similar to: Problem with the svn jitter buffer

Since r12660, the speex_jitter_get with high latency doesn?t works, I have no sound. Before this release, the speex_jitter_get works in all conditions. speex_jitter_get return void, then I cannot know the reason of this problem. Regards Ouss -----Original Message----- From: Jean-Marc Valin [mailto:jean-marc.valin@usherbrooke.ca] Sent: dimanche 18 mars 2007 23:07 To: Ouss Cc:

I use the speex version of your jitter, and in speex_jitter_get, you always call the jitter_buffer_update_delay. -----Original Message----- From: Jean-Marc Valin [mailto:jean-marc.valin@usherbrooke.ca] Sent: dimanche 18 mars 2007 13:06 To: Ouss Cc: speex-dev@xiph.org Subject: Re: [Speex-dev] Problem with the svn jitter buffer > I think that the new Jitter Buffer have a problem. > >

Hi Ouss, Can you test again? I think I found and fixed the problem. Jean-Marc Ouss a ?crit : > Since r12660, the speex_jitter_get with high latency doesn?t works, I have > no sound. > Before this release, the speex_jitter_get works in all conditions. > speex_jitter_get return void, then I cannot know the reason of this problem. > > Regards > > Ouss > > >

Hi. After changing my code to construct a JitterBufferPacket and passing that to speex_jitter_put, my program works with the new jitter buffer using the wrapper functions (speex_jitter_* instead of the new jitter_buffer_*). However, a lot of warning: did you forget to call jitter_buffer_tick() by any chance? is displayed. Looking at speex_jitter_get, the logic seems to be as follows: if

Dear speex developers and users, I'm considering adopting the speex jitter buffer for use with a different codec in a voice conferencing system and would be very grateful if those more acquainted with it could help me with some questions. The speex_jitter_buffer.c wrapper seems to maintain (buffer?) one packet-frame ("current_packet") in addition to the packets already

Hi Jean, > Actually, Speex has Packet Loss Concealment (PLC) > builtin. If a packet > is missing, instead of repeating the previous one, > just try decoding by > passing NULL instead of the SpeexBits struct. > Thanks, I have made the above changes and the effect seems to be better now. > > I think jitter buffering is more correct way to > solve > > this problem

Thank you for a very good explanation which shed light on some of the questions that I had after reading the source code. Reading your text however, I wonder if I'm perhaps missing an important point on the proper use of the jitter buffer: ... > Now, clearly, if early_ratio is high and late_ratio is very > low, the buffer is buffering more than it needs to; it will > skip a frame

Hi, I am using the JitterBuffer. Since there is not so much documentation I think I dont use it in a correct way. All the packets are recieved (I control the sequence numbers) but the JitterBuffer often tells me he has no packet. I am using it in the following way: I am not sure if I use the ticks correctly but I think it can be set to 20(msec). It is set as a Member in my class and i

Dear all. Questions regarding VoIP implementation and the use of the Speex jitter buffer, if I may: Am I right in my understanding that the Speex jitter buffer implementation is used only on the receiving end of a network VoIP stream? 1) The sender would sample+encode+timestamp packets/frames of speex data and send via UDP to receiver. UDP packet would be constructed as: [TIMESTAMP][Speex

Thanks for your reply Jean-Marc! this was what I had before. But I decided to restructure it since the thread that plays the sound is a callback from the sound hardware, more or less an interrupt handler. For me it seems more reasonable to waste some memory for to save the decompressed Packet. While I write this I begin to think that it is possible I decompress Packets that are never used

('binary' encoding is not supported, stored as-is) I'm working on a voip project with Speex and the only major design obstacle left (that I'm aware of) is the jitter buffer. Before I attempt to write something of my own I'd like to try out the jitter buffer functions in Speex's unstable release. Can anyone give me a basic run down of how the experimental jitter buffer is

> Thank you for a very good explanation which shed light on some of the > questions that I had after reading the source code. > > Reading your text however, I wonder if I'm perhaps missing an important > point on the proper use of the jitter buffer: > > ... >> Now, clearly, if early_ratio is high and late_ratio is very >> low, the buffer is buffering more than

Daniel Schmidt a ?crit : > I found the cause of the problem. The function shift_timings can > produce overflows in the timing array if the jitter is huge or the > time units are very short. After changing the timing values' type from > spx_int16_t to spx_int32_t it seems to work. Hmm, I always assumed there wouldn't be any overflows. What parameter range are you using that

The frame size is 320 Ouss -----Original Message----- From: Jean-Marc Valin [mailto:jean-marc.valin@usherbrooke.ca] Sent: lundi 23 octobre 2006 18:26 To: Ouss Cc: speex-dev@xiph.org Subject: Re: [Speex-dev] Bug with the new preprocessor What frame size are you using? Jean-Marc Ouss a ?crit : > Hello, > > I have an (Access violation reading location) on line 115 in the fftwrap.c

Hello, The way you describe how the jitter buffer should be implemented makes me wonder: How does the jitter buffer works when there is no transmission? Let's say my "output" thread gets a speex frame from the jitter buffer every 20ms. What happen when there is no frame that arrived on the socket? No frames at all for a pretty long time (ie many seconds). This is my case because I

Hello, The denoiser was good with a car noise or a raod noise before the r11739. But for some situation, the actual version is perfect. That's why I think that if we can adjust the agressivity of the denoiser, we can respond to all of the situations. Maybe two parameters should be enough : high or low. For the AEC, I have to test with older versions because it's another person that

The jitter buffer would "freeze" under the following condition: - The sender and receiver are in sync. - The sender machine freezes for a few seconds while the receiver does not. - This causes all the packets sent by the sender to have a timestamp that is too low to be considered, meaning jitter_buffer_put ditches it before it checks if lost_count > 20 to reset. - The jitter buffer

> (PS, if you do use threads, protect speex_jitter_put/get with a mutex > (CRITICAL_SECTION I believe they're called in Win32Speak) -- calling put > and get at the exact same time from different threads leads to "features") I've never tested this, but I designed the jitter buffer to work from two threads even without using a mutex. This would work as long as there is

Hi, I'd like to report a bug in speexclient/speex_jitter_buffer.c. In the function speex_jitter_get(), after the line: packet.data = data; add the line packet.len = 2048; If this variable is uninitialized, then in jitter_buffer_get() (in jitter.c), the predicate "jitter->packets[i].len > packet->len" is undetermined. When this happens, the wrong amount of

Le mardi 02 mai 2006 ? 18:15 +0200, Thorvald Natvig a ?crit : > Hi. > > After changing my code to construct a JitterBufferPacket and passing that > to speex_jitter_put, my program works with the new jitter buffer using the > wrapper functions (speex_jitter_* instead of the new jitter_buffer_*). Oops, I forgot to make sure I keep the API stable for the old buffer. Any thoughts on