similar to: Need help on calling Head from C

Hi , I am asking too many questions , sorry for that . I am creating a data frame in C itself , reading a table . The data frame calling code looks like this ====================================== *PROTECT(dfm=lang2(install("data.frame"),df));* *SEXP res = PROTECT(eval(dfm,R_GlobalEnv));* UNPROTECT(2); return res; ================================== It works fine , now the problem

On 6/30/20 1:06 PM, Jan Gorecki wrote: > It is quite known that R documentation on R C api could be improved... Please see "5.11 Evaluating R expressions from C" from "Writing R Extensions" Best Tomas > Still R-package-devel mailing list should be preferred for this kind > of questions. > Not sure if that is the best way, but works. > > call_to_sum <-

Hi All, I was reading the R extension manual section 5.11 ( Evaluating R expression from C) and I tried to build a simple call to the sum function. Please see below. call_to_sum <- inline::cfunction( language = "C", sig = c(x = "SEXP"), body = " SEXP e = PROTECT(lang2(install(\"sum\"), x)); SEXP ans = PROTECT(eval(e, R_GlobalEnv)); UNPROTECT(2); return

Hi I'm trying to implement something similar to the following R snippet using C. I seem to have hit the wall on accessing class slots using C. library(fPortfolio) lppData <- 100 * LPP2005.RET[, 1:6] ewSpec <- portfolioSpec() nAssets <- ncol(lppData) setWeights(ewSpec) <- rep(1/nAssets, times = nAssets) ewPortfolio <- feasiblePortfolio( data = lppData, spec = ewSpec,

I'd like to propose that the whenever the length of condition passed to an if or a while statement differs from one, an error is produced rather than just a warning as today: > x <- 1:2 > if (x == 1) message("x == 1") x == 1 Warning message: In if (x == 1) message("x == 1") : the condition has length > 1 and only the first element will be used There are

Is it expected that attributes set on a LGLSXP created by ScalarLogical will apply to all future objects created by ScalarLogical as well? For example: the 'test1' function below returns FALSE and 'test2' returns FALSE with an attribute: library(inline) test1 <- cfunction(body = 'return ScalarLogical(0);') test2 <- cfunction(body = ' SEXP success =

Hi all I don't know if my message are correct in this forums. I create a program in c++ who use statistical function. I want to execute this function in R (in particular for use packages ade4, lattice, bioconductor...) Until now, my program work for simple function ("plot", "rnorm"...) but I can't use library My class are : // in constructor int argc = 1;

Hi, I'm writing a C function that has to call a R function with multiple arguments. I've read the relevant section in Writing R Extensions, and searched the R site, mailing lists as well as rseek. I managed to call the function, but I'm now having trouble creating the argument list. I tried to create a pairlist of the arguments and send it to the R function. The R function however

Full_Name: Simon Anders Version: 2.6.2 OS: Ubuntu Linux Submission from: (NULL) (86.22.75.91) This is a rather minor "documentation bug", certainly not at all urgent. The manual "Writing R extensions" explains in section 5.10 ("Evaluating R expressions from C") how to use the eval function. Without going into much details, an example is given how to build up a

# read.table is NOT part of the data.table package #library(data.table) DFM <- read.table( text= 'obs start end 1 2/1/2015 1/1/2017 2 4/11/2010 1/1/2011 3 1/4/2006 5/3/2007 4 10/1/2007 1/1/2008 5 6/1/2011 1/1/2012 6 10/5/2004 12/1/2004 ',header = TRUE, stringsAsFactors = FALSE) # cleaner way to compute D DFM$start <- as.Date( DFM$start, format="%m/%d/%Y" ) DFM$end

It is quite known that R documentation on R C api could be improved... Still R-package-devel mailing list should be preferred for this kind of questions. Not sure if that is the best way, but works. call_to_sum <- inline::cfunction( language = "C", sig = c(x = "SEXP"), body = " SEXP e = PROTECT(lang2(install(\"sum\"), x)); SEXP r_true =

Thanks Jan and Tomas for the feedback. Answer from Jan is what I am looking for. Maybe I am not looking in the right place buy it is not easy to understand how these LCONS, CONS, SETCDR...etc works. Thank you Best regards Morgan On Tue, 30 Jun 2020, 12:36 Tomas Kalibera, <tomas.kalibera at gmail.com> wrote: > On 6/30/20 1:06 PM, Jan Gorecki wrote: > > It is quite known that R

Since the number of choices is small (6), how about this? Starting with Jeff's initial DFM: DFM <- structure(list(obs = 1:6, start = structure(c(16467, 14710, 13152, 13787, 15126, 12696), class = "Date"), end = structure(c(17167, 14975, 13636, 13879, 15340, 12753), class = "Date"), D = c(700, 265, 484, 92, 214, 57), bin = structure(c(6L, 3L, 5L, 1L, 3L, 1L), .Label

Thank you Jeff and All, Within a given time period (say 700 days, from the start day), I am expecting measurements taken at each time interval;. In this case "0" means measurement taken, "1" not taken (stopped or opted out and " -1" don't consider that time period for that individual. This will be compared with the actual measurements taken (Observed-

In my main R program, I have source("retaanalysis/Functions/doAirport.R") .... stuff to read data and calculate ads sapply(ads, function(x) {doAirport(x, base)} ) And doAirport has # analyze the flights for a given airport doAirport = function(df, base) { # Get rid of unused runway factor levels (from other airports) df$lrw <- drop.levels(df$lrw) # In gdata package #

I suspect there may be a bug in base::rbind.data.frame Below there is minimal example of the problem: m <- matrix (1:12, 3) dfm <- data.frame (c = 1 : 3, m = I (m)) str (dfm) m.names <- m rownames (m.names) <- letters [1:3] dfm.names <- data.frame (c = 1 : 3, m = I (m.names)) str (dfm.names) rbind (m, m.names) rbind (m.names, m) rbind (dfm, dfm.names) #not working rbind

Hi lily, As I have no idea of what the "true record" is, I can only guess. Maybe this will help: # get some fairly distinct colors rainbow_colors<-rainbow(9) # this should sort the numbers in dfm$A dfm$Acolor<-factor(dfm$A) plot(dfm$B,dfm$C,pch=ifelse(dfm$DF==1,1,19), col=rainbow_colors[as.numeric(dfm$Acolor)]) legend("bottom",legend=sort(unique(dfm$A)),

But it is not taken 'verbatim from src/main/print.c' (at least not in that version of R), and the code is not run with USE_RINTERNALS defined when write-barrier checking is enabled. The example has been updated to match the current code in 2.7.0 alpha. On Sun, 30 Mar 2008, sanders at fs.tum.de wrote: > Full_Name: Simon Anders > Version: 2.6.2 > OS: Ubuntu Linux >

Hi Jim, For true color, I meant that the points in the figure do not correspond to the values from the dataframe. Also, why to use rainbow(9) here? And the legend is straight in the middle, is it possible to reformat it to the very bottom? Thanks again. On Sun, Jul 16, 2017 at 2:50 AM, Jim Lemon <drjimlemon at gmail.com> wrote: > Hi lily, > As I have no idea of what the "true

For more than 10 records, how to reformat the colors? Also, how to show the first legend only, but at the bottom, while the second legend in your code is not necessary? In all, the same A values have the same color, but different symbols in DF==1 and DF==2. Thanks for your help. On Sun, Jul 16, 2017 at 9:28 AM, lily li <chocold12 at gmail.com> wrote: > Hi Jim, > > For true color,