similar to: data.matrix output is not numeric

Displaying 20 results from an estimated 50000 matches similar to: "data.matrix output is not numeric"

2017 Sep 28
3
Boxplot, formula interface, and labels.
I have data I'd like to plot using the formula interface to boxplot. I call boxplot like so: with(mydata, boxplot(count ~ geno * tissue)) I get a boxplot with x axis labels like "wt.kidney". I would like to change the '.' to a newline. Where is this separator configured? Thanks, -Ed
2017 Nov 02
3
ggplot inside function doesn't plot
I don't really understand. I mean, I understand the solution is print(ggplot(...)). But why is that required in a function and not at the console? Shouldn't I be able to rely on what I do at the console working in a script? Is this inconsistent behavior by design? On Thu, Nov 2, 2017 at 11:54 AM, David Winsemius <dwinsemius at comcast.net> wrote: > >> On Nov 2, 2017,
2017 Sep 28
0
Boxplot, formula interface, and labels.
mybp <- boxplot(count ~ geno * tissue, data = mydata, plot = FALSE) mybp$names <- gsub("\\.", "\n", mybp$names) bxp(mybp) See ?boxplot for details. Best, Ista On Thu, Sep 28, 2017 at 12:40 PM, Ed Siefker <ebs15242 at gmail.com> wrote: > I have data I'd like to plot using the formula interface to boxplot. > I call boxplot like so: > > with(mydata,
2017 Sep 28
1
Boxplot, formula interface, and labels.
Just change the separator: data(Titanic) Titanic.df <- as.data.frame(Titanic) boxplot(Freq~Class*Sex, Titanic.df, cex.axis=.6, sep="\n") See attached .png. ---------------------------------------- David L Carlson Department of Anthropology Texas A&M University College Station, TX 77843-4352 -----Original Message----- From: R-help [mailto:r-help-bounces at r-project.org] On
2017 Oct 24
2
as.data.frame doesn't set col.names
Why doesn't this work? > samples$geno <- as.data.frame(sapply(yo, toupper), col.names="geno") > samples quant_samples age sapply(yo, toupper) E11.5 F20het BA40 E11.5 F20het BA40 E11.5 F20HET E11.5 F20het BA45 E11.5 F20het BA45 E11.5 F20HET
2018 May 18
3
Exporting to text files
I have dose response data analyzed with the package 'drc'. 'summary(mymodel)' prints my kinetic parameters. I want that text in an ASCII text file. I want to get exactly what I would get if I copied and pasted from the terminal window. I've read the documentation on data export to text files here:
2012 Mar 28
2
lapply and paste
I have a list of suffixes I want to turn into file names with extensions. suff<- c("C1", "C2", "C3") paste("filename_", suff[[1]], ".ext", sep="") [1] "filename_C1.ext" How do I use lapply() on that call to paste()? What's the right way to do this: filenames <- lapply(suff, paste, ...) ? Can I have lapply()
2012 Feb 29
3
Broken R
Hi, I am running Debian Sid. I am having trouble with the R packages. Executing 'help()' or 'demo()' launches 'most' with no text. 'help.start()' works properly. When I try to install a package, I get the following problem: ********************************************************************* > install.packages("ctv") Installing package(s) into
2017 Oct 24
0
as.data.frame doesn't set col.names
Wait. Now I'm really confused. > > head(samples) quant_samples age sapply(yo, toupper) E11.5 F20het BA40 E11.5 F20het BA40 E11.5 F20HET E11.5 F20het BA45 E11.5 F20het BA45 E11.5 F20HET E11.5 F20het BB84 E11.5 F20het BB84 E11.5 F20HET E11.5 F9.20DKO KTr3 E11.5 F9.20DKO KTr3 E11.5 F9.20DKO E11.5
2012 Mar 24
3
argument names inside a function?
Is there a way I can get the names of the arguments passed to a function from within a function?
2017 Oct 23
2
A list of data frames and a list of colnames.
