Displaying 20 results from an estimated 10000 matches similar to: "Multiple left hand side variables in a formula"
2016 Apr 14
4
Bug in by() function which works for some FUN argument and does not work for others
Dear Sirs,
I am Professor at Indira Gandhi Krishi Vishwavidyalaya, Raipur,
Chhattisgarh, India.
While taking classes, I found the *by() *function producing following error
when I use FUN=mean or median and some other functions, however,
FUN=summary works.
Given below is the output of the example I used on a built-in dataset
"mtcars", along with error message reproduced herewith:
>
2010 Dec 13
2
Does a formula object have a "left hand side"
Hello,
Does anyone know of a function that will determine whether
or not a formula object has a left hand side?
I.e., can differentiate between
y ~ x + z
and
~ x + z
Perhaps I'm overlooking the obvious...
Thanks!
2016 Apr 15
4
Bug in by() function which works for some FUN argument and does not work for others
Dear All,
Thanks for your help. However, I would like to draw your attention to the
following:
Actually, I was replicating the Example 2.3, using the dataset
"brainsize.txt" given in Section 2.3.3 ("Summarize by group") at page 55,
of a famous book "R by Example" written by "Jim Albert and Maria Rizzo"
published in Springers (2012) in a Use R! Series. The
2016 Apr 14
0
Bug in by() function which works for some FUN argument and does not work for others
I think you are not using the best function for what your intentions are.
Try:
> by(data=mtcars, INDICES=list(as.factor(mtcars$am)), FUN=colMeans)
: 0
mpg cyl disp hp drat wt
qsec vs
17.1473684 6.9473684 290.3789474 160.2631579 3.2863158 3.7688947
18.1831579 0.3684211
am gear carb
0.0000000
2020 Oct 18
2
Resultado de la consola como un tibble
Buen día
estimados
Estoy tratando de hacer un tibble con los resultados de un apply que se
muestran en la consola que me da R, no estoy seguro si eso se pueda hacer,
pero me gustaría organizar los resultados de esa manera.
mi código es:
data("mtcars")
Mtcars_matriz <- as.matrix(mtcars)
apply(Mtcars_matriz, MARGIN =2, FUN = shapiro.test)
DF2 <- tibble(Variable = NA, W = NA, Pvalue =
2013 Apr 12
3
Why copying columns of a data.frame becomes numeric?
Dear list,
I want the 1st, 2nd, 5th, and 6th columns of mtcars. After copying them,
the columns become numeric class rather than data frame.
But, when I copy rows, they data frame retains its class. Why is this? I
don't see why copying rows vs columns is so different.
> class(mtcars)
[1] "data.frame"
> head(mtcars)
mpg cyl disp hp drat wt qsec vs
2010 Nov 06
1
Prettier axis labels when using log scales in Lattice
Hello,
I am trying to alter the way in which lattice functions (specifically xyplot) print the axis labels when one uses the 'scales' parameter.
I can obtain the effect I want by using
scales=list(y=list(log=10, labels=expression(yvalues)))
where yvalues are the values that would have been printed as the y-axis labels if the "labels" argument had not been present. To help
2012 Jul 10
3
fill 0-row data.frame with 1 line of NAs
Dear all
Is there a simpler method to achieve the following: When I obtain an
empty data.frame after subsetting, I need for it to contain one line
of NAs. Here's a dummy example:
> (.xb <- iris[ iris$Species=='zz', ])
[1] Sepal.Length Sepal.Width Petal.Length Petal.Width Species
<0 rows> (or 0-length row.names)
> dim(.xb)
[1] 0 5
> (.xa <-
2012 Nov 04
1
Apply same linear model to subset of dataframe
I have applied the same linear model to several different subsets of a
dataset. I recently read that in R, code should never be repeated. I feel my
code as it currently stands has a lot of repetition, which could be
condensed into fewer lines. I will use the mtcars dataset to replicate what
I have done. My question is: how can I use fewer lines of code (for example
using a for loop, a function or
2020 Oct 18
1
Resultado de la consola como un tibble
Hola,
Bueno, puedes hacer el cálculo de una forma mucho más compacta y rápida.
Esta forma es especialmente recomendable cuando tienes muchas columnas y
muchas filas.
