similar to: Note: no visible definition

On 4/9/16 10:54 AM, Dirk Eddelbuettel wrote: > On 9 April 2016 at 10:28, Mick Jordan wrote: > | Can someone explain a message of this form from an rscript execution: > | > | Note: no visible global function definition for 'foo' > | > | > | This happens right at the start of execution. 'foo' is only executed in > | a branch of an 'if' that is not

On 09/04/2016 2:55 PM, Mick Jordan wrote: > On 4/9/16 10:54 AM, Dirk Eddelbuettel wrote: >> On 9 April 2016 at 10:28, Mick Jordan wrote: >> | Can someone explain a message of this form from an rscript execution: >> | >> | Note: no visible global function definition for 'foo' >> | >> | >> | This happens right at the start of execution.

A couple of my colleagues are having problems building R-3.2.4 on Mac OS X El Capitan somehow related to libiconv. I personally don't have any problems on either of my Macs. I'm hoping thie make log might trigger something in the readers of this list: gcc -dynamiclib -Wl,-headerpad_max_install_names -undefined dynamic_lookup -single_module -multiply_defined suppress -L../../../../lib

On 5/3/16 11:29 AM, Thierry Onkelinx wrote: > Dear Mick, > > Note that both knitr and rmarkdown are listed under Suggests: both are > required to compile the vignette. Installing rmarkdown should solve > the problem. If not, please provide more information. OS, R version, > digest version, ... > > This is occurring in the context of an automated testing environment that

I need some help understanding a problem running the tests on the 'digest' package. Initially, I got the message that the 'knitr' package was needed to run vignettes: Running vignettes for package ?digest? Error in loadVignetteBuilder(vigns$pkgdir) : vignette builder 'knitr' not found So I installed the knitr package and all its dependents (?mime?, ?stringi?,

I was surprised by this: R --interactive -e 'interactive()' bash-3.2$ R -q -e 'interactive()' --interactive > interactive() [1] FALSE > as the command options document says that --interactive should force interactive=TRUE: " When *R* is run in a terminal (via |Rterm.exe| on Windows), it assumes that it is interactive if ?stdin? is connected to a (pseudo-)terminal

I have a data frame. And I'd like to subset according to rownames. subset(mydataframe, rownames(mydataframe) == myrow, select = mycols) it turned out that "myrow" cannot be a vector. But I have multiple rows to pick. Is there a way to get around this problem?? Thank you for your help!! Lei Jiang Department of Chemsitry University of Washington Box 351700 Seattle, WA 98195

>>>>> peter dalgaard <pdalgd at gmail.com> >>>>> on Sat, 12 Mar 2016 19:11:40 +0100 writes: > OK, .Internal is not necessary to reproduce oddity in this area. I also see things like (notice 1980) >> strptime(paste0(sample(1900:1999,80,replace=TRUE),"/01/01"), "%Y/%m/%d", tz="CET") ............... >

Here's a dummy example that I think illustrates the problem: toto <- function() { if (runif(1) < 0.5) function(a) a else function(a,b) a+b } > fcn <- toto() > fcn(1,2) [1] 3 > fcn <- toto() > fcn(1,2) [1] 3 > fcn <- toto() > fcn(1,2) Error in fcn(1, 2) : unused argument (2) How can you use the returned function, if you get different arguments?

Hello, when testing packages under R version 2.6.0 Under development (unstable), in order to discover future compatibility issues, I recently get numerous "possible problem notes" for different (own and other contributed) packages containing Tcl/Tk code, e.g.: * checking R code for possible problems ... NOTE sEdit : editVec : build: no visible global function definition

vapply <- function(X, FUN, FUN.VALUE, ..., USE.NAMES = TRUE) { FUN <- match.fun(FUN) if(!is.vector(X) || is.object(X)) X <- as.list(X) .Internal(vapply(X, FUN, FUN.VALUE, USE.NAMES)) } This is an implementor question. Basically, what happened to the '...' args in the call to the .Internal? cf lapply:, where the ... is passed. lapply <- function (X, FUN, ...)

Hello, first of all, thanks to LT for \pkg{codeutils}. I agree that it is indeed very useful to identify errors and also to encourage re-thinking past solutions. My problem: I want to compare different sets of related sub-functions which should be used alternatively by the same top-level function. Sets of related functions should be bound together (as lists) and the workspace should be as clean

Listers, I have a question regarding correlation matrices. It is fairly straight forward to build a correlation matrix of an entire data frame. I simply use the command cor(MyDataFrame). However, what I would like to do is construct a smaller correlation matrix using just three of the variable out of my data set. When I run this: cor(MyDataFrame$variable1,

I'm having trouble using split on a very large data-set with ~1400 levels of the factor to be split. Unfortunately, I can't reproduce it with the simple self-contained example below. As you can see, splitting the artificial dataframe of size ~13MB results in a split dataframe of ~ 144MB, with an increase memory allocation of ~10 fold for the split object. If split scales linearly, then my

Hi All, I'm looking for ways to compute aggregate statistics (with the aggregate function) but with an option for sorting and selecting a subset of the data frame. For example, I have would like to turn this : aggregate(myDataframe$TargetValue,list(SomeFactor = myDataframe$SomeFactor),mean) into something like aggregate(myDataframe$TargetValue,list(SomeFactor =

Hi guys, here is a list of names that I have: MyList: > myList<-list("A", "B","C","D") > myList [[1]] [1] "A" [[2]] [1] "B" [[3]] [1] "C" [[4]] [1] "D" I want to turn this list into a matrix of 1 row and 4 columns with those four components (A, B, C, D) so here is what I do: myDataFrame <-

I am new to R and have tried for a good while to figure out how to code this in R. The dataset below: FTIStandKey State County FTITract CoverType Ver_CT V_Origin V_SpGrp NAH6005-001 Texas Jasper NAH6005 PPLB-2000-U PPLB-2000-U P P NAH6005-002 Texas Jasper NAH6005 NHHX-1950-O NHHX-1950-I N H NAH6253-001 Texas Tyler NAH6253 PPLB-2001-U PPLB-2001-U P P

Dear people, I am including an example of a dataframe: mydataframe<-data.frame(X=c(1:4),total_bill=c(16.99,10.34,21.01,23.68),tip=c(1.01,1.66,3.50,3.31),sex=c("Male","Male","Male","Female")) When I use the sapply function getting the information about the factors works: sapply(mydataframe,function(x)is.factor(x)) X total_bill tip

I'm trying to bootstrap resample from a repeated measures dataset. I sample a vector of "ID"'s from my dataframe with replacement. Then I merge this back with my dataframe. I'm re-sampling subjects in the dataset rather than rows of the data. I thought I could use the left/right join features of the merge to select the records I want from the dataframe (mydataframe), like

hello R-Users, I have this simple but not for me question: I do: > res<-dbSendQuery(con, "SELECT * FROM tabellaProva") > myDataFrame<-fetch(res) > myDataMatrix<-as.matrix(myDataFrame[,-1]) > namerows(myDataMatrix)<-as.character(myDataFrame[,1]) and I have: io tu io "0" "1" tu "1" "0" my problem is that the