I have a list of file names, and a list of data frames contained in those files. mynames <- list.files() mydata <- lapply(mynames, read.delim) Every file contains two columns. > colnames(mydata[[1]]) [1] "Name" "NumReads" > colnames(mydata[[2]]) [1] "Name" "NumReads" I can set the colnames easily enough with a for loop. for (i in
2016 Apr 18
2
lists and rownames
I'm doing some string manipulation on a vector of file names, and noticed something curious. When I strsplit the vector, I get a list of character vectors. The list is numbered, as lists are. When I cast that list as a data frame with 'as.data.frame()', the resulting columns have names derived from the original filenames. Example code is below. My question is, where are these names
2017 Nov 02
3
ggplot inside function doesn't plot
I have a function: myplot <- function (X) { d <- plotCounts(dds2, gene=X, intgroup="condition", returnData=TRUE) png(paste("img/", X, ".png", sep="")) ggplot(d, aes(x=condition, y=count, color=condition)) + geom_point(position=position_jitter(w=0.1,h=0)) + scale_y_log10(breaks=c(25,100,400)) + ggtitle(X) +
2018 May 18
0
Exporting to text files
?sink On May 18, 2018 9:47:25 AM PDT, Ed Siefker <ebs15242 at gmail.com> wrote: >I have dose response data analyzed with the package 'drc'. >'summary(mymodel)' prints my kinetic parameters. I want >that text in an ASCII text file. I want to get exactly what I >would get if I copied and pasted from the terminal window. > >I've read the documentation on
2017 Nov 02
0
ggplot inside function doesn't plot
> On Nov 2, 2017, at 9:27 AM, Ed Siefker <ebs15242 at gmail.com> wrote: > > I have a function: > > myplot <- function (X) { > d <- plotCounts(dds2, gene=X, intgroup="condition", returnData=TRUE) > png(paste("img/", X, ".png", sep="")) > ggplot(d, aes(x=condition, y=count, color=condition)) + >
2012 Jun 04
2
Why do I have a column called row.names?
I'm trying to read in a tab separated table with read.delim(). I don't particularly care what the row names are. My data file looks like this: start stop Symbol Insert sequence Clone End Pair FISH 203048 67173930 ABC8-43024000D23 TI:993812543 TI:993834585 255176 87869359 ABC8-43034700N15 TI:995224581 TI:995237913 1022033 1060472
2012 Mar 15
1
subsetting by cell value with a list
I would like to subset by dataframe by matching all rows that have any value from a list of values. I can get it to work if I have exactly one value, I'm not sure how to do it with a list of values though. This works and gives me exactly one line: my.df[ which( mydf$IDX==17)), ] I would like to do something like this: my.df[ which( mydf$IDX==c(17, 42), ] Obviously that won't work, but
2018 May 31
2
How to alpha entire plot?
I have two chromatograms I want plotted on the same axes. I would like the plots to be transparent, so the first chart is not obscured. I have tried adjustcolor(..., alpha.f=0.3), the problem is that my chromatogram is so dense with datapoints that they overlap and the entire graph just ends up a solid color. The second histogram still obscures the first. Consider this example: col1 <-
2017 Sep 22
2
update numeric values of list with new values...
Suppose I have the following: test <- list(a=1,b=2,c=3) I also have a vector (or list, or something else...) with new numbers new <- c(4,5,6) What I'm trying to figure out is how to take the list, and update the numbers from {1,2,3} to {4,5,6} So, in the end,I want the 'update' test list to look like (a=4,a=5,a=6) I tried a bunch of obvious things I know about
2007 May 16
3
more woes trying to convert a data.frame to a numerical matrix
I have the following csv file: name,x,y,z category,delta,gamma,epsilon a,1,2,3 b,4,5,6 c,7,8,9 I'd like to create a numeric matrix of just the numbers in this csv dataset. I've tried the following program: sample.data <- read.csv("sample.csv") numerical.data <- as.matrix(sample.data[-1,-1]) However, print(numerical.data) returns what appears to be a matrix of