similar to: Picking back up Ruby on Rails

I am new to R. I just tried to recreate in R (using sem package and the identical input data) a solution for a simple measurment model I have found before in LISREL. LISREL had no problems and converged in just 3 iterations. In sem, I got no solution, just the warning message: "Could not compute QR decomposition of Hessian. Optimization probably did not converge. in: sem.default(ram =

Hello, I finally run my measurement model in sem - successfully. Now, I am trying to print out the path diagram that is based on the results - but for some reason it's not working. Below is my script - but the problem is probably in my very last line: # ANALYSIS OF ANXIETY, DEPRESSION, AND FEAR - LISREL P.31 library(sem) # Creating the ANXIETY, DEPRESSION, AND FEAR intercorrelation matrix

Hello ALL! I have a problem to plot factor (lets say gender) as a line, or at least both line and point, from ols model: ols1 <- ols(Y ~ gender, data=dat, x=T, y=T) plot(ols1, gender=NA, xlab="gender", ylab="Y", ylim=c(5,30), conf.int=FALSE) If I convert gender into discrete numeric predictor, and use forceLines=TRUE, plot is not nice and true, since it shows values

Hi all, I'm quite new to R and have a very basic question regarding how one gets the standard error of the mean for factor levels under aov. I was able to get the factor level means using: summary(print(model.tables(rawfixtimedata.aov,"means"),digits=3)), where rawfixtimedata.aov is my aov model. It doesn't appear that there is an equivalent function to get the standard

I am having two problems creating data frames that I have solutions, but they really seem like kludges and I assume I just don't understand the proper R way of doing things. The first situation is I have an set of uneven data vectors. When I try to use them to create a data frame I would like the bottoms of them padded with NAs, without explicitly specifying that. When I do: anxiety.data =

workaround can't be used in wine 1.3.21 winetricks wininet wine iexplore fixme:urlmon:create_object Could not find object for MIME L"application/x-gzip-compressed"

Hi all, I have received the following error from summary.manova: Error in summary.manova(manova.test, test = "Pillai") : residuals have rank 36 < 64 The data is simulated data for 64 variables. The design is a 2*2 factorial with 10 replicates per treatment. Looking at the code for summary.manova, the error involves a problem with qr(). Does anyone have a suggestion as to how to

On 2020-06-19, Justin Hibbits via llvm-dev wrote: >On Fri, 19 Jun 2020 17:38:02 +0100 >Renato Golin <rengolin at gmail.com> wrote: > >> On Fri, 19 Jun 2020 at 16:43, Robinson, Paul via llvm-dev >> <llvm-dev at lists.llvm.org> wrote: >> > If anyone's keeping track of the voting: >> > +1 for "dev" (contrasts with "release")

Hi, I have a set of 30 binary variables measuring side effects after drug treatment. Since each subject can have multiple side effects, I want to display these side effects in a multiple choice table. I'm using the summary and mChoice functions of the Hmisc package, because it produces nicely formatted latex tables. My problem is, that table includes a category for people who have at

On Fri, 19 Jun 2020 14:45:37 +0100 Renato Golin via llvm-dev <llvm-dev at lists.llvm.org> wrote: > On Fri, 19 Jun 2020 at 12:57, Hal Finkel via llvm-dev > <llvm-dev at lists.llvm.org> wrote: > > I like "dev" as an option here. It's short, and in addition, > > conveys the fact that the development happens in that branch. > > "main" in

I am looping over many data files and reading in the data with F <- read.table(filename) to read in a 22000 by 15 matrix. Works fine on the first matrix F, but I get the following error when the second file is read into F: Error in "row.names<-.data.frame"(*tmp*, value = row.names) : duplicate row.names are not allowed I have tried picking a column of the matrix and

On Fri, 19 Jun 2020 14:46:19 +0000 "Keane, Erich via llvm-dev" <llvm-dev at lists.llvm.org> wrote: > If the name of our branch causes anxiety/difficulty for a significant > portion of our population, it is literally the least we can do to > choose a word that better respects the last few centuries of world > history. Honestly, if the name of a branch causes

Hi all, I am trying to get a handle on gls (package nlme). I have a toy problem: 3 fixed factors (A, B, C), two levels each, 5 replicates per treatment. The response variable is continuous, normal. I have a correlation matrix of the form: > mat A B C A 1.00 0.75 0 B 0.75 1.00 0 C 0.00 0.00 1 which is common to all observations. How do I construct the call to gls? I think I need to

Could anyone please explain how to set up contrasts between means in R. I want to know if "before I conduct an experiment and believe the mean for 1 and 2 will be different from means 3 and 4, Is this true?" That is what I have to prove or disprove, I thought that contrasts would be the way to go. Thanks for the help. Igor [[alternative HTML version deleted]]

I am being barraged with Ruby, Rails and Rich Internet application work right now. Almost enough that I could quit the day job and make a go of it, forgetting about Java altogether. Places in the greater Miami area are turning on to Rails and Ruby -- much of it fueled by the stronger voices in the local Java community. Am I alone in this, or do many of you see absolutely explosive growth in Ruby,

Hello All, I am developing a JRuby on Rails 3 application. Standard stuff. I am facing problems getting autotest to run. Here''s the trace: % autotest loading autotest/rails_rspec2 bundle exec /Users/manish/Foo/Foo-Server/jruby-1.5.2/lib/ruby/gems/1.8/gems/rspec-core-2.0.0.beta.22/bin/rspec

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Hello, I''ve completed the update of all my servers to the new mongrel. No problems whatsoever to report, well done. But, I have some colleagues who are wondering what the primary improvements are to mongrel with this new release. I read the Change log but it was a bit cryptic for me. Can anyone provide an executive summary of why 1.0.1 is better than 0.3.xx? a few main bullet

Dear all, I am looking at habituation of dogs trotting on a treadmill. I record the ground reaction force and I analyze it with several discrete variables (maximum, minimum,...) For each variable, I get between 40 and 50 data per sample. I record data at time 1 min, 2 min, and 4 min a day, and I have 4 days of measurement (one day a week). That means I have 12 samples : Day1_Min1, Day1_Min2,

Hello, My name is Rodrigo, I am using R program and I have a trouble. I am trying to do a dendrogram with genetics information. Let me explain... The Similarity Matrix was already did, and with this matrix I want to construct a dendrogram. So, the distance is done. I need to transform this matrix (that I have) in a dendrogram, I woud be very grateful if someone could help me. PS: I am sending