Displaying 20 results from an estimated 3000 matches similar to: "problems with saving plots from loop"
2004 Mar 15
11
creating a ps. file
Dear all
I wrote a routine. At the end of each cycle of the loop I would like to 
save the result (plot) in a postcriptfile.
Of course if I just use dev.print in the following way: 
dev.print(device=postcript, 'c:/Rfigures/plot_1.ps")
I overwrite my results with the second cycle of the loop. I suppose 
there is a way to define the file name so that several plots are 
2018 May 11
3
add one variable to a data frame
Hi Sarah,
Thank you so much!! I got your good ideas.
Ding
-----Original Message-----
From: Sarah Goslee [mailto:sarah.goslee at gmail.com] 
Sent: Friday, May 11, 2018 11:40 AM
To: Ding, Yuan Chun
Cc: r-help mailing list
Subject: Re: [R] add one variable to a data frame
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2007 Dec 28
3
How to catch data from the different dataframes and lm problem?
Dear all: 
I am a new R-user and I have 2 questions
about it.  
1) I have a dataframe.  Based on ?formulation? and ?subject?, a
dataframe is split into 4 dataframes.  The
example is as follows.  Moreover, I want
to calculate ?test? value for these 4 dataframes.  My question is that the ?test? values not
correct and I do not know where the problem is.
2) There are 12 ?test? (y) values from
2018 May 11
0
add one variable to a data frame
Sarah's solutions are good, and here's another, even more basic:
tmp1 <- unique(dat1$B)
tmp2 <- seq_along(tmp1)
dat1$C <- tmp2[ match( dat1$B, tmp1) ]
> dat1
    N      B C
1   1 29_log 1
2   2 29_log 1
3   3 29_log 1
4   4 27_cat 2
5   5 27_cat 2
6   6  1_log 3
7   7  1_log 3
8   8  1_log 3
9   9  1_log 3
10 10  1_log 3
11 11  3_cat 4
12 12  3_cat 4
As a single line
2018 May 11
3
add one variable to a data frame
Hi All,
I have a data frame dat1:
dat1 <-data.frame(N=seq(1, 12,1), B=c("29_log","29_log", "29_log", "27_cat", "27_cat",
                                                                       "1_log", "1_log", "1_log", "1_log", "1_log",
                                                           
2011 Feb 05
3
spline interpolation
Hello R-help 
I have the following data for a standard curve
concentration(nM),fluorescence
0,48.34
2,58.69
5,70.83
10,94.73
20,190.8
50,436.0
100, 957.9
 
(1)Is there function in R to plot a spline.
(2)How can I interpolation,say 1000 point from 0nM-100nM and store this as a 
data frame of concentration,fluorescence
(3)How can I modify the code below so that instead of retrieving a concentration 
2013 May 07
4
create unique ID for each group
Hey All,
I have a dataset(dat1) like this:
ObsNumber     ID          Weight
     1                 0001         12
     2                 0001          13
     3                 0001           14
     4                  0002         16
      5                 0002         17
And another dataset(dat2) like this:
ID               Height
0001            3.2
0001             2.6
0001            
2013 Sep 21
1
Translating recoding syntax from SPSS to R
Colleagues,
I am in the process of learning R. I've been able to import my dataset (from Stata) and do some simple coding. I have now come to coding situation that requires some assistance. This is some code in SPSS that I would like to be able to execute in R:
if (race eq 1 and usborn=0) confused=1 .
if (race eq 2 and usborn=0) confused=1 .
if (race eq 1 and usborn=1) confused=0 .
if (race
2010 Mar 30
2
Need help to split a given matrix is a "sequential" way
I need to split a given matrix in a sequential order. Let my matrix is :
> dat <- cbind(sample(c(100,200), 10, T), sample(c(50,100, 150, 180), 10,
> T), sample(seq(20, 200, by=20), 10, T)); dat
      [,1] [,2] [,3]
 [1,]  200  100   80
 [2,]  100  180   80
 [3,]  200  150  180
 [4,]  200   50  140
 [5,]  100  150   60
 [6,]  100   50   60
 [7,]  100  100  100
 [8,]  200  150  100
 [9,] 
2013 Jan 08
2
plot residuals per factor
Dear R-users,
I want to plot residuals vs fitted for multiple groups with ggplot2.
I try this code, but unsuccessful.
library("plyr")
models<-dlply(dat1,"d",function(df)
mod<-lm(y~x,data=df)
  ggplot(models,aes(.fitted,.resid), color=factor(d))+
  geom_hline(yintercept=0,col="white",size=2)+
  geom_point()+
  geom_smooth(se=F)
-- 
---
Catalin-Constantin ROIBU
2013 Apr 29
4
expanding a presence only dataset into presence/absence
Hello,
I'm working with a very large dataset (250,000+ lines in its' current form)
that includes presence only data on various species (which is nested within
different sites and sampling dates). I need to convert this into a dataset
with presence/absence for each species. For example, I would like to expand
"My current data" to "Desired data":
My current data
2008 Mar 25
2
Compare two data sets
I would like to compare two data sets saved as text files (example below) to determine if both sets are identical(or if dat2 is missing information that is included in dat1) and if they are not identical list what information is different between the two sets(ie output "a1", "a3" as the differing information).  The overall purpose would be to remove "a1" and
2013 Jan 09
4
select partial name and full name columns
Hi, I have the following function:
getDataFromDVFileCustom <- function (file, hasHeader = TRUE, separator =
"\t") 
{
DVdatatmp <- as.matrix(read.table(file, sep = "\t", fill = TRUE,
comment.char = "#", as.is = TRUE, stringsAsFactors = FALSE, na.strings =
"NA"))
DVdatatmper <- as.matrix(DVdatatmp[ , c("datetime",
2018 May 11
0
add one variable to a data frame
Hi,
Here's one way to approach it, using the coercion of factor to numeric.
Note that I changed your data.frame() statement to avoid coercing
strings to factors, just to make it simpler to set the levels.
dat1 <-data.frame(N=seq(1, 12,1), B=c("29_log","29_log", "29_log",
"27_cat", "27_cat", "1_log", "1_log",
2013 Jan 04
2
Can you help me please
HI Fares,
You could try this:
dat1<- read.table(text="
date????? donation
3jan2003?? 20235
4jan2003?? 25655
5jan2003?? 225860
6jan2003?? 289658
7jan2003?? 243889
8jan2003?? 244338
9jan2003?? 243889
",sep="",header=TRUE,stringsAsFactors=FALSE) 
The post is not very specific as to what you need.? I hope this works for you.
library(xts)
2012 Jul 01
2
list to dataframe conversion-testing for identical
HI R help,
I was trying to get identical data frame from a list using two methods.
#Suppose my list is:
listdat1<-list(rnorm(10,20),rep(LETTERS[1:2],5),rep(1:5,2))
#Creating dataframe using cbind
dat1<-data.frame(do.call("cbind",listdat1))
colnames(dat1)<-c("Var1","Var2","Var3")
#Second dataframe conversion
2013 Aug 29
4
Add new calculated column to data frame
Hi,
I have a following data set:
id    event    time (in sec)
1     add      1373502892
2     add      1373502972
3     delete   1373502995
4     view      1373503896
5     add       1373503996
...
I'd like to add new column "time on task" which is time elapsed between two
events (id2 - id1...). What would be the best approach to do that?
Thanks,
Srecko
	[[alternative HTML
2013 Mar 27
9
conditional Dataframe filling
Hi everyone:
This may be trivial but I just have not been able to figure it out.
Imagine the following dataframe:
a     b     c     d
TRUE  TRUE  TRUE  TRUE
FALSE FALSE FALSE TRUE
FALSE  TRUE  FALSE  FALSE
I would like to create a new dataframe, in which TRUE gets 0 but if  
false then add 1 to the cell to the left. So the results for the  
example above should be something like:
a     b     c
2012 Jun 07
3
conditional statement to replace values in dataframe with NA
Hello and thanks for helping.
#some data
L3 <- LETTERS[1:3]
dat1 <- data.frame(cbind(x=1, y=rep(1:3,2), fac=sample(L3, 6, replace=TRUE)))
#When x==1 and y==1 I want to replace the 1 values with NA
#I can select the rows I want:
dat2<-subset(dat1,x==1 & y==1)
#replace the 1 with NA
dat2$x<-rep(NA,nrow(dat2)
dat2$y<-rep(NA,nrow(dat2)
#select the other rows and rbind
2010 Aug 20
2
Determining the length of unique items in a vector
Dear all, let suppose I have following vector:
 
> dat1 <- c(rep("asd", 5), rep("xyz", 12), rep("erd", 17))
> dat1 <- dat1[sample(1:length(dat1), length(dat1), replace=F)]
> dat1
 [1] "erd" "xyz" "erd" "asd" "asd" "erd" "xyz" "asd" "erd" "erd"