Displaying 20 results from an estimated 50000 matches similar to: "update R version in windows"
2017 Nov 10
3
update R version in windows
However, trying this on Linux Mint gave
package ?installr? is not available (for R version 3.4.2)
Has the package not been updated yet?
JN
Try the installr package. It was designed for this purpose.
On Fri, Nov 10, 2017 at 11:49 AM, Bond, Stephen <Stephen.Bond at cibc.com> wrote:
> Is there a utility which will allow me to upgrade my R version and update all packages from the old
2017 Nov 10
0
update R version in windows
This issue does not exist on Linux. My Ubuntu updates both R and all packages.
Stephen B
-----Original Message-----
From: J C Nash [mailto:profjcnash at gmail.com]
Sent: Friday, November 10, 2017 1:19 PM
To: r-help; RICHARD M. HEIBERGER; Bond, Stephen
Subject: Re: [R] update R version in windows
However, trying this on Linux Mint gave
package ?installr? is not available (for R version
2017 Dec 20
2
offset with a factor
Knowledgeable useRs,
Please, advise how to use offset with a factor. I estimate monthly effects from a much bigger data set as monthly effects seem to be stable, and other variables are estimated from a small, but recent data set as there is variation in those non-seasonal coefficients.
How can I use the seasonality estimates from the big data set as an offset provided to the small data set. I
2011 Nov 03
2
Create design matrix
Greetings useRs,
What is the easiest way to create a design matrix of several factor variables? Function gendata in Design seems to do that for a fitted model, but how to do that only on several factor vectors??
The result should be a df with one row for each distinct combination of levels of factors eg for (M,F) (Y,O)
We get
M Y
M O
F Y
F O
In reality I will have more than 1000 rows so doing
2014 Oct 07
3
lattice add a fit
What is the way to add an arbitrary fit from a model to a lattice conditioning plot ?
For example
xyplot(v1 ~v2 | v3,data=mydata,
panel=function(...){
panel.xyplot(...)
panel.loess(...,col.line="red")
}
)
Will add a loess smoother. Instead, I want to put a fit from lm (but not a simple straight line) and the fit has to be done for each panel
2018 Mar 22
2
how to add a child to a child in XML
Big thanks. newXMLNode works great. Wonder why it is not included in the documentation.
There is newXMLDoc and newXMLNamespace, but no mention of newXMLNode.
Stephen
From: Ben Tupper [mailto:btupper at bigelow.org]
Sent: Wednesday, March 21, 2018 6:18 PM
To: Bond, Stephen
Cc: r-help
Subject: Re: [R] how to add a child to a child in XML
Hi,
XML doesn't use the `$` to access child nodes.
2017 Jun 24
2
Comparing pooled proportions(complication and reoperation rates) of different treatment modalities
Note though that this has been put on hold on stats.stackexchange.com as
off-topic.
On 23/06/2017 19:33, Bert Gunter wrote:
> Probably the wrong list. R-help is concerned with R programming, not
> statistics methodology questions, although the intersection can be
> nonempty.
>
> I suggest you post on stats.stackexchange.com instead, which *is*
> concerned with statistics
2013 Sep 09
1
windowing
Is there a package or a command that does window aggregation like
select
sum(col1) over
(partition by col2, col3 order by col4
rows between unbounded preceding and current row) as sum1
from table1 ;
the above is Netezza syntax, but Postgre has same capability.
Stephen B
[[alternative HTML version deleted]]
2018 Mar 22
0
how to add a child to a child in XML
Hi,
It's a reasonable question. The answer is that it actually is included, but there are many instances across packages where multiple functions are documented on a single help page. The following brings up such a page... (for XML_3.98-1.9)
> library(XML)
> ?newXMLNode
You can see the same on line...
https://www.rdocumentation.org/packages/XML/versions/3.98-1.9/topics/newXMLDoc
2018 Mar 22
1
how to add a child to a child in XML
Just to clarify and hopefully catch the attention of the maintainer:
The newXMLNode function is not mentioned in:
https://cran.r-project.org/web/packages/XML/XML.pdf
which supposedly describes all functions in the package.
Stephen
From: Ben Tupper [mailto:btupper at bigelow.org]
Sent: Thursday, March 22, 2018 10:40 AM
To: Bond, Stephen
Cc: r-help
Subject: Re: [R] how to add a child to a
2017 Jun 26
0
Comparing pooled proportions(complication and reoperation rates) of different treatment modalities
What is the best way to change my R code to be able to compare the pooled proportions(complication and reoperation rates) with the Chi square method?
