similar to: issue creating a subset

Hi all, I have a data.frame I received with data that look like this (comma separated strings in last row): ID Shop Items ID1 A1 item1, item2, item3 ID2 A2 item4, item5 ID3 A1 item1, item3, item4 But I would like to unbind the strings in col(2) items so that it will look like this: ID Shop Items ID1 A1 item1 ID1 A1 item2 ID1 A1 item3 ID2 A2 item4 ID2 A2 item5 ID3 A1 item1 ID3 A1 item3 ID3 A1

Hi All, Apologies if this has been answered somewhere else, but I have been searching for an answer all day and not been able to find one. I am trying to plot a path diagram for a CFA I have run, I have installed Rgraphviz and run the following: pathDiagram(cfa, min.rank='item1, item2, item3, item4, item5, item6, item7, item8, item9, item10, item11, item12', max.rank='SMP,

Hello All, Eric Langley here with my first post to this list. I am looking to determine if R is suitable for a development project I am working on and if so possibly finding someone proficient in R that would be interested in doing the coding. I would like to preface my inquiry that while I am not a programmer I can communicate in a dialog my objectives. An array of rank ordered data looks like

I'm learning R and am converting some code from SPSS into R. My background is in SAS/SPSS so the vectorization is new to me and I'm trying to learn how to NOT use loops...or use them sparingly. I'm wondering what the most efficient to tackle a problem I'm working on is. Below is an example piece of code. Essentially what it does is set a variable to zero, loop through item

I need to wrap a loop inside a function and am having a small bit of difficulty getting the results I need. Below is a replicable example. # define functions pcm <- function(theta,d,score){ exp(rowSums(outer(theta,d[1:score],'-')))/ apply(exp(apply(outer(theta,d, '-'), 1, cumsum)), 2, sum) } foo <- function(theta,items, score){ like.mat <-

Folks, It has been a whole day spent on this but I still can''t get my mind around the most probably very stupid/basic mistake here... First, the code I use: <h3>List A</h3> <ul id="lista" > <li id="item1"> Item 1</li> <li id="item2"> Item 2</li> <li id="item3"> Item 3</li> </ul>

List: Thank you for the replies to my post yesterday. Gabor and Phil also gave useful replies on how to improve the function by relying on mapply rather than the explicit for loop. In general, I try and use the family of apply functions rather than the looping constructs such as for, while etc as a matter of practice. However, it seems the mapply function in this case is slower (in terms of CPU

I am teaching myself R for use in Psych research. I don't understand the error message I am getting or how to fix it. Any suggestions will be greatly appreciated df1=read.table("fastfood.txt", header=TRUE); df1 > > c(t(as.matrix(df1))) > > r = c(t(as.matrix(df1))) # response data > > r > f=c("item1","item2", "item3") > k=3 >

Hello R folks. 1) The question that generated the data, which I call Qx: Which of the following 5 items have you performed in the past month? (multipe response) 2) How the data is coded in my current dataframe: The first item that a person selected is coded under a field called Qxfirst; the second selected under Qxsecond, etc. For the first Person, the NAs mean that that person only selected

Hi, I have a question about reformatting data. It looks like it should be simple, but I've been working at it for awhile now and it's about time I ask for help. My data look like this: ITEM VALUE STEP item1 A first item2 C first item2 D second item1 A second item3 A first item3 B second item3 A third I just want to transform

Dear R-users, I would like to construct a list of arguments for a function in a format function (list(item1=c("A","B"), item2=c("B","C")), item3=...): The individual vectors in the list are permutations of colnames of a dataframe. The trouble is that I am not able to handle escaping of parentheses correctly. I was trying the following: library(gregmisc)

Hello, I have two data frames. One is my dependent variable and the other is my independent variable. For each row I'd like to split the independent variable into fractiles (25 or more) and calculate the average value of the dependent variable. Then I would like to plot the average of the averages for each row for each fractile. If possible, I'd like to have the option to 1) define the

is there a method similar to php''s expload function in ruby. i have a database field that contains an array of items, when i output this field i notice the items are seperated by ''-'' e.g item1-item2-item3. how would i go about putting them back into an array in ruby. for example in PHP i would just do this: $field; // = item1-item2-item3 $field_as_array =

Hi, I have a class ''Menu'' with a method ''addItem''. The method (simplified) looks like this: addItem: function(itemId, text) { this.container.innerHTML += ''<div id="''+itemId+''">''+text+''</div>''; Event.observe(itemId, ''mouseover'',

Hi, I''m creating a list of ingredients on a page. When the user clicks the ''Add Ingredient'' button a record gets added to the db and the ingredient gets added to the page. On the page, each record is represented by a <div> with three <span>s inside. One of the <span>s has a link_to_remote to ''delete'' the ingredient. When the link

Hi I would like to transform a data frame like Subject Item Score Subject 1 Item 1 1 Subject 1 Item 2 0 Subject 1 Item 3 1 Subject 2 Item 1 1 Subject 2 Item 2 1 Subject 2 Item 3 0 .... *to * Subject Item1 Item2 Item3 .....Item N Subject1 1 0 1 Subject2 1 1 0 ........ SubjectP.. Apologize for the simple nature of my query but I am stuck.

Hello, I'm switching over from SAS to R and am having trouble merging data frames. The data frames have several columns with the same name, and each has a different number of rows. Some of the values are missing from cells with the same column names in each data frame. I had hoped that when I merged the dataframes, every column with the same name would be merged, with the value in a complete

I have constructed the function mml2 (below) based on the likelihood function described in the minimal latex I have pasted below for anyone who wants to look at it. This function finds parameter estimates for a basic Rasch (IRT) model. Using the function without the gradient, using either nlminb or optim returns the correct parameter estimates and, in the case of optim, the correct standard

I have a 96x34 array of Likert scale data (96 cases, 34 items) of ordered factors (strongly disagree, disagree, neutral, agree, strongly agree) that are coded numerically (1 through 5). I cannot seem to convert this array (in any class) into ordered vectors. I have all the cases as vectors of ordered factors, but any which way I reassemble those vectors loses the ordered factors and converts

All - Each time through a loop I create a new dataset, which I would like to append to a list object. Each item of the list should be the data matrix created in that step of the loop; I would like the NAME (or tag) of that list item to be assigned the value of a character string: I've tried something like this: running.list <- numeric(0) for(i in 1:num.files){ ..... running.list