similar to: [LLVMdev] LLVM optmization

1. Re: LLVM optmization (Bill Wendling) Hi, The IR is not wrong. I said that the assembler generated by MSVC is quicker. We can see that the for loop, in the TESTE function, is done without jump's in the MSVC and with jumps in LLVM. I think thats the point. If we don't use threads, the result is the same. My test were done with one billion interactions in the for loop. The MSVC

The following C code : #include <stdio.h> #include <stdlib.h> int TESTE2( int parami , int paraml ,double paramd ) { int varx=0,vary; int nI =0; //varx= parami; if( parami > 0 ) { varx = parami; vary = varx + 1; } else { varx = vary + 1; vary = paraml; } varx = varx + parami + paraml; for( nI = 1 ; nI <= paraml; nI++) { varx =

Hi Manoel, > Hi, Duncan. > > Here an example : > #include <stdio.h> > #include <stdlib.h> > // > int TESTE ( int parami ,int paraml ) > { > int varx=0; > int nI =0; > > if( parami > 0 ) > { > varx = parami; > } > else > { > varx = 1; > } > > for( nI = 1 ; nI <= paraml;

hi all why does the following not work??? this was someone elses code and i couldnt explain why it doesn't work. m=matrix(c(0,0),2,1) v=matrix(c(1,0,0,1),2,2) Y=function(X1,X2,mu=m,V=v) { X=matrix(c(X1,X2),2,1) a=(1/((2*pi)*sqrt(det(V))))*exp((-0.5)*(t(X-mu)%*%solve(V)%*%(X-mu))) a[1] } x1=seq(-1,1) x2=x1 Z=outer(x1,x2,FUN="Y",mu=m,V=v) persp(x1,x2,Z) my code:

Dear all, Being a newbie to R, I've trawled through many old posts on this list looking for a solution to my problem, but unfortunately couldn't quite figure it out myself. I'd be very grateful if someone here on this list could perhaps help me out. I have a lattice plot with several panels and would like to add some text next to the y-axis on the right hand side of each row of

Hola a todos, Partiendo de: library(ggplot2); library(data.table) datos <- data.table(Date = seq.Date(as.Date("2017-01-01"), as.Date("2017-01-10"), by = "day"), V1 = rnorm(10), V2 = rnorm(10)) Quiero crear una función para pintar un gráfico cuyos argumentos sean

R users, I have df like this a <- data.frame( indx = 1:20, var1 = rep(c("I20", "I40", "A50", "B60"), each=5), var1_lab= rep(c("cat", "dog", "mouse", "horse"), each=5), var2 = rep(c("B20", "X40", "D50",

Buen día para todos los que ven este correo. En estos días estoy estudiando la potencia de una prueba en inferencia, pero no entiendo bien como correr un codigo que lo haga pertinentemente, el codigo que corro es el siguiente, la idea es que a medida que crece el tamaña muestral pues la potencia de la prueba aumente, pero no se como hacer para que, repita la prueba variando el tamaño de la

I am getting a difference in results when running some analysis using by and tapply compare to using a for loop. I've tried searching the web but had no luck with the keywords I used. I've attached a simple example below to illustrates my problem. I get a difference in the mean of yvar, diff and the p-value using tapply & by compared to a for loop. I cannot see what I am doing wrong.

I need to update a record in a table based on a event that occurs in the View. I believe the update action should occur in the controller. I think I need to call the controller action from the View and pass data that is stored in a Javascript variables as a parameter, but I am not sure how to do it. Can someone show me how I should be doing this? Below is a simplified version of the code I

Hi everyone, I'm working on a script trying to use foreach %dopar% but without success, so I manage to run the code with foreach %do% and looks like this: The code is part of a MCMC model for projects valuation, returning the most important results (VPN, TIR, EVA, etc.) of the simulation. foreach (simx = NsimT, .combine=cbind, .inorder=FALSE, .verbose=TRUE) %do% { MCPVMPA = MCVAMPA[simx]

Hi, If I try to do this: if(is.R()) data("eg1.DSE.data.diff", package="dse1") model <- est.VARX.ls(eg1.DSE.data.diff) (Page 14 - DSE Package Manual) I obtain a Segment Violation. I use R-1.3.0 and the last dse package version Maximino Ameneiro Gomez -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read

I want to populate the matrix prb through the function HWMProb <- function (a,j,dt) that encapsulates different functions (please see code below), using j= 0:2 for each j. It only populates prb if I specify each function independently in the global environment and then run the loop with the iF statement, as per below. for (j in 0:2) { if (j==0) { prb["0","1"] <-

Hi Eric I did not see any answer and frankly speaking I cannot provide you with canned help. AFAIK if a function is defined within another function (which is your case) it cannot be called directly so it is necessary to define it in global environment. > fff <- function(x) { + myf <- function(a) a+2 + myf(x)^2} > > fff(5) [1] 49 > myf(5) Error in myf(5) : could not find

Hi Well, I am not an expert in this field so I cannot comment your approach. I wanted only to point out that building matrix your way is like scratching your left ear with right hand, especially in R. What if you want increase size of your matrix? E.g. you use function ProbUP once for row "0" and than for rows different from jmax (if I correctly understand your code). Use of any

James Courtier-Dutton <james.dutton at gmail.com> writes: > I think this is a very simple question, and it must just be missing something. > > I am looking for find out how to assign a constant integer value to > the variable in llvm ir. > > The following returns 12, and %var2 = 12. > ; ModuleID = 't.c' > target datalayout = >

Hi Petr, Many thanks for your response. Basically I want to create a probability matrix to be used in a trinomial tree going forward. This is the reason why I thought to build the matrix around 0 would be much more efficient. I need to loop through because the probabilities will depend on my node and is not always the same per row (e.g. if N> jmax, jmax being defined in another function) I

On Mar 15, 2013 10:53 PM, "Óscar Fuentes" <ofv at wanadoo.es> wrote: > > James Courtier-Dutton <james.dutton at gmail.com> writes: > > > I think this is a very simple question, and it must just be missing something. > > > > I am looking for find out how to assign a constant integer value to > > the variable in llvm ir. > > > > The

You can't. You have to use the value 12 directly. On 16 March 2013 00:18, James Courtier-Dutton <james.dutton at gmail.com>wrote: > > On Mar 15, 2013 10:53 PM, "Óscar Fuentes" <ofv at wanadoo.es> wrote: > > > > James Courtier-Dutton <james.dutton at gmail.com> writes: > > > > > I think this is a very simple question, and it must

Hi all, I am working on rewriting my entire puppet environment and try to ''fix'' ''Dynamic lookup'' as it will be deprecated in some time, but even after reading quite some docs and on the forum, it''s not really clear to me. What I have read so far, is that each variable must be fully-qualified or parameterized in a class. As a quick