Displaying 20 results from an estimated 8000 matches similar to: "Improvement in hist command documentation"
2009 Jul 26
2
problems hist() and density
Hello,
I have a problem with the hist() function and showing densities. The
densities sum to 50 and not to 1! I use R version 2.9.1 (2009-06-26) and
I load the seqinR library.
My data is the following vector:
[1] 0.1400000 0.2000000 0.2200000 0.2828283 0.1600000 0.1600000
0.3600000
[8] 0.1600000 0.2200000 0.2600000 0.2000000 0.3000000 0.2200000
0.2342342
[15] 0.1800000 0.2200000 0.1600000
2006 Aug 25
1
How to get back POSIXct format after calculating with hist() results
Hi,
I have a casting/formatting question on hist.POSIXt:
The histogram plot from POSIXct works perfect (with help of Prof. Ripley
-thanks!).
When processing the hist(plot=FALSE) output and then plotting the
results over the x-axis (bins) coming from hist(), I lose the date/time
labels, getting instead integers displayed.
Trying to cast the $breaks with as.POSIXct gives silly results with
2010 Dec 18
3
use of 'apply' for 'hist'
Hi all,
##########################################
dof=c(1,2,4,8,16,32)
Q5=matrix(rt(100,dof),100,6,T,dimnames=list(NULL,dof))
par(mfrow=c(2,6))
apply(Q5,2,hist)
myf=function(x){ qqnorm(x);qqline(x) }
apply(Q5,2,myf)
##########################################
These looks ok.
However, I would like to achieve more.
Apart from using a loop,
is there are fast way to 'add' the titles to be
2004 Aug 19
3
probability histogram question
Hello, all;
I get an unexpected result when trying to plot a probability histogram
with R1.9.1 on windows xp:
#with the following code:
> x <- runif(100,0,1)
> hist(x)
> hist(x, freq=F)
> h <- hist(x, freq=F)
> summary(h)
# Length Class Mode
#breaks 11 -none- numeric
#counts 10 -none- numeric
#intensities 10 -none- numeric
#density 10
2009 Jun 01
1
Bug in hist() when working with Dates ?
Hi,
It seems that hist() has a buggy behavior when breaking over "days".
The bug can be reproduced in a few steps:
> d=data.frame(date=c("2009-01-01", "2009-01-02", "2009-01-02"))
> d$date=as.Date(d$date)
> d$date
[1] "2009-01-01" "2009-01-02" "2009-01-02"
> h=hist(d$date, "days")
> h$count
[1] 3
2008 Sep 01
3
another histogram question
Hi there,
I hope this question is not as stupid as the one before ...
I tried to shorten my histogram (because the distribution is quite skewed and I
simply don't want to see the long tail but still use the histogram plot). How
can I do something like this? (The example does not work but I don't know why...)
data <- rnorm(100) # as example, of course this is not skewed...
h <-
2004 Nov 26
2
hist and truehist
Hello!
Up to now I have been using hist() to display the distributions.
Howevere, I noteiced strange numbers on y (vertical) axis, if I used
probability = T or freq = F option. I thought it is a bug and launched
the R-bug system and found some posts on that matter. Brian Ripley
responded to one, that one should look at truehist() for that. Ok I can
use truehist() if I want to see the ratios
2011 Dec 31
1
Histogram omitting/collapsing groups
I have two large datasets (156K and 2.06M records). Each row has the
hour that an event happened, represented by an integer from 0 to 23.
R's histogram is combining some data.
Here's the command I ran to get the histogram:
> histinfo <- hist(crashes$hour, right=FALSE)
Here's histinfo:
> histinfo
$breaks
?[1] ?0 ?1 ?2 ?3 ?4 ?5 ?6 ?7 ?8 ?9 10 11 12 13 14 15 16 17 18 19 20 21
2006 Apr 05
1
hist function: freq=FALSE for standardised histograms
Dear All,
I am a undergraduate using R for the first time. It seems like an excellent
program and one that I look forward to using a lot over the next few years,
but I have hit a very basic problem that I can't solve.
I want to produce a standardised histogram, i.e. one where the area under
the graph is equal to 1. I look at the manual for the histogram function and
find this:
freq:
2007 Aug 15
4
Possible to "import" histograms in R?
