similar to: Post for R

Hi Carrie, You may have a problem with this if some subsets are empty: L3<-lapply(split(df,cut(df$max,seq(0,1,by=0.01))), split,cut(df$submax,seq(0,0.2,by=0.02))) Jim On Thu, Jun 1, 2017 at 12:48 PM, carrie wang via R-help <r-help at r-project.org> wrote: > > Hello, > I want to split the dataframe into 1000 groups based on two column values(max value and second max value).

Dear R-users, i have to integrate the following function `fun1` <- function (a, l1, l2) { exp(log(l1) * (a - 1) - l2 * lgamma(a)) } but if l1 is large, i get the "non-finite function value" error, so my idea is to rescale with exp(-l1) `fun2` <- function (a, l1, l2) { exp(log(l1) * (a - 1) - l2 * lgamma(a) - l1) } but it seems this doesn't solve the problem, when

I was wondering if one can have the coefficients of VAR model sorted according to variable names rather than lags. If you notice below, the output is sorted according to lags. >VAR(cbind(fossil,labour),p=2,type="const") VAR Estimation Results: ======================= Estimated coefficients for equation fossil: =========================================== Call: fossil = fossil.l1

Hi Could anybody explain me how to check how many L1/L2 cache my cpu have. I'm using CentOS 5.6 *cat /proc/cpuinfo |grep CPU * model name : Intel(R) Core(TM)2 Duo CPU T9300 @ 2.50GHz model name : Intel(R) Core(TM)2 Duo CPU T9300 @ 2.50GHz Diagram of a generic dual-core processor, with CPU-local level 1 caches, and a shared, on-die level 2 cache.

Hello, #I have two matrices, eg.: y <- matrix( c(20, NA, NA, 45, 50, 19, 32, 101, 10, 22, NA, NA, 80, 49, 61, 190), ncol=4 ) x <- matrix( c(20, NA, NA, NA, 50, 19, 32, 101, 10, 22, NA, NA, 80, 49, 61, 190), ncol=4 ) #Whereas x contains all NA?s from y plus some additional NA?s. #I want to find the index of these additional NA?s. I think, there must be a very

I have a vector of character strings such as mainnames<-c("CAD","AUD") and another vector say checknames<-c("CAD.l1","AUD.l1","JPY.l1","EUR.l1","CAD.l2","AUD.l2","JPY .l2","EUR.l2") I want a new vector of character strings that is just

Hi, I'm running into a wall when trying to use the integrate function. I have the following setting: powerLaw2 <- function(x,l1,l2,c0,t0) { idx <- which(x <= 0); if (length(idx) > 0) { x[idx] <- 0; } xl <- (-l1+l2)*log(x/t0); L <- log(c0)-l1*log(x)-log(1+exp(xl)); L <- exp(L); return(L); } plCDF2 <- function(x,l1,l2,c0,t0) {

I think that's incorrect. It should to: .section .foo .L1: .L2 = .L1 .section .bar .long .L3-.L2 .L3: Because .L3 and .L2 are in different sections. - Justin On Thu, Jun 26, 2014 at 2:46 PM, Rafael Espíndola <rafael.espindola at gmail.com> wrote: > This reduces to > > .section .foo > .L1: > .L2 = .L1 > .section .bar > .long .L1-.L2 > > > Which is fairly

Hi list, I have a very strange problem with my network. I have 2 internet connections: A - 1 Gbit, B - 100Mbps. Network layout: A, B | | [Brd1] / \ [L1] [L2] \ / [ GW1] ................... Clients ..................... Brd1 runs bgpd, and balances the traffic through L1 and L2. L1 and L2 do traffic shaping. GW1 does some packet

Hello list, I am wondering if a joining "one-to-many" can be done a little bit easier. I tried merge function but I was not able to do it, so I end up using for and if. Suppose you have a table with locations, each location repeated several times, and some attributes at that location. The second table has the same locations, but only once with a different set of attributes. I would

>> In short: there is no (live) migration support for nested VMX yet. So as >> soon as your guest is using VMX itself ("nVMX"), this is not expected to >> work. > > Hi David, thanks for getting back to us on this. Hi Florian, (sombeody please correct me if I'm wrong) > > I see your point, except the issue Kashyap and I are describing does > not

I have two factors l1, l2, and I'd like to merge them. (Remark: The factors can not be converted to charaters) Function c() does not give me the result I want: > l1 = factor(c('aaaa', 'bbbb')) > l2 = factor(c('ccc', 'dd')) > lMerge = factor(c(l1, l2)) > lMerge [1] 1 2 1 2 Levels: 1 2 > I'd like to merge l1 and l2 and to get lMerge

#If I have two lists as follows a1<- array(1:6, dim=c(2,3)) a2<- array(7:12, dim=c(2,3)) l1<- list(a1,a2) a3<- array(1:4, dim=c(2,2)) a4<- array(5:8, dim=c(2,2)) l2<- list(a3,a4) #how can I create a new list with the mean across all arrays within the list, so all components are included? As an example for [[1]]; cbind((l1[[1]][,1]+l2[[1]][,1])/2,

On 07.02.2018 16:31, Kashyap Chamarthy wrote: > [Cc: KVM upstream list.] > > On Tue, Feb 06, 2018 at 04:11:46PM +0100, Florian Haas wrote: >> Hi everyone, >> >> I hope this is the correct list to discuss this issue; please feel >> free to redirect me otherwise. >> >> I have a nested virtualization setup that looks as follows: >> >> - Host:

Hi LLVM developers, I want to add LICM pass after loop unrolling pass in current optimization pipeline. Because both of them are loop passes, so if I registered them one by one, they will interleaved go through all loops in bottom up way within same loop pass manager. Loop unroling pass may create new inner loops from partial unrolling, and those newly created loops can be visited only if the

Hello guys, I have a list L1 of matrix. I have another list L2 with the same number of elements representing the row of the L matrix that I want to delete (L1[[i]][-L2[[i]],]) but I can't do this with lapply as it iterates through L1 (first argument) and not L2. Any idea? ----- Anna Lippel -- View this message in context:

Hi, I am trying to create a dotplot where each panel shows levels vs. responses; the levels are sorted by responses but levels vary from one panel to another. However, I run into problems with controlling the y-limits and y-labels. In particular, suppose I have a data frame rsp <- c(10,2,4,0,2,3) lvl <-

In the context in which I am actually working it is necessary for me to build parts of a text string to place on a plot in two separate stages. The following toy example illustrates what I am trying to do: L1 <- substitute(list(paste("Bias in ", gamma,", "))) L2 <- substitute(list(beta==b0),list(b0=300)) plot(1:10,main=L1) # Works fine. plot(1:10,main=L2) # Works fine.

Hello, I'm using the function nlminb of the package stats inside a loop and when the number of trials grows, R crashes and says "R GUI front-end has stopped working". Could you help me with this problem? I have try in versions 2.15.1,2.15.2 and 3.0.0. > sessionInfo() R version 2.15.2 (2012-10-26) Platform: i386-w64-mingw32/i386 (32-bit) locale: [1]

Hi, There are some generated Sparc assembly code like this: main: ! @main ! BB#0: save %sp, -112, %sp sethi 0, %l0 or %g0, 5, %l1 st %l0, [%fp+-4] st %l1, [%fp+-8] st %l1, [%fp+-12] sethi %hi(.L.str), %l1 ld [%fp+-8], %o1 add %l1, %lo(.L.str), %l1 or %g0, %l1, %o0 call printf nop ld [%fp+-12], %o2 ld [%fp+-8], %l2 sethi %hi(.L.strQ521), %l3 add