similar to: Problems plotting and regression w.r.t. date data type on x axis

Hello, I have a long list of x-, y- and z-data and try to generate a heatmap. Obviously there are several data with identical x- and y-values. I get the following error message: Error in interp.old(x, y, z, xo = xo, yo = yo, ncp = 0, extrap = extrap, : duplicate data points: need to set 'duplicate = ..' Unfortunately there seems no help screen on "duplicate". I'd prefer

Sehr geehrte Damen und Herren, An der Fachhochschule Winterthur wurde f??r mich im Rahmen einer Diplomarbeit (Prof. Ruckstuhl) ein R-Programm zur Auswertung von IR-Spektren (line-shape-Analyse zur quantitativen Analyse von Gasmischungen) entwickelt. Die Daten werden einer Excel-Tabelle entnommen. Bisher werden die spektroskopischen Daten ??ber den Inhalt von 64 Kan??len ??ber die

Hi, I have a problem with the df. I read in a big csv file. Tabelle <- read.csv("C:\\Users\\Public\\Documents\\Bachelorarbeit\\eingabe8_durchnummeriert.csv" , header = T , sep=";") then I try this: > ygamma <- glm(Tabelle$sb_ek_ber ~1+ Tabelle$FAHRL_C + Tabelle$NUTZKREIS + Tabelle$schw_drittel_c   , family = Gamma) >  anova(ygamma, test="Chisq")

channel <- odbcConnectExcel("nuova tabella terapia occupazionale mod.xls") > ## list the spreadsheets > sqlTables(channel) TABLE_CAT TABLE_SCHEM TABLE_NAME 1 c:\\TABELLE DