similar to: Basic pagination question

I''ve created a class method in my model called find_filtered. The intent is that I take various params that the user has submitted, and let the model build the query and return the AR collection, which is exactly what happens. However, now I''d like to paginate the recordset. Everything I''ve been able to find about pagination presumes that you have no pre-existing AR

I''m struggling with the issue of pagination and many to many relationships. I have products and categories (a many to many relationship.) When I go to a category page, I wish to load all products associated with that category and have pagination of the products. @category_products = @category.products gives me all the products associated with the category however, when I try to

Hi there everyone, I''ve recently moved to RoR and am still struggling with the basics of what used to be second nature in php, so on with my question: I have a database with products, and I need to create a search form that paginates the results. What I have so far in my controller is: def list # If the values are nil, then set them, otherwise wrap them in % # Also,

Hi, Why can''t I use a variable to specify the :per_page attribute when using the most basic form of pagination? (if I use a hardcode number, it runs) What did I do? Thx. My code: def list_orders page_size = 20 ... order_pages, @orders = paginate(:orders, :per_page => page_size) end My Errors: undefined method `>'' for false:FalseClass RAILS_ROOT:

I am having this problem with pagination query in my controller class. I am using SQL server and following code to create pagination fails, complains about column name ''program_name'' (which is valid column/attribute of program) The error message is: DBI::DatabaseError: S0022 (207) [Microsoft][ODBC SQL Server Driver][SQL Server]Invalid column name

Can I do any "fancy" conditionals when using the Pagination helper? The problem is that I want to be able to specify a conditional based on the criteria of a parent object. Here''s an example: Object A has_many Object B''s I want to paginate through 100 B''s but I *only* want it to return the ones who''s A.flag = true I poked around through the Wiki

I have searched for days for an example that demonstrates what i would like to do, and this morning i thought i''d worked it out, but no....here''s what i have: Controller ========== class ProfilesController < ApplicationController def friends current_user.profile.friends end def list_friends @profile_pages, @profiles = paginate( friends, :per_page => 10) end end

Hello, maybe that I''m a stupid, but I don''t know how I can working with pagination. In all examples is written (for example) next: def user_list @user_pages, @users = paginate(:users, :order_by => ''name'') end So, it''s OK (as a scaffold) for all set of users. But I need a little other functionality. For example I need paginate only a little bit

I currently have a call to this action, which I''d like to paginate: def get_words @catid = params[:category] @words = Category.find(@catid).words render :partial => "word_display", :collection => @words end As you can see, a word_display partial is rendered for each word. If I add the pagination call (getting the links object), how can I then get

I am a Rails newbie and I am trying to build a test site in which users will have their own sets of data. I understand how to manipulate shared data very well. Most of the Rails examples out there seem to deal with such shared data. I am struggling with the "best practice" method for a user to work with their own data however (and not be able to view/edit other users''

hi everybody, i am new to rails.. plz clear my doubt... this is my question In my table(public_topics), i have 11 rows of data.. whenever i run the following view, it shows the entire rows in the current page.. and i have set the '':per_page'' option to ''2''.so it must show two data per page..but it shows all the rows in a single page..and this case continue

Hi Guys, I am trying to paginate the results from a search. When I use actual constants in the search conditions, it works fine: def query @k2_result_pages, @k2_results = paginate (:k2_results, :conditions => [''e_date >= ? AND e_date <= ?'', ''2006-07-12'', ''2006-08-12''],

Hi there, Is there a neat and easy way to implement pagination with letters rather than numbers eg : A B C D ... Z Rob

I have tried to use eager association with pagination, but the :include option is not supported: Here''s the one-line pagination call without :include @link_pages, @links = paginate :link, :per_page => 10, :order_by => sort_clause and here the work around, using the "classic" method # @link_pages = Paginator.new self, Link.count, 10,

Trying to create stuff without resorting to scaffold command. I have a list view in my login_controller.rb file... def list_users @user_pages, @users = paginate :users, :per_page => 14 end I have a command in my list_users.rhtml file which undoubtedly calls this pagination... <% odd_or_even = 0 for user in @users odd_or_even = 1 - odd_or_even %> and instead of being presented a

Hello all, I''m new to RoR but loving leanrning it and wish i''d found it earlier instead of spending so much time with PHP. I have a problem with a custom routing and pagination... In my application, users can save their favourite bookmarks, and can view each others favourites. I have set up rooting so they can do this easily by the URL www.mysite.com/username using the

I am trying to use pagination with the order option. I am following examples I''ve seen all over the web, but I am getting an error. My code seems simple: def list @upload_pages, @uploads = paginate :uploads, :per_page => 20, :order => ''id'' end Yet I keep getting this error: ___________________________________________

Hey there, Previous to finding ferret I had a test query setup to do pagination like: @listing_pages, @listings = paginate(:listing, :per_page => 10, :conditions => [" name LIKE ? ", "%" + search_criteria + "%"], :order_by => "name ASC") Can I do similar pagination with @results array returned from a ferret

Hi all, I am trying to use the pagination capabilities in a search tool that I have. A search view takes several parameters provided in text input and drop down boxes. Submitting the form causes a POST call to :action => ''search''. I generate some DB conditions based on the parameters and do a paginate. Everything gets shuttled off to the view again and things get rendered

How does one do pagination with link_to_remote calls so the pagination can be done with AJAX? For example, this obviously works out of the box with the standard scaffold: <%= link_to ''Next page'', { :page => @image_pages.current.next } if @image_pages.current.next %> to get users to the next page. The tutorial at: http://wiki.rubyonrails.com/rails/pages/How+to