Displaying 20 results from an estimated 300 matches similar to: "Best and worst values for each date"
2013 Sep 27
0
Best and Worst values
Ira,
obj_name<- load("arun.RData")
Pred1<- get(obj_name[1])
Actual1<- get(obj_name[2])
dat2<- data.frame(S1=rep(Pred1[,1],ncol(Pred1)-1),variable=rep(colnames(Pred1)[-1],each=nrow(Pred1)),Predict=unlist(Pred1[,-1],use.names=FALSE),Actual=unlist(Actual1[,-1],use.names=FALSE),stringsAsFactors=FALSE)
dat2New<- dat2[!(is.na(dat2$Predict)|is.na(dat2$Actual)),]
?dat3<-
2009 Mar 21
1
Forestplot () box size question
Hi All,
I have been able to modify the x-axis to start at zero by adding xlow
and xhigh parameters; that was pretty simple. I have been unable to
find the location of the code that would turn off the information
weighting of the box size (I have smaller randomized trials getting
less weight than a much larger non-randomized trial). The function
is forestplot() from rmeta.
Thanks for any
2009 Feb 08
0
Modifying forestplot function in rmeta
All,
I am using the forestplot function in rmeta.
I was able to modify the x axis range by commenting out one line and
feeding it two new parameters (I wanted to set zero as the axis start point).
#xrange <- c(max(min(lower, na.rm = TRUE), clip[1]),
min(max(upper, na.rm = TRUE), clip[2]))
#new line
xrange <- c(xlow,xhigh)
Now I am trying to modify the text font size for
2013 May 11
3
boxplot with grouped variables
my dataset looked like this in the beginning:
>Daten
V1 V2 V3
1 Dosis Gewicht Geschlecht
2 0 6.62 m
3 0 6.65 m
4 0 5.78 m
5 0 5.63 m
I need box plots for V2 with all combination of V1 and V3, so I deleted the
first row, and tried this:
boxplot(Daten$V2[Daten$V3=="m"])
but it does not work and I
2013 Mar 27
9
conditional Dataframe filling
Hi everyone:
This may be trivial but I just have not been able to figure it out.
Imagine the following dataframe:
a b c d
TRUE TRUE TRUE TRUE
FALSE FALSE FALSE TRUE
FALSE TRUE FALSE FALSE
I would like to create a new dataframe, in which TRUE gets 0 but if
false then add 1 to the cell to the left. So the results for the
example above should be something like:
a b c
2013 Jun 15
2
Plotting two y-axis vs non-numeric x-axis
Hi dear all, the following code is correct. but I want to use non-numeric
x-axis, for example
if I replace time <- seq(0,72,6) by
month <-
c("Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec","Pag")
Ofcourse I use factor(month) instead of
2008 Dec 13
2
weird pasting of ".value" when list is returned
could someone explain why the name of FPVAL gets " .value" concatenated
onto it when the code below is run and temp is returned.
I've been trying to figure this out for too long. It doesn't matter when
I put the FPVAL in the return statement. It happens regardless of
whether it's first or last. Thanks.
f.lmmultenhanced <-
function(response, pred1, pred2)
{
2020 Nov 19
2
Understanding CallInst::Create
Hello;
I am working on porting a tool written for LLVM3.5 to LLVM10. There
used to be a call instruction with the signature
static CallInst * Create (Value *F, Value *Actual, const Twine
&NameStr="", Instruction *InsertBefore=0)
Can anyone please explain what it supposed to do? What was F and Actual?
Thank you so much.
--
Dr. Arnamoy Bhattacharyya
R&D Compiler Engineer
2013 Aug 22
1
converting a summary table to survey database form
Hi!
I am looking to choose a condom based on its pleasure score.
I received some summarised data from 10 individuals:
structure(list(Ramses = c(4, 4, 5, 5, 6, 3, 4, 4, 3, 4), Sheiks = c(5,
5, 6, 4, 7, 6, 4, 5, 6, 3), Trojans = c(7, 8, 7, 9, 6, 3, 2,
2, 2, 3), Unnamed = c(2, 1, 1, 3, 3, 4, 5, 4, 4, 3)), .Names = c("Ramses",
"Sheiks", "Trojans", "Unnamed"),
2004 Jun 16
2
gam
hi,
i'm working with mgcv packages and specially gam. My exemple is:
>test<-gam(B~s(pred1)+s(pred2))
>plot(test,pages=1)
when ploting test, you can view pred1 vs s(pred1, edf[1] ) & pred2 vs
s(pred2, edf[2] )
I would like to know if there is a way to access to those terms
(s(pred1) & s(pred2)). Does someone know how?
the purpose is to access to equation of smooths terms
2009 Feb 23
1
Follow-up to Reply: Overdispersion with binomial distribution
THANKS so very much for your help (previous and future!). I have a two
follow-up questions.