Verstuurd vanaf mijn iPhone
> Op 24 jun. 2017 om 14:18 heeft Michael Dewey <lists at dewey.myzen.co.uk> het volgende geschreven:
>
> Note though that this has been put on hold on stats.stackexchange.com as off-topic.
>
>>
2018 Mar 21
2
how to add a child to a child in XML
I am trying to add a child to a child using XML package in R. the following fails
library(XML)
node1 <- c("val1","val2","val3")
names(node1) <- c("att1","att2","att3")
root <- xmlNode("root", attrs=node1)
node2 <- LETTERS[1:3]
names(node2) <- paste("name",1:3,sep="")
root <-
2009 Oct 09
2
weigths in nls (PR#13991)
Potential bug:
I mistyped weights in the call ('weigths') and it did not produce any error=
message. The coefs were exactly the same like without weights, so I was su=
spicious and when weights(nls1) gave NULL, I saw my typo.
Usually the function will say "Unused arguments", which shows you the error=
, but not nls.
Regards
Stephen
[[alternative HTML version deleted]]
2018 Mar 21
0
how to add a child to a child in XML
Hi,
XML doesn't use the `$` to access child nodes. Instead use either `[name]` to get a list of children of that name or `[[name]]` to get the just the first child of that name encountered in the genealogy. Thus for your example...
> root$child1
NULL
> root[['child1']]
<child1 name1="A" name2="B" name3="C"/>
On the other hand, you might
2012 Mar 30
3
ff usage for glm
Greetings useRs,
Can anyone provide an example how to use ff to feed a very large data frame to glm?
The data.frame cannot be loaded in R using conventional read.csv as it is too big.
glm(...,data=ff.file) ??
Thank you
Stephen B
2018 Mar 05
2
Σχετ: Problem with Rd2.tex tduring compilation
Hi and thanks for the prompt reply. I cannot say I understood or know what to do.
Can you please tell me which is this mailing list?
???? 2:15 ?.?. ???????, 5 ??????? 2018, ?/? Michael Dewey <lists at dewey.myzen.co.uk> ??????:
The error is that one of your documentation files is failing. Try
compiling each one separately with
R CMD Rd2pdf yourfilenamehere.Rd
and see what
2018 Mar 22
3
How do I include a factor in a groupedData object? Meaning and use of inner and outer parameters
Windows 10 64-bit, R-Studio, R version 3.4.3
Several questions relating to groupedData:
(1) I am trying to create a groupedData object that can be used to run an analysis that I have been able to urn using lmer. When I include the interaction terms in the groupedData opbject I get an error message stating that + is not meaningful for factors. How do I include factors in my model? See code and
2018 Mar 05
0
Σχετ: Problem with Rd2.tex tduring compilation
https://stat.ethz.ch/mailman/listinfo/r-package-devel
On 05/03/2018 13:46, michael tsagris wrote:
> Hi and thanks for the prompt reply. I cannot say I understood or know
> what to do.
> Can you please tell me which is this mailing list?
>
>
>
> ???? 2:15 ?.?. ???????, 5 ??????? 2018, ?/? Michael Dewey
> <lists at dewey.myzen.co.uk> ??????:
>
>
> The
2010 Oct 12
5
aggregate with cumsum
Hello everybody,
Data is
myd <- data.frame(id1=rep(c("a","b","c"),each=3),id2=rep(1:3,3),val=rnorm(9))
I want to get a cumulative sum over each of id1. trying aggregate does not work
myd$pcum <- aggregate(myd[,c("val")],list(orig=myd$id1),cumsum)
Please suggest a solution. In real the dataframe is huge so looping with for and subsetting is not a
2017 Aug 10
1
Plotting log transformed predicted values from lme
Thank you Michael,
Curves for each level of the factor sounds very interesting,
Do you have a suggestion how to plot them?
Thank you!
Alina
*Alina Vodonos Zilberg*
On Thu, Aug 10, 2017 at 7:39 AM, Michael Dewey <lists at dewey.myzen.co.uk>
wrote:
> Dear Alina
>
> If I understand you correctly you cannot just have a single predicted
> curve but one for each level of your