similar to: samba Digest, Vol 136, Issue 31

Enviado desde mi smartphone BlackBerry Z10 4G Lte.   Mensaje original   De: admin at pr.copextel.com.cu Enviado: sábado, 7 de mayo de 2016 12:30 a.m. Para: admin at pr.copextel.com.cu Asunto: Daily mail report for 2016-05-06 Grand Totals ------------ messages 409 received 4135 delivered 0 forwarded 10 deferred (114 deferrals) 14 bounced 90 rejected (2%) 0 reject warnings 0 held 0 discarded (0%)

Dear R users I'm new in R management and maybe It's a silly question. I'm working with GLM to obtain predictive models. I have some problesm with the prediction instruction: > DatosTotal <- read.csv("Var_perdizcsv.csv", sep =";") > edvariable <- edit(DatosTotal) > pre <- predict(rlfinal, DatosTotal, type = 'probs') Erro en

Estimados No me resultó, describo paso a paso y adjunto base de datos str((df[,1:2]))# evaluo el tipo de variable salida data.frame': 101 obs. of 2 variables: $ alergia1 : chr "no" "no" "si" "si" ... $ parasitismo1: chr "si" "si" "si" "si" ... #esto es lo que quiero hacer library(MASS) farms.mca <-

> Estimados > > --En este artículo http://scielo.isciii.es/pdf/nh/v31n3/46originalvaloracionnutricional08.pdf Vectores de impedancia bioeléctrica, en la fig 1 hay un gráfico que realizan en un programa, mi pregunta es si > en R se puede calcular, si esto se relaciona a biplot, por favor > necesito de su ayuda > saludos > Dr. Jose A. Betancourt Bethencourt > Universidad

update.packages(ask=F, checkBuilt=T) FUNCIONA BIEN, ESTOY ACTUALIZANDO El 4/5/20, Emilio L. Cano <emilopezcano en gmail.com> escribió: > Sí la hay, yo antes lo hacía. Pero ahora pienso como Hadley: > https://twitter.com/hadleywickham/status/1254387031842701312 > <https://twitter.com/hadleywickham/status/1254387031842701312> > > Te digo de memoria (en Windows): copia

Estimados En este artículo que adjunto Vectores de impedancia bioeléctrica, en la fig 1 hay un gráfico que realizan en un programa, mi pregunta es si en R se puede calcular, si esto se relaciona a biplot, por favor necesito de su ayuda Saludos Dr. Jose A. Betancourt Bethencourt Universidad de Ciencias Medicas Carlos j. Finlay

Hi, This is likely an stupid question, but I cannot find the solution. I am searching for an "exit" function, to end the execution of an R script if some condition is not filled. Any clue? Thank you in advance! Federico

subscribe -- Ing. Pedro Rafael Reyes Terrero Admon. MediRed Instituto Superior de Ciencias Medicas Santiago de Cuba E-mail: pedro@medired.scu.sld.cu

Estimados quisiera tener el script para al hacer un pdf desde rmarkdown poder modificarle el tamano y tipo de fuente saludos José -- Dr. Jose A. Betancourt Bethencourt Universidad de Ciencias Medicas Carlos j. Finlay

Estimado Gracias por su ayuda José 2023-05-06 19:47 GMT-04:00, Carlos Ortega <cof en qualityexcellence.es>: > Hola, > > Si añades lo que destaco, defines el layout y queda más ajustado en la > pantalla. > > #-------------------------- > library(readxl) > Sistolica <- read_excel("./Sistolica1.xlsx") > library(meta) > m <- metacont( >

Dear all, I have a problem that may be someone of you can help. I am a newbie and do not find how to do it in manuals. I have two arrays, for example: ar1 <- array(data=c(1:16),dim=c(4,4)) ar2 <- array(data=c(1:16),dim=c(4,4)) colnames(ar1)<-c("A","B","D","E") colnames(ar2)<-c("C","A","E","B") > ar1

Hello, it might be a very simple question but I cannot find the solution (I tried a || b, any(a,b)... but none works). My problem is: I have two vectors, a <- c(TRUE,FALSE,FALSE) b <- c(TRUE,FALSE,TRUE) and I would like to obtain a vector that indicates if it is TRUE in any of the two vectors. Hence, the desired output would be: TRUE, FALSE, TRUE Thank you in advance, Federico

Hi, I am investigating a problem for which I found no solution. I have a matrix with two columns. I have plotted it as an x-y plot (plot(matrix[,1],matrix[,2]) But this is not apropriate for my purposes. I need to group the data in matrix[,1] into groups (as an histogram would do). Then I have to calculate the average of matrix[,2] for each group. Before starting with loops and loops I

msz De: Fern?ndez-L?pez, Ambito Iberoamericano, Paseo de la Castellana 223, Madrid. [1]InEnglish - [2]EnEspanol Caros amigos luso-brasileiros, ? de se perguntar se as "patrulhas ideol?gicas" esquerdistas estar?o impedindo que os ?ltimos artigos do ex preso pol?tico e escritor cubano Armando Valladares - que abordam delicados aspetos das rela??es entre o regime

Dear members of the list, it is likely a stupid question but I cannot find the information neither in R manuals nor in google. I am generating a plot (from hclust results) but I cannot see properly the labels because the default font size is too large. How can I change it? Thanks! Federico

We are pleased to announce the 6th European LLVM conference on March 17-18, 2016 in Barcelona, Spain. This will be a full two-day conference which aims to present the latest developments around LLVM and help strengthen the network of LLVM developers and users. The format will be similar to that of the previous meetings, with ample time for presentations, discussion, and networking between

Dear all, maybe somebody can provide some help for this problem: Example: I've got the following dataframe "data": grid.id<-c(1:4) lat<-c(10,12,13,15) species1<-c(0,0,0,1) species2<-c(1,1,0,0) species3<-c(1,1,1,1) data<-data.frame(cbind(grid.id,lat,species1,species2,species3)) How can I, out of "data" make a new dataframe, where the cells of value

Estimado José, Es la segunda vez que veo te pregunta en este Foro, la primera vez se te pidió mas detalles y luego se te dio una respuesta. El hecho que reiteres tu pregunta, sin detalles y sin mencionar que es lo que no funcionó con la respuesta anterior, me hace recordar algunas recomendaciones que leí en una excelente respuesta en http://stackoverflow.com/, que trato de adaptar a

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Dear R-list members, I´m using the package "survey" and I need to find a function for multinomial logistic regression in a complex design. The functions that I see are only for dicotomic and ordinal variables. Thank you! Rosario Austral ________________________________ De: "r-help-request@r-project.org" <r-help-request@r-project.org> Para: