similar to: edit.data() read-only?

Greetings All! As is often the case on this list, the answer may well be under my nose but I can't see it! I am looking for a "smart" way to do the following. Say I have a vector of values, X. I set up bins" for X, say with breaks at B = c(b1,b2,...,b11) covering the range of X, i.e. bins numbered 1:10. The value x is in bin i if B[i] < x <= B[i+1] What I seek is a

Greetings! For some reason I am not managing to work out how to do this (in principle) simple task! As a result of applying strsplit() to a vector of character strings, I have a long list L (N elements), where each element is a vector of two character strings, like: L[1] = c("A1","B1") L[2] = c("A2","B2") L[3] = c("A3","B3")

Greetings All. My apologies for a question whose answer is probably readily available somewhere (for some interpetation of "somewhere") ... Say I have just typed (from a sheet of paper) several lines into the R command-line, and what I see is: > chisq.test(matrix(c(3,6,3,4,4, + 4,1,4,6,5, + 2,7,4,2,5, + 8,2,4,4,2, +

Greetings All. I want to do the following simple thing. I have defined a function med3x3() such that, given vectors X,Y, med3x3(X,Y) returns a 3x3 table where: Row 1: X > median(X) Row 2: X = median(X) Row 3: X < median(X) Col 1: Y < median(Y) Col 2: Y = median(Y) Col 3: Y > median(Y) (with intersections of these conditions for the individual cells). I can easily define fixed

A quick question: Is there anywhere a listing of the RGB components of the named colours listed by colors()? For example, where would I find the RGB for "orange1" or "salmon"? When I look at an EPS file from R where I have used these colours, it seems that for: "salmon": 0.9804 0.5020 0.4471 rgb "orange1": 1 0.6471 0 rgb However, this is a tedious way

Hi Folks, [This is not unrelated to the current "vector of vectors" thread, but arises quite independently] Say I have a function f(x,y) which computes a value for scalar x and y; or, if either x=X or y=Y is a vector, a corresponding vector of values f(X,y) or f(x,Y) (with the usual built-in vectorisation of operations). Now I have X=(x.1,x.2,...,x.m) and Y=(y.1,y.2,...,y.n). I'm

Greetings All. Once again, I am probably missing something fairly accessible, but since I can't find it I'd welcome advice! I have a dataframe derived from a text file of data in tabular format. For one of the variables, say X, I want to select the subsets which in which X equals a particular value. Such values are given in the text file like: 2.3978953, and each such value will occurr

Greetings All. This is a somewhat generic query (I'm really asking on behalf of a friend who uses R on Windows, whereas I'm on Linux, but the same phenomenon appears on both). Say one has a largish dataframe -- call it "G" -- which in the case under discussion has 592 rows and 41 columns. The intention is to display the data by simply entering its name (G) as command. Say the

Greetings all! A recent news item got me thinking that a problem stated therein could provide a teasing little exercise in R programming. http://www.bbc.co.uk/news/uk-england-cambridgeshire-17680326 Cambridge University hosts first European 'maths Olympiad' for girls The first European girls-only "mathematical Olympiad" competition is being hosted by Cambridge

Greetings! I want to have the coefficients that R uses in shapiro.test() for the Shapiro-Wilk test for a prticular sample size, i.e. the a[i] in W = Sum(a[i]*x[i])/(Sum(x[i] - mean(x))^2) (where the x[i] are sorted). Two questions: Q1: Is there a readymade R function from which I can extract these? Q2: I was wondering if I might be able to modify the code for the function shapiro.test() so

No. But it has not been posted either. You got that message because you sent your message to the wrong address. You should have sent it to r-help at r-project.org You had probably sent it to r-help-request at r-project.org which would have had the effect that the server would have tried to interpret the contents of you message as commands (e.g. to unsubscribe, change your subscription

Hi folks, Suppose I have a series of cases each with categorical factors A, B. What is the best way to "glue" A and B together into a single factor? For example, given A0 B1 ... A1 B1 ... A0 B2 ... A1 B0 ... A0 B0 ... A1 B2 ... then I'd like to end up with a single factor with levels A0B0, A0B1, A0B2, A1B0, A1B1, A1B2 according to all the combinations which actually occur in

Hi, i'm using read.xls, and it counts more rows in my Excel than I really have. i've used both: especie26 <- read.xls("especie26cargar.xls") datos26 <- read.xls("especie26cargar.xls", header = TRUE, as.is = FALSE, na.strings = "NA", skip = 0, check.names = TRUE, fill = FALSE, strip.white = FALSE, blank.lines.skip = TRUE) when i

Hi Folks, The spreadsheet-like layout displayed when 'data.entry' is invoked is very useful simply for legible display of data, quite apart from its intended use for the purpose of entering or editing data. If one wants to use it _simply_ as a display device, so that one can look around inside a data-set while working on it, then it is not a good idea to have its _editing_ capabilities

Just to avoid possible confusion, let me correct a typo (at step [2] in the example below). Apologies! -----FW: <XFMail.111023084327.ted.harding at wlandres.net>----- Date: Sun, 23 Oct 2011 08:43:27 +0100 (BST) Sender: r-help-bounces at r-project.org From: (Ted Harding) <ted.harding at wlandres.net> To: r-help at r-project.org Subject: Re: [R] symmetric matrix multiplication On

Hi Ted, yes this was the problem. Thank you very much. best idaios On Wed, Jan 9, 2013 at 4:51 PM, Ted Harding <Ted.Harding@wlandres.net>wrote: > Ah! You have aqssigned a parameter "equal.var=TRUE", and "equal.var" > is not a listed paramater for t.test() -- see ?t.test : > > t.test(x, y = NULL, > alternative = c("two.sided",

Hi, I noticed the following fortune in R 2.7 and 2.6.2: fortune('Spreads') If anything, there should be a Law: Thou Shalt Not Even Think Of Producing A Graph That Looks Like Anything From A Spreadsheet. -- Ted Harding (in a discussion about producing graphics) R-help (August 2008) Just wondering, what function and library gave this detailed prediction? Cheers

The thread "R licensing query" currently running has raised the classic critcisms of using Excel for statistics. I was wondering: Has anyone applied the same or similar set of tests to OpenOffice "calc"? Or would the Executive Summary be: "Calc is just like Excel"? (Not that I'm a spreadsheet user, if I can avoid it; but I sometimes get asked about such

Dear R list, I have one very elementary question regrading correlation between two variables. x = c(44,46,46,47,45,43,45,44) y = c(44,43,41,41,46,48,44,43) > cov(x, y) [1] -2.428571 However, if I try to calculate the covariance using the formula as covariance = sum((x-mean(x))*(y-mean(y)))/8       # no of of paired obs. = 8 or     covariance = sum(x*y)/8-(mean(x)*mean(y)) gives

Hi Folks, I have a nasty data restructuring problem! I can think of one or two really clumsy ways of doing it with 'for' loops and the like, but I can't think of a *neat* way of doing it in R. The data are the Hadley Centre "Central England Temperature" series, daily from 01/01/1772 to 31/03/2007, and can be viewed/downloaded at