1) You say that dispersion = 1 by definition ....dispersion changes from 1
to 13.5 when I go from binomial to quasibinomial....does this suggest that
I should use the binomial? i.e., is the dispersion factor more important
that the
2) Is there a cutoff for too much overdispersion - mine seems to be
2012 Mar 19
1
glm: getting the confidence interval for an Odds Ratio, when using predict()
Say I fit a logistic model and want to calculate an odds ratio between 2
sets of predictors. It is easy to obtain the difference in the predicted
logodds using the predict() function, and thus get a point-estimate OR. But
I can't see how to obtain the confidence interval for such an OR.
For example:
model <- glm(chd ~age.cat + male + lowed, family=binomial(logit))
pred1 <-
2007 Jun 04
3
Extracting lists in the dataframe $ format
I'm new to R and am trying to extract the factors of a dataframe using numeric indices (e.g. df[1]) that are input to a function definition instead of the other types of references (e.g. df$out). df[1] is a list(?) whose class is "dataframe". These indexed lists can be printed successfuly but are not agreeable to the plot() and lm() functions shown below as are their df$out
2005 Mar 03
3
creating a formula on-the-fly inside a function
I have a function that, among other things, runs a linear model and
returns r2. But, the number of predictor variables passed to the
function changes from 1 to 3. How can I change the formula inside the
function depending on the number of variables passed in?
An example:
get.model.fit <- function(response.dat, pred1.dat, pred2.dat = NULL,
pred3.dat = NULL)
{
res <- lm(response.dat ~
2011 Sep 06
1
Question about Natural Splines (ns function)
Hi - How can I 'manually' reproduce the results in 'pred1' below? My attempt
is pred_manual, but is not correct. Any help is much appreciated.
library(splines)
set.seed(12345)
y <- rgamma(1000, shape =0.5)
age <- rnorm(1000, 45, 10)
glm1 <- glm(y ~ ns(age, 4), family=Gamma(link=log))
dd <- data.frame(age = 16:80)
mm <- model.matrix( ~ ns(dd$age, 4))
pred1 <-
2011 Apr 06
3
ROCR - best sensitivity/specificity tradeoff?
Hi,
My questions concerns the ROCR package and I hope somebody here on the list can help - or point me to some better place.
When evaluating a model's performane, like this:
pred1 <- predict(model, ..., type="response")
pred2 <- prediction(pred1, binary_classifier_vector)
perf <- performance(pred, "sens", "spec")
(Where "prediction" and
2016 Nov 01
2
as.formula("x") error on C stack limit
Dear all,
I tried to run as.formula("x") and got an error message "Error: C stack
usage 7971120 is too close to the limit" whether x exists or not. This is
not the case in as.formula("y"), where "object 'y' not found" is the error
message if y not exists, or "invalid formula" error or a formula depending
on y. Can anyone confirm this is
2009 Jun 12
1
coupled ODE population model
I'm fairly new to R, and I'm trying to write out a population model that
satisfies the following;
the system consists of s species, i= 1, 2,...,s
network of interactions between species is specified by a (s x s) real matrix,
C[i,j]
x[i] being the relative population of the "ith" species (0 =< x[i] =< 1,
sum(x[i]=1)
the evolution rule being considered is as follows;
2008 Sep 11
1
how to calcaulate matrices for two subsets
I am an R beginner and trying to run a market model using event study in
R framework.
First, I run a market model, that is lm(stock security~SP500 index,
subset=Obs[197, 396]) ->result1
Then I get predict results for a new dataset using predict (result1,
newdata=Obs[397,399]) ->pred1
Pred1 should have three numbers.
Now I need to calculate abnormal return by the formula stock
2013 May 07
4
how to calculate the mean in a period of time?
Hi,
Your question is still not clear.
May be this helps:
dat2<- read.table(text="
patient_id????? t???????? scores
1????????????????????? 0??????????????? 1.6
1????????????????????? 1??????????????? 2.6
1????????????????????? 2???????????????? 2.2
1????????????????????? 3???????????????? 1.8
2????????????????????? 0????????????????? 2.3
2?????????????????????? 2???????????????? 2.5