similar to: Help: ifelse selection for x,y coordinates

Hi Jim, Thank you very much for the answer?! The result is really better with this?? Here is the code?: > kk<- function(x.Koordinate, y.Koordinate, data=data) + { + coordx<-data$x.Koordinate[data$G==24] + coordy<-data$y.Koordinate[data$G==24] + x <- ifelse(data$x.Koordinate>coordx-51 & data$G>15,data$x.Koordinate," ") +

Hi Celine, what about removing the unwanted after you made the x and y x<-x[x>0] # or x<-x[x>0&&y>0], ditto for y, x[x!=""] in your ifelse (... ,"") case if x and y will not have the same length afterwards you need to make that list thingy. cheers Peter On 23. Jun 2017, at 07:30, C?line L?scher <c-luescher at hispeed.ch<mailto:c-luescher at

Hi Celine, Perhaps if you modify your return value like this: xy<-as.data.frame(list(x,y)) names(xy)<-c("x","y") return(xy) Jim On Thu, Jun 22, 2017 at 6:48 PM, C?line L?scher <c-luescher at hispeed.ch> wrote: > Hi everyone, > My database has 3 columns : the x coordinates, the y coordinates and the value of G for every individual (20 in total). I would like

Yes of course, I can share this short view of the datas. Here is the head() of data100, containing all the trees with a final value higher than 100?: CV11 CV12 CV13 CV14 CV15 CV21 CV22 CV23 CV24 CV25 CV26 CV31 CV32 CV33 CV41 CV42 CV43 CV44 CV51 CV52 IN11 IN12 IN13 1291 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1083 0 4 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 3919 0 0 0 0 0 0 0 0 0 0 0 2 0

Do you have a simplified example with a code? It is not clear to me what do you mean by tree but if you refer to tree data structure, maybe you could change the data structure to tree (https://cran.r-project.org/web/packages/data.tree/vignettes/data.tree.html) and try to write comparison of two tree objects. It might be easier that data.frame alone. On 12 September 2017 at 12:27, C?line L?scher

Hi C?line, Looks like you are looking for a statistical test between two sets of distributions, such as KS test, for example, generate histogram for each row in an identical way and run KS test. But if you are after simple difference you may use compare package ( https://cran.r-project.org/web/packages/compare/index.html). Best, -m PS: Data is already plural :) datas does not exist. On 12

Dear all, I am stuck at applying loop function for creating separated plots. I have coding like below: dataset.table <- table(data.frame(var1=c(1,2,3,1,2,3,1),colour=c("a","b","c","c","a","b","b") )) kk = function(f) { ls=as.character(f) pie(dataset.table[ls,],main=ls)

Thompson's Manual to Accompany Agresti's book refers to a package named "repeated". It's not on CRAN from what I can see. I have seen rpm's for it. Where is the best place to download this package? Rick B.

I have a data set like this in one .txt file (cols separated by !): APE!KKU!684! APE!VAL!! APE!UASU!! APE!PLA!1! APE!E!10! APE!TPVA!17122009! APE!STAP!1! GG!KK!KK! APE!KKU!684! APE!VAL!! APE!UASU!! APE!PLA!1! APE!E!10! APE!TPVA!17122009! APE!STAP!1! GG!KK!KK! APE!KKU!684! APE!VAL!! APE!UASU!! APE!PLA!1! APE!E!10! APE!TPVA!17122009! APE!STAP!1! GG!KK!KK! it contains over 14 000 000 records. Now

This message is in MIME format. The first part should be readable text, while the remaining parts are likely unreadable without MIME-aware tools. Send mail to mime@docserver.cac.washington.edu for more info. ---559023410-1141662977-1014960253=:3119 Content-Type: TEXT/PLAIN; CHARSET=iso-8859-1 Content-Transfer-Encoding: QUOTED-PRINTABLE Content-ID:

Colleagues, one of my servers had to be rebooted uncleanly and then I have backgrounded fsck locked for more than an our in snaplk: 742 root 1 -4 4 1320K 688K snaplk 0:02 0.00% fsck_ufs File system in question is 200G gmirror on SATA. Usually making a snapshot (e.g., for making dumps) consumes 3-4 minutes for that fs, so it seems to me that filesystem is in a deadlock. Any

This came up on r-help but indicates a bug. dnbinom(x,n,p) calls dbinom_raw(n-1,...) which returns 0 for n<1. -thomas ---------- Forwarded message ---------- Date: Thu, 08 Feb 2001 17:10:23 +0000 From: Yudi Pawitan <yudi@stat.ucc.ie> To: Mark Myatt <mark@myatt.demon.co.uk> Cc: R-Help <r-help@stat.math.ethz.ch> Subject: Re: [R] Goodness of fit to Poisson / NegBinomial

Hi everyone, I need your help to solve a problem with occurrence and two dataframes. I have an excel table of 15200 lines. Each line correspond to a tree analyzed for its structures. I have all the structures in columns (48 structures). The occurrence of these structures has been counted on every tree. For example, the tree 12607 has 3 structures CV11, 1 structure IN12 and none (0) of the rest of

Hello, how to merge a data.frame and a matrix by one column in the data.frame and rownames of the matrix? df <- data.frame(col1=c("kk","yy","kk"),col2=c(6,4,3)) > df   col1 col2 1   kk    6 2   yy    4 3   kk    3 m<-matrix(c(3,8,56,9), nrow=2, dimnames = list(c("aa","kk"),c("col1","col2"))) > m    col1 col2 aa   

Dear all, I am dealing with the following (apparently simple problem): For some reasons I am interested in passing variables from a dataframe to a specific environment, and in fitting a standard glm: dati<-data.frame(y=rnorm(10),x1=runif(10),x2=runif(10)) KK<-new.env() for(i in 1:ncol(dati)) assign(names(dati[i]),dati[[i]],envir=KK) #Now the following two lines work correctly:

Jun-qi Deng <dengjunqi06323011 at gmail.com> writes: >> Is it? In my experience, it isn't. Please show the relevant command >> generated by your makefile and the associated error message(s). >> > >> RTTI is an on/off option that changes per LLVM library, so setting >> -fno-rtti for using LLVM makes no sense. VMCore and Support have -frtti >> while

Dear folks? Is there a function to correctly find (and count) the NAs in a factor when exclude=NULL, regardless of whether their origin is in the original data or by subsequent assignment? In example number 1 below, where NAs are assigned by is.na()<-, testing the factor with is.na() finds the correct number of NAs. In example number 2, where the NAs are from the data, neither is.na(), ==NA,

Hi there, I am trying to understand how AliasAnalysis works out in LLVM. I used the following simple test-case (test4.c): -- void test() { int *jj, *kk; int aa = 100; jj = &aa; *jj = 300; } int main() { test(); return 0; } -- Then I did "llvm-gcc -emit-llvm -c -o test4.bc test4.c" to get bc. I tried the following 2 ways to get what I expect to get as

I've redirected this reply from r-help to the bugs list. On 11/3/2006 8:25 AM, vito muggeo wrote: > Dear all, > I am dealing with the following (apparently simple problem): > For some reasons I am interested in passing variables from a dataframe > to a specific environment, and in fitting a standard glm: > > dati<-data.frame(y=rnorm(10),x1=runif(10),x2=runif(10)) >

On Thu, May 14, 2009 at 2:19 PM, Weihua Sheng <weihua.sheng at gmail.com> wrote: > I actullay would expect the more accurate results from applying > anders-aa, but I could not interpret what has been returned - at least > I should see something like jj->aa, right? I'm not quite following... jj and aa don't alias; both versions show that. The results returned for