similar to: how to convert a data.frame to tree structure object such as dendrogram

I have two datasets: A with columns Open and Name (and many others, irrelevant to the merge) B with columns Time and Name (and many others, irrelevant to the merge) I want the dataset AB with all these columns Open from A - a difftime (time of day) Time from B - a difftime (time of day) Name (same in A & B) - a factor, does NOT index rows, i.e., there are _many_ rows in both A & B with

Hi, I created the model below, which returns me the following warning message: In sem.default(ram = ram, S = S, N = N, param.names = pars, var.names = vars, : Could not compute QR decomposition of Hessian. Optimization probably did not converge. ######### Model ######## mDPDF = data.frame(mj1,mj2,mj3,mj4,mj5,eL1,eL2,eL3,eL4,eL5,aC1,aC2,aC3,aC4,disR1,disR2,disR3,disR4,disR5,

Hello, This is Elaine. I am trying a path analysis using lavaan Package. There are three explanatory variables: X, Z, and M. The response variable is Y. A, b, and c have direct effects on Y. On the other hand, X and Z also have direct effects on M. In other words, X and Z have indirect effects on Y. I found the code example of lavaan package describes only one indirect effect as below. Please

Hi All I am having 2 very long character strings (550chars) and I want to put them as expressions together with c(). The problem is that I also get these double-quotes, as seen below in 'fct'. How can I remove these double-quotes? I tried as.name() but it did not work (because of size?). These are creating trouble with subsequent programs, which I tested with strings that for some

Hello, after thorough searching of the R help files as well as S+-help, I'm coming to the list: Is there a possibility to compute partial correlation coefficients between multiple variables (correlation between two paired samples with the "effects of all other variables partialled out")? All I seem to find are the standard Pearson correlation coefficients (with cor()) and no clue

Hi, > The patch in PR is wrong since it will make both darwin and windows > unhappy. I will comment on gentoo PR about possible proper solution. I'll give it a try as you comment on the gentoo PR. But my ppc box is in my office, so I'll post a result on next Monday (JST). Thanks,

Can someone recommend a good quality 24 or greater port channel bank? Steve -------------- next part -------------- An HTML attachment was scrubbed... URL: http://lists.digium.com/pipermail/asterisk-users/attachments/20070506/e5896021/attachment.htm

Hi, I'm working on the codes below however every time I run them when they get to OpenBUGS I keep getting the error message: array index is greater than array upper bound for hab. Any help would be greatly appreciated, Suzie Codes: ungulate <- read.csv(file.choose ()) #ungulate ungulate <- as.matrix(ungulate);colnames(ungulate)<-NULL;rownames(ungulate)<-NULL

Hi, >> The patch in PR is wrong since it will make both darwin and windows >> unhappy. I will comment on gentoo PR about possible proper solution. > > I'll give it a try as you comment on the gentoo PR. > But my ppc box is in my office, so I'll post a result on next Monday (JST). I posted my result on the gentoo PR. https://bugs.gentoo.org/show_bug.cgi?id=403519#c12

Dear R-Friends, Sorry to bother everyone with my earlier question: "Do we have similar R function to work like Minitab's INDICATOR?" I found the way to make things work: e.g., > x <- c(2,2,5,3,6,5,NA) > model.matrix(~ factor(x) - 1) factor(x)2 factor(x)3 factor(x)5 factor(x)6 1 1 0 0 0 2 1 0 0 0

Dear Friends: I like so much to work with R program. Congratulations for your work. I need R for work with multivariate data. My question is: With the pairs(X) command my output is a pairwise scatterplot symmetric matrix. Like: | X1 |X1 vs X2|X1 vs X3|X1 vs X4| |X2 vs X1| X2 |X2 vs X3|X2 vs X4| |X3 vs X1|X3 vs X2| X3 |X3 vs X4| |X4 vs X1|X4 vs X2|X4 vs X3| X4 | It is

Hello, I have a statistical problem that I am using R for, but I am not making sense of the results. I am trying to use multiple regression to explore which variables (weather conditions) have the greater effect on a local atmospheric variable. The data is taken from a database that has 20391 data points (Z1). A simplified version of the data I'm looking at is given below, but I have a

Hi I am using the following script to average a set of data 0f 62 columns into 31 colums. The data consists of values of ln(0.01) or -4.60517 instead of NA's. These need to be averaged for each row (i.e 2 values being averaged). What I would I need to change for me to meet the conditions: 1. If each run of the sample has a value, the average is given 2. If only one run of the sample has a

I've a vector of pairwise correlations in the order low-index element precedes the high-index element, say: corr(1,2)=0.1, corr(1,3)=0.2, corr(2,3)=0.3, corr(3,4)=0.4 How can I construct the corresponding correlation matrix? I tried using the "combn"-function in "combinat" package: library(combinat) combn(c(0.1,0.2,0.3,0.4),2) , but to no avail... Thank you for your

Adding llvm-dev as that might be a more suitable audience for this discussion. (& I know Lang's been playing around with the same problem in the Orc JIT, so adding him too) Is there any basis/reason to believe that the .X suffix is a better, more principled one than straight X? Is that documented somewhere as a thing the demangling tools will ignore? On Tue, Apr 14, 2015 at 12:06 PM,

Hello, Two lapply questions (system info and sample data below): 1) Why does the first form of command1 add the name of y _after_ the str() output rather than before as does the second (preferred) form? # command1 version1 invisible(lapply(ls(pattern='bn'), function(y) cat(y, "\n", str(get(y)), "\n") )) # command1 version2 (preferred output)

Good Morning, I am trying to create a new column of character strings based on the first two letters in a string in another column. I believe that I need to use some combination of ifelse and grep but I am not totally sure how to combine them. I am not totally sure why the command below isn't working. Obviously it isn't finding anything that matches my criteria but I am not sure why. Any

Full_Name: Marc Mamin Version: 1.8, 2.0.0 OS: Windows & Linux Submission from: (NULL) (217.17.202.254) Using only the beginning of a column name will match it: >aaa<-1 >df<-as.data.frame(aaa) >names(df) [1] "aaa" >df$a [1] 1 !!!!!!!!! (I expect df$a to be undefind) >df$x >NULL Compare with: > df["aaa"] aaa 1 1 > df["a"]

I have two tables and a join table for them e.g. books, authors in a many to many relationship (habtm) and a join table books_authors. I can successfully search for a book that has "author.id = 2 OR author.id = 4" but I am unable to search for "author.id = 2 AND author.id = 4" This is because the result of all the joins only has one author.id column so no single row has

Hi I wonder if there's a smarter way to do this procedure. I have a vector of filenames wher I only am interested in the first part of the filename. I would use the following method of extracting the first part. But is there a more simple way of doing this? Names <-