> library(data.table)
> myDT <- as.data.table(mtcars)
> myDTlong <- melt(myDT, measure.vars=1:ncol(myDT))
> myDTlong[ , list(p_value = shapiro.test(value)$p.value, v_stat =
shapiro.test(value)$statistic) , by
2016 Apr 16
2
Bug in by() function which works for some FUN argument and does not work for others
Dear All,
I have got your core message, that it is my responsibility to determine
whether any particular function in my version of R satisfies the language
requirements at the time of your use. Jim Albert and Maria Rizzo must have
used their code, which was permitted in the R-code of their time (2012).
Therefore, I have now modified my R-code, as per R-3..2.4 version,
according to my requirement
2007 May 12
2
Implicit vs explicit printing and the call stack
Hi everyone,
I've run into a bit of strange problem with implicit vs explicit
printing and the call stack. I've included an example at the bottom of
this email. The basic problem is that I have an S3 object with a
print method. When the object is implicitly printed (ie. typed
directly into the console) the function arguments in the call stack
are exploded out to their actual values,
2016 Apr 15
0
Bug in by() function which works for some FUN argument and does not work for others
> On Apr 15, 2016, at 1:16 AM, Akhilesh Singh <akhileshsingh.igkv at gmail.com> wrote:
>
> Dear All,
>
> Thanks for your help. However, I would like to draw your attention to the
> following:
>
> Actually, I was replicating the Example 2.3, using the dataset
> "brainsize.txt" given in Section 2.3.3 ("Summarize by group") at page 55,
> of a
2017 Aug 29
2
DBI::dbWriteTable syntax error apparently from quotes
I have been successfully using RODBC for a long time (years) to connect to
MS SQL Server from R.
This week I wanted to try using odbc but I am seeing some problems which
may be related to how I set up my driver and/or connection.
The dbWriteTable manual page gives as an example command:
dbWriteTable( pDB$con, "mtcars", mtcars[1:5,])
When I try this I get the following error
Error:
2011 Oct 03
4
Question about ggplot2 and stat_smooth
I'm interested in creating a graphic -like- this:
c <- ggplot(mtcars, aes(qsec, wt))
c + geom_point() + stat_smooth(fill="blue", colour="darkblue", size=2,
alpha = 0.2)
but I need to show 2 sets of bands (with different shading) using 5%,
25%, 75%, 95% limits that I specify and where the heavy blue line is the
median. I don't understand how to do this with
2009 Jul 23
2
param:qsec in ggplot2
Hii
i have been trying to do a scatter plot with ggplot2, like the plot 6 here
(http://had.co.nz/ggplot2/geom_point.html) .. where the points size vary
with values
> p + geom_point(aes <http://had.co.nz/ggplot2/aes.html>(size = qsec))
but am not sure how to setup the parameter - qsec
could anyone please give some pointers on how to define that
thanks
Mo.
[[alternative HTML
2016 Apr 17
0
Bug in by() function which works for some FUN argument and does not work for others
> On Apr 16, 2016, at 2:03 AM, Akhilesh Singh <akhileshsingh.igkv at gmail.com> wrote:
>
> Dear All,
>
> I have got your core message, that it is my responsibility to determine whether any particular function in my version of R satisfies the language requirements at the time of your use. Jim Albert and Maria Rizzo must have used their code, which was permitted in the R-code
2009 Aug 11
2
Varying x-axis labels in lattice
Dear Group:
I want to use lattice with a formula such as y ~ x | v to plot a data
frame in which v varies to indicate which "x" is really being plotted.
I know how to make the x-axis scales vary with the panel but is it
possible to let the x-axis label vary, i.e., to let the user specify a
vector of x-axis labels?
Thanks
Frank
--
Frank E Harrell Jr Professor and Chair
2006 Jul 14
1
Splitting the left and right hand terms of a formula
Let's say I have the following formula:
a.formula <- x ~ y + z
I want to extract the left and right-hand sides of the function so
that I have two character vectors like the ones you would create using
the following assignments:
left.hand.side <- "x"
right.hand.side <- c("y", "z")
One way to do this follows:
left.hand.side <-
2005 Dec 19
0
has_one mapping with arbitrary right and left hand side keys
I have two tables:
table_1:
tab1_id,
other_id
table_2:
id,
tab2_id,
something_else
I would like to specify a has_one mapping from table_1 to table_2 but
specifying that the join is based on (table_2.tab2_id =
table_1.other_id).
I am half way there with:
class Table1 < ActiveRecord::Base
set_table_name "table_1"
set_primary_key "tab1_id"
has_one :Table2, :class_name