similar to: question regarding lang2 command in C

Hi , I am trying to create a dataframe in C and sebd it back to R. Can anyone point me to the part of the source code where it is doing , let me explain the problem I am having . -------------------------------------------------------------------- My simple implementation is like this SEXP formDF() { SEXP dfm ,df , dfint , dfStr,lsnm; char *ab[3] =

Hi , I am trying to call head function from C . My doubt is with the parameter n,how to pass it . PROTECT(dfm=lang3(install("data.frame"),df,ScalarLogical(FALSE))); SET_TAG(CDDR(dfm), install("stringsAsFactors")) ; SEXP res = PROTECT(eval(dfm,R_GlobalEnv)); PROTECT(head=lang3(install("head"),res,ScalarInteger(1))); head = PROTECT(eval(head,R_GlobalEnv)); I tried

there is my code,  expect return value  is a data frame but R say it is list: SEXP Julia_R_MD_NA_DataFrame(jl_value_t* Var) {  SEXP ans,names,rownames;  char evalcmd[4096];  int i;  const char* dfname="DataFrameName0tmp";  jl_set_global(jl_main_module, jl_symbol(dfname), (jl_value_t*)Var);  //Get Frame cols   sprintf(evalcmd,"size(%s,2)",dfname);  jl_value_t*

Hi All, I was reading the R extension manual section 5.11 ( Evaluating R expression from C) and I tried to build a simple call to the sum function. Please see below. call_to_sum <- inline::cfunction( language = "C", sig = c(x = "SEXP"), body = " SEXP e = PROTECT(lang2(install(\"sum\"), x)); SEXP ans = PROTECT(eval(e, R_GlobalEnv)); UNPROTECT(2); return

On 6/30/20 1:06 PM, Jan Gorecki wrote: > It is quite known that R documentation on R C api could be improved... Please see "5.11 Evaluating R expressions from C" from "Writing R Extensions" Best Tomas > Still R-package-devel mailing list should be preferred for this kind > of questions. > Not sure if that is the best way, but works. > > call_to_sum <-

Hi, I have been studying the R manual on lists but cannot seem to create a simple R list in C - I keep on getting "'dimnames' applied to non-array" whenever I attempt to assign names to the list elements: Wanted output a list structure something like [ type="Bid", price=2.0, volume=1000 ] I can get up to a list of [ "Bid2, 2.0, 1000 ] But for the life of

This message is in MIME format. Since your mail reader does not understand this format, some or all of this message may not be legible. ------_=_NextPart_000_01C3738F.63DE3390 Content-Type: text/plain; charset="iso-8859-1" #I want to be able to create a new S4 class and read data into it using C code # Here is a very simple S4 object inheriting from "array", but with 5

Hello, I have created a vector with 2 elements(see code below) I am calling this function many thousands of times (hundreds of thousands) after some time i get *** caught segfault *** address 0x5, cause 'memory not mapped' However, if i dont set the R_NamesSymbol, I do not get any such error. Am I doing this correctly? Thank you Saptarshi ==CODE=== // kxp and usar are two SEXP's

Hi , For our production package i need to create a dataframein C . So I wrote the following code SEXP dfm ,head,df , dfint , dfStr,lsnm; *SEXP valueVector[2];* char *ab[3] = {"aa","vv","gy"}; int sn[3] ={99,89,12}; char *listnames[2] = {"int","string"}; int i,j; //============================= PROTECT(df = allocVector(VECSXP,2));

man for `qr` says that the function uses LINPACK's DQRDC, while it in fact uses DQRDC2. ``` The QR decomposition of the matrix as computed by LINPACK or LAPACK. The components in the returned value correspond directly to the values returned by DQRDC/DGEQP3/ZGEQP3 ```

Hi, I'm troubleshooting some native code on Windows that very occationally (and semi-randomly) crashes R. Already looked at "everything", I just want to double check that it is safe to UNPROTECT() allocated variables as soon as they are assigned to, say, a PROTECTed list. >From (R v2.3.0) Section 5.7.1 "Handling the effects of garbage collection" in "Writing R

Hi, I have a C code which produces array of integers and potentially a string, and I have problems passing the string out. Here is the relevant part of the code: 1 PROTECT(Ret = allocVector(INTSXP, n)); 2 ret = (int*) INTEGER(Ret); /* get pointer to R's Ret */ 3 for(i=0; i<n; i++) ret[i] = data[i]; 4 Free(data); 5 i=1; 6 if (comment) { // comment was found 7 n

Hi, I have a C code which produces array of integers and potentially a string, and I have problems passing the string out. Here is the relevant part of the code: 1 PROTECT(Ret = allocVector(INTSXP, n)); 2 ret = (int*) INTEGER(Ret); /* get pointer to R's Ret */ 3 for(i=0; i<n; i++) ret[i] = data[i]; 4 Free(data); 5 i=1; 6 if (comment) { // comment was found 7 n

# read.table is NOT part of the data.table package #library(data.table) DFM <- read.table( text= 'obs start end 1 2/1/2015 1/1/2017 2 4/11/2010 1/1/2011 3 1/4/2006 5/3/2007 4 10/1/2007 1/1/2008 5 6/1/2011 1/1/2012 6 10/5/2004 12/1/2004 ',header = TRUE, stringsAsFactors = FALSE) # cleaner way to compute D DFM$start <- as.Date( DFM$start, format="%m/%d/%Y" ) DFM$end

Since the number of choices is small (6), how about this? Starting with Jeff's initial DFM: DFM <- structure(list(obs = 1:6, start = structure(c(16467, 14710, 13152, 13787, 15126, 12696), class = "Date"), end = structure(c(17167, 14975, 13636, 13879, 15340, 12753), class = "Date"), D = c(700, 265, 484, 92, 214, 57), bin = structure(c(6L, 3L, 5L, 1L, 3L, 1L), .Label

Thank you Jeff and All, Within a given time period (say 700 days, from the start day), I am expecting measurements taken at each time interval;. In this case "0" means measurement taken, "1" not taken (stopped or opted out and " -1" don't consider that time period for that individual. This will be compared with the actual measurements taken (Observed-

In my main R program, I have source("retaanalysis/Functions/doAirport.R") .... stuff to read data and calculate ads sapply(ads, function(x) {doAirport(x, base)} ) And doAirport has # analyze the flights for a given airport doAirport = function(df, base) { # Get rid of unused runway factor levels (from other airports) df$lrw <- drop.levels(df$lrw) # In gdata package #

I suspect there may be a bug in base::rbind.data.frame Below there is minimal example of the problem: m <- matrix (1:12, 3) dfm <- data.frame (c = 1 : 3, m = I (m)) str (dfm) m.names <- m rownames (m.names) <- letters [1:3] dfm.names <- data.frame (c = 1 : 3, m = I (m.names)) str (dfm.names) rbind (m, m.names) rbind (m.names, m) rbind (dfm, dfm.names) #not working rbind

Hi lily, As I have no idea of what the "true record" is, I can only guess. Maybe this will help: # get some fairly distinct colors rainbow_colors<-rainbow(9) # this should sort the numbers in dfm$A dfm$Acolor<-factor(dfm$A) plot(dfm$B,dfm$C,pch=ifelse(dfm$DF==1,1,19), col=rainbow_colors[as.numeric(dfm$Acolor)]) legend("bottom",legend=sort(unique(dfm$A)),

Hi Jim, For true color, I meant that the points in the figure do not correspond to the values from the dataframe. Also, why to use rainbow(9) here? And the legend is straight in the middle, is it possible to reformat it to the very bottom? Thanks again. On Sun, Jul 16, 2017 at 2:50 AM, Jim Lemon <drjimlemon at gmail.com> wrote: > Hi lily, > As I have no idea of what the "true