, 3L, 1L, 2L, 3L, 1L,

You seem to have a typo at this expression (and some others like it) Namely, you write any(!dat2$norm_sd) >= 1 when you possibly meant to write !( any(dat2$norm_sd) >= 1 ) i.e. I think your ! seems to be in the wrong place. HTH, Eric On Thu, Dec 14, 2017 at 3:26 PM, DIGHE, NILESH [AG/2362] < nilesh.dighe at monsanto.com> wrote: > Hi, I need some help with running a

Hi, I'm trying to understand some details about an example maintened in [1]. According that link, I have total.data as a data set (am I right?). But I don't understand how is built that table. I saved the dataset in a file, with dput(), and had something like this: structure(list(df.all = structure(list(V1 = structure(c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L,

I'm creating a lattice barchart based off a pretty complicated data structure. The barchart comes out quite nice ( thanks to lattice ) but the problem is that the horizontal axis comes out all scrunched because the barchart doesn't know that the intervals of Var.1 are really "associated" with the conditioning variable Var.2. Therefore, all the intervals of Var.1 are put on

Hi, I need some help with running a recursive function. I like to run funlp2 recursively. When I try to run recursive function in another function named "calclp" I get this "Error: any(!dat2$norm_sd) >= 1 is not TRUE". I have never built a recursive function before so having trouble executing it in this case. I would appreciate any help or guidance to resolve this issue.

Eric: Thanks for taking time to look into my problem. Despite of making the change you suggested, I am still getting the same error. I am wondering if the logic I am using in the stopifnot and if functions is a problem. I like the recursive function to stop whenever the norm_sd column has zero values that are above or equal to 1. Below is the calclp function after the changes you suggested.

My own typo ... whoops ... !( any(dat2$norm_sd >= 1 )) On Thu, Dec 14, 2017 at 3:43 PM, Eric Berger <ericjberger at gmail.com> wrote: > You seem to have a typo at this expression (and some others like it) > > Namely, you write > > any(!dat2$norm_sd) >= 1 > > when you possibly meant to write > > !( any(dat2$norm_sd) >= 1 ) > > i.e. I think your !

The message is coming from your stopifnot() condition being met. On Thu, Dec 14, 2017 at 5:31 PM, DIGHE, NILESH [AG/2362] < nilesh.dighe at monsanto.com> wrote: > Hi, I accidently left out few lines of code from the calclp function. > Updated function is pasted below. > > I am still getting the same error ?Error: !(any(data1$norm_sd >= 1)) is > not TRUE? > > >

Hi, I accidently left out few lines of code from the calclp function. Updated function is pasted below. I am still getting the same error ?Error: !(any(data1$norm_sd >= 1)) is not TRUE? I would appreciate any help. Nilesh dput(calclp) function (dataset) { dat1 <- funlp1(dataset) recursive_funlp <- function(dataset = dat1, func = funlp2) { dat2 <- dataset %>%

Hi: I need some help with the legend. I got 14 samples(Muestreo) and I am trying to plot a smooth line for each sample. I am able to accomplish that but the problem is that the legend only displays every other sample. How can I force the legend to show all of my Muestreos? Thanks in advance. fish_ByMuestreo <- structure(list(data = structure(list(SampleDate = structure(c(3L, 3L, 3L, 3L,

Dear R users, A have a dataframe (matrix) with two collumns (plot, and diameter (d)). I want all diameters values for different combination of plots. For example I want all d values for all posible combination, 100C2 (all d values for plot 1 with all d values in the plot 2.......with all d values from plot 1 with all d values from plot 100, ...... with all d values from plot 99 with all d values

Your code contains the lines stopifnot(!(any(data1$norm_sd >= 1))) if (!(any(data1$norm_sd >= 1))) { df1 <- dat1 return(df1) } stop() "throws an error", causing the current function and all functions in the call stack to abort and return nothing. It does not mean to stop now and return a result. Does the function give

Eric: I will try and see if I can figure out the issue by debugging as you suggested. I don?t know why my code after stopifnot is not getting executed where I like the code to run the funlp2 function when the if statement is TRUE but when it is false, I like it to keep running until the stopifnot condition is met. When the stopifnot condition is met, I like to get the output from if statement

If you are trying to understand why the "stopifnot" condition is met you can replace it by something like: if ( any(dat2$norm_sd >= 1) ) browser() This will put you in a debugging session where you can examine your variables, e.g. > dat$norm_sd HTH, Eric On Thu, Dec 14, 2017 at 5:33 PM, Eric Berger <ericjberger at gmail.com> wrote: > The message is coming from

Hi all: I am trying to use the ddply function to estimate the mean of 'Total','Fry','Smolt' and 'Fry.Eq' columns without success. I have the dput of my dataset below. I wonder if someone can give me a hand with this function. # dput(winter) winter <-structure(list(IDDate = structure(c(37L, 48L, 59L, 62L, 63L, 64L, 65L, 66L, 67L, 38L, 39L, 40L, 41L, 42L, 43L,

Hi R help forum, I have a simple data frame of four columns - one of numbers (really a categorical variable), one of dates and one of data. I have over 500,000 data points to work with, spread over 40 files, each named after a different animal. These are contact data recorded by proximity loggers over two years between the animals of the file name and collars being worn by other animals. The

Hi all: I've done this before with factors but can't figure how to do it with a continuous variable. I am trying to reorder the sequence of my weeks along the X axis. I want to start with week 27 to 52 and then 1 to 26. I guess I could use levels along with seq() but doesn't seem to work for me. Thanks for your help winter <- structure(list(week = c(27L, 28L, 29L, 30L, 31L, 32L,

hello, i need to calculate ci's for each of 4 groups within a dataset, to be able to infere about differences in the variable "similarity". the problem is that data within groups is dependent, as assigned by the blocking-factor "site". my guess was to use a block bootstrap but samples within in these blocks / sites are not of same length. i was not able to find a method to

hello, i'd appreciate help with my glmer. i have a dependent which is an index (MH.index) ranging from 0-1. this index can also be considered as a propability. as i have a fixed factor (stage) and a nested random factor (site) i tried to model with glmer. i read that it's possible to use a quasibinomial distribution, for this kind of data, which i than actually did - but firstly (1)