similar to: Plot mortality data and show trend

Good morning! I've searched the docs etc... Am I doing something wrong or is this a bug? I'm doing a merge of two dataframes and getting extra rows in the resulting dataframe - the dataframes being merged might have NAs... count <- 10 nacount <- 3 a1 <- as.data.frame(as.Date("2005-06-01")+0:(count-1)) names(a1) <- "mdate" a1$value <- runif(count)

Colleagues During the transition to R3.0.0 (OS X), one of the packages that I used -- SASxport -- did not work until I used the "type=source" option in install.packages. This led to an adventure: 1. I downloaded the package source: SASxport_1.2.4.tar.gz 2. in the SASxport/R folder, I found all the functions that are part of the package. I became interested in whether I could

I tried the code that Richard O'Keefe posted last week, to wit: library(chron) ymd.to.POSIXlt <- function (y, m, d) as.POSIXlt(chron(julian(y=y, x=m, d=d))) n <- 100000 y <- sample(1970:2004, n, replace=TRUE) m <- sample(1:12, n, replace=TRUE) d <- sample(1:28, n, replace=TRUE) system.time(ymd.to.POSIXlt(y, m, d)) [1] 8.78 0.10

Dear all, I have a problem with the function Julian, may be a bug in the function ? Here is a vector of character, which represents dates (May 18 to May 20 2000): > amj <- c("2000-05-18","2000-05-18","2000-05-18","2000-05-19","2000-05-19" > ,"2000-05-19", "2000-05-19", "2000-05-20", "2000-05-20",

hi, Thanks for responding of gantt charts. but i have some problem regarding with gantt charts. i.e. Ymd.format <- "%Y/%m/%d" Ymd <- function(x){ as.POSIXct(strptime(x, format=Ymd.format))} gantt.info <- list( labels =c("First task","Second task","Third task","Fourth task","Fifth task"), starts

I am having a problem with a gantt chart since moving to R2.4.0. from 2.3.1 I made some adaptations to the code from http://addictedtor.free.fr/graphiques/RGraphGallery.php?graph=74 and successful produced a simple gantt chart. However when I upgraded to 2.4.0 it no longer works as desired. See http://ca.geocities.com/jrkrideau/R/gantproblem.pdf for the two charts. The charts were produced

Hi, I don't know to solve this error that is returned, even though I understand it: library(plotrix) Ymd.format<-"%Y/%m/%d" gantt.info<-list(labels= c("First task","Second task (1st part)","Third task (1st part)","Second task (2nd part)","Third task (2nd part)", "Fourt task","Fifth task","Sixth

I know this: > library(date) > x="1979-04-04" > try=as.date(x, "ymd") > print(try) [1] 4Apr79 and that `x' here has to be a string, e.g.: > x=1979-04-04 > print(x) [1] 1971 I'm stuck in reading from a file. I say: > A <- read.table(file="try") > print(A) V1 V2 1 1979-04-04

Hola, Otra forma, utilizando la función de intervalos y la que comprueba si otro intervalo se solapa del paquete "lubridate": #---------------------- library(lubridate) fe.chas <- data.frame( entra=c('2001-01-01','2001-06-01','2003-01-01') ,sale=c('2002-01-01','2002-06-01','2004-01-01') ) ref <-

I have a daily time series and have two questions to get some help with. Firs,t I have dates in simple numeric values. e.g. ymd [1] 20050104 20050105 20050106 20050107 20050110 20050111 20050113 20050114 [9] 20050118 20050120 20050121 20050124 20050125 20050126 20050127 20050128 [17] 20050201 20050202 20050203 20050204 Now, I'd like to compute statistics, e.g. acf, by business days. So, I

Dear, According to the documentation, the parameters given in "dates" are passed to the function "chron". When trying this out, it turns out that this apparently doesn't happen, eg: > dates("20100101",format="Ymd",out.format="day mon year") [1] 01/01/10 > chron("20100101",format="Ymd",out.format="day mon

Hi All, I am reading data file ( > 1B rows) and do some date formatting like dat=fread(mydatafile) dat$date1 <- as.Date(ymd(dat$date1)) However, I am getting an error message saying that Error: cons memory exhausted (limit reached?) The script was working when the number rows were around 650M. Is there another way to handle a big data set in R? Thank you.

Hi! Is not there an standard R function to retrieve the day of the year (since 1st Jan of the same year)? I know I can make my own using julian, but find it weird that having days(), months() etc doy() does not exist as an standard function. Also, is the following not a bit inconsistent? > a <- chron("20100506",format="ymd") > a [1] 100506 > years(a) [1] 2010

How do I parse a date "yyyymmdd"? I tried asking chron(s, "ymd") but that didn't work. Would the date parsing routines of the Date class of 1.9 grok this? -- Ajay Shah Consultant ajayshah at mayin.org Department of Economic Affairs http://www.mayin.org/ajayshah Ministry of Finance, New Delhi

Good afternoon, I have a 63 small .csv files which I process daily, and until two weeks ago they processed just fine and only took a matter of moments and had non noticeable memory problem. Two weeks ago they have reached 318 lines and my script "broke". There are some missing-values in some of the files. I have tried hard many times over the last two weeks to create a

I'm trying to read intraday zoo but running into issues (again) ... what am I missing here? (the date doesn't seem to read in correctly) > head(dat) TrdDate TrdTime impliedVol 1 20090102 09:55:03 0.3610715 2 20090102 09:55:04 0.3637943 3 20090102 09:55:05 0.3752375 4 20090102 09:55:05 0.4190025 5 20090102 09:55:06 0.3696080 6 20090102 09:55:06 0.4944981 > f <-

Buenas, Tengo un dataframe con 64.000 observaciones llamado Datos y las variables "Id.Producto","Fecha"y "Rating" . La variable fecha tiene el formato: 2016-12-28 (ymd). Quiero crear la variable: "Rating.Semanal" - Esta variable tiene que ser la media agregada por "Id.Producto" de la variable "Rating", solo teniendo en cuenta

I took a look at Hadley's lubridate which seems a very neat package, but i am having a small problem with  concatenating lubridates to build vectors of it. Namely when function c( )  is applied to lubridate seems to change time to a local timezone in this particular case changing the date to previous one.  > d<-ymd('20111231') > d [1] "2011-12-31 UTC" > c(d) [1]

Hi R, How to get the range of values form startDate to lastDate as given below?. #***************************************************************** # Load historical data #****************************************************************** library('quantmod') endDate =Sys.Date() startDate = as.Date(endDate-30, order="ymd") dataspy = getSymbols("SPY", from = startDate,

I have date data as a numeric and hourly data in 0 to 2300 hours in a dataframe. d <- rep(20110101,24) h <- seq(from = 0, to = 2300, by = 100) df <- data.frame(LST_DATE = d, LST_TIME = h, data = rnorm(24, 0, 1)) S <- chron(dates. = as.character(df$LST_DATE), times. = paste(as.character(df$LST_TIME/100), ":0:0", sep = ""), format =