Hi,
I have a large amount of data that I would like to create a histogram of and
plot and do things with in R. It is pretty much impossible to read the data
into R, so I have written a program to bin the data and now have a list of
counts in each bin. Is it possible to somehow import this into R and use
hist(), so I can, for instance, plot the probability density? I have looked
at the help page
2020 Jan 18
1
How to get an object name from C?
(earlier I sent it as html by mistake).
Hi,
How can I get from C an object name used as a function argument? I
have sample code in C that gives me access to the name of the function
being called:
SEXP xname(SEXP x)
{
const char *fun_name = CHAR(PRINTNAME(CAR(x)));
x = CDR(x);
const char *arg_name = isNull(TAG(x)) ? "" : CHAR(PRINTNAME(TAG(x)));
2008 Nov 15
1
Rename objects based on list
Hi all,
I am trying to find a way to rename R objects with names pulled from a
vector of names. For example, I have a data frame, my.data.frame, and
a list of names, my.names. My.names is simply the column names of
my.data.frame.
I want save the histogram with the column name as the name of the object.
for (i in 1:ncol(my.data.frame) {
tmp<-hist(my.data.frame[,i])
2007 Dec 30
1
Histogram with different colors for different portions
Dear Rusers,
I would like to color different sections of a histogram different colors.
I have an example that was done by "brute force" given below. Has anyone
implemented something like this in general? If not, any suggestions/pointers
on how to write a general function to do so would be most appreciated.
Alan-
2012 Feb 06
2
histogram
With R and the hist function, is there a way to make a histogram in which
the y axis denotes propotion with respect to a separate sample dataset of
the same range instead of frequency?
[[alternative HTML version deleted]]
2005 Oct 18
2
hist of dates
Hi all
I wish to draw an histogram... with dates but the following append, i don't know where is the problem, help(hist.Date) works and i don't see any usefull information on what i'm doing wrong...
> hist.Date(dt_cycles)
Error: couldn't find function "hist.Date"
> hist.date(dt_cycles)
Error: couldn't find function "hist.date"
> cycles
[1] 7 1
2006 Dec 04
2
erroneous warning in hist (PR#9408)
Full_Name: Alex Deckmyn
Version: 2.4.0
OS: linux
Submission from: (NULL) (193.190.63.62)
specifying the "right" option in hist results in a warning when plot=F. The
option is taken into account correctly, but a warning is issued anyway. When
plot=T there is no warning.
> hist(c(1,1.5),breaks=0:4)$counts
[1] 1 1 0 0
> hist(c(1,1.5),breaks=0:4,right=T)$counts
[1] 1 1 0 0
>
2008 May 20
2
hist clarification
Can someone help me with a misunderstanding I'm having with hist? I
expected, from the example below, that the number of bins would always be 10
and the length of the counts array the same. According to the help section
'breaks' can be a integer indicating the number of bins. From the example
below, the number of bins (length of the counts array) varies. Am I wrong in
expecting the
2001 Oct 23
0
problems with postscript device
Hola!
I am producing postscript output from R (windows 98), both using firts
the windows devicd and then " copy to postscript", or using the
postscript device directly. The problem shows up equally both ways.
The function producing the plot is given below. The only difference I
can see with this function and other I have producing plots, is that
this uses split.screen(). I include the
2010 Mar 30
1
hist.default()$density
Dear developers,
the current implementation of hist.default() calculates 'density' (and
'intensities') as
dens <- counts/(n*h)
where h has been calculated before as
h <- diff(fuzzybreaks)
which results in 'fuzzy' values for the density, see e.g.
> tmp <- hist(1:10,breaks=c(-2.5,2.5,7.5,12.5),plot=FALSE)
> print(tmp$density,digits=15)
[1]
2003 Jan 08
4
weird breaks in hist (PR#2431)
Full_Name: Reinhold Koch
Version: 1.6.1
OS: redhat 8.0
Submission from: (NULL) (131.152.84.111)
I came across rather weird behavior of the breaks in hist:
hist(1:3)
gives the expected result, besides an unnecessary gap between 2nd and 3rd
column
hist(1:4)
always merges up the first two columns, also if I resort to
hist.default(1:4,breaks=1:4). hist.default(1:4, include.lowest=F) gives an