similar to: Default value of the option initial in the ses function in the forecast package.

The first one, i.e. "optimal"; check help for match.arg() for the idiom. -pd > On 2 Oct 2017, at 11:48 , Ashim Kapoor <ashimkapoor at gmail.com> wrote: > > Dear All, > > I am trying to use the function ses from the forecast package. > > From its help I have : > > Usage: > > ses(y, h = 10, level = c(80, 95), fan = FALSE, initial =

I suggest, you read: Forecasting: principles and practice from Hyndman-Athana?sopou?los https://www.otexts.org/fpp

I've some demand data, for which I wish to judge what will be the direction in the forecast period (Up/Down). What will be a best ML method to do this? Currently I'm using the data given below - 9/4/2016 241 9/11/2016 233 9/18/2016 226 9/25/2016 282 10/2/2016 291 10/9/2016 282 10/16/2016 308 10/23/2016 291 10/30/2016 268 11/6/2016 262 11/13/2016 273 11/20/2016 262 11/27/2016 309 12/4/2016

Dear All, I want a transformation which will make the spread of the response at all combinations of 2 factors the same. See for example : boxplot(breaks ~ tension * wool, warpbreaks) The closest I can do is : spreadLevelPlot(breaks ~tension , warpbreaks) spreadLevelPlot(breaks ~ wool , warpbreaks) I want to do : spreadLevelPlot(breaks ~tension * wool, warpbreaks) But I get : >

Dear Olivier, Many thanks for your reply. Very cool. You know what I thought ? I thought you had modified the A4 sheet size to compute the paperheight and paperwidth ? I wonder if that's another way of proceeding. Best, Ashim On Sat, Nov 18, 2023 at 12:51?PM Olivier Crouzet <olivier.crouzet at univ-nantes.fr> wrote: > > Dear Ashim, > > these are documented in the LaTeX

Dear All, Here is a reprex: > x<- 1:100 > x[-which(x>100)] integer(0) In words, I am finding out which indices correspond to values in x which are greater than 100 ( there are no such items ) . Then I remove those indices. I should get back the x that I started with since there are no items in x which are bigger than 100 . Instead, it is returning an empty vector. Why is this ?

Dear All, we need to do : library(car) for the spreadLevelPlot function I forgot to say that. Apologies, Ashim On Sun, Jan 7, 2018 at 10:37 AM, Ashim Kapoor <ashimkapoor at gmail.com> wrote: > Dear All, > > I want a transformation which will make the spread of the response at all > combinations > of 2 factors the same. > > See for example : > >

Dear R Developers, For package seriation I use Fortran code. I recently got a request to add #if defined(__ICC) || defined(__INTEL_COMPILER) USE IFPORT #endif to the code since the Intel Fortran compiler otherwise has problems with rand(). However, to enable the FPP preprocessor I have to either add a compiler flag (-cpp for gFortran) which is possibly not portable or change the

And indeed again (I did not understand your previous question exactly at first), the 'hard-coded' definition of a landscape a4 sheet would therefore be: paperwidth=29.7cm, paperheight=21cm Olivier. On Sat, 18 Nov 2023 13:20:49 +0530 Ashim Kapoor <ashimkapoor at gmail.com> wrote: > Dear Olivier, > > Many thanks for your reply. > > Very cool. > > You know

Dear R-helpers, Please have a look at the following. f1 is the same as f2 except that it has some values replaced by NA. But it's corresponding file is slightly bigger than the file containing f2. Could someone please tell me if this is an anomaly ? > load("file1") > ls() [1] "f1" > load("file2") > ls() [1] "f1" "f2" > >

Dear all, I have posted a query which has received a response but that is not working on my computer. Here is the query: https://stackoverflow.com/questions/77387434/pdf-from-rmarkdown-landscape-and-aspectratio-169 Can someone please help me ? Best Regards, Ashim

Dear Olivier, Many thanks for your reply. This works well for me. How did you come up with the pagewidth / pageheight numbers? I do understand that their ratio = 16:9, but how did you choose these numbers? Best Regards, Ashim On Fri, Nov 17, 2023 at 9:25?PM Olivier Crouzet <olivier.crouzet at univ-nantes.fr> wrote: > > Dear Ashim, > > I don't think the aspectratio is

Dear Ashim, these are documented in the LaTeX 'geometry' package (see for example on CTAN: https://ctan.org/pkg/geometry). As I added in my response on Stackoverflow, several parts in the RMarkdown header actually concern information that are processed by LaTeX to actually generate the PDF, among which the 'geometry' line. For someone who is used to working with LaTeX, it is

Dear R-helpers, It seems to me that a character zoo cannot be coerced to a numeric zoo. Below is a minimal example. Can someone tell me what I have done wrong? > z<-zoo(1:4,order.by=1:4) > coredata(z)<-as.character(coredata(z)) > str(z) ‘zoo’ series from 1 to 4 Data: chr [1:4] "1" "2" "3" "4" Index: int [1:4] 1 2 3 4 >

Dear All, My query is: Do we always need to use perl = TRUE option when doing ignore.case=TRUE? A small example : my_text = "RECOVERY OFFICER-II\nDEBTS RECOVERY TRIBUNAL-III\n RC No. 162/2015\nSBI VS RAMESH GUPTA.\n Dated: 01.03.2016 Item no.01\n Present: Ms. Sonakshi, the proxy counsel for Ms. Usha Singh, the counsel for ARCIL.\n None for the CDs.\n

Buenos días, Os cuento: Cargo la librería "Forecast" y ejecuto su función Arima(...) sobre una serie temporal: mimodelo <- Arima(miST$miserie, ...); Ahora si ejecuto las siguientes sentencias, voy obteniendo los resultados contenidos en "mimodelo", pero algunos de ellos no sé lo que son: mimodelo[[1]] obtengo los coeficientes del modelo ARIMA mimodelo[[2]] obtengo el

Here is a small reproducible example: data <- structure(list(V1 = structure(1:3, .Label = c("Name1", "Name2", "Name3"), class = "factor"), V2 = structure(c(1L, 3L, 2L), .Label = c("nam1", "name-1", "name_12"), class = "factor"), V3 = structure(1:3, .Label = c("nam2", "nam_34",

Look at which(x>100) This is a zero-length vector. The negative of nothing is nothing, not a list of all possible index values. Do you want x[ !( x > 100 ) ] ? On April 18, 2018 6:13:30 AM CDT, Ashim Kapoor <ashimkapoor at gmail.com> wrote: >Dear All, > >Here is a reprex: > >> x<- 1:100 >> x[-which(x>100)] >integer(0) > >In words, I am

Dear Ashim, I don't think the aspectratio is appropriate in this context because it would imply that the beamer (LaTeX) class is used but you're actually using the article (LaTeX) class. You may use specifications of the geometry package rather than specifying options to the class: e.g. replace your current header: --- title: "Testing landscape and aspect ratio" output:

Dear All, I had done an automatic upgrade of my Debian 10 system which had also upgraded R. I reinstalled the stargazer package and the error went away. Query : Do I need to reinstall all packages with each upgrade of R ? Best, Ashim On Thu, Jun 8, 2023 at 11:11?AM Ashim Kapoor <ashimkapoor at gmail.com> wrote: > > Dear All, > > Here is my reproducible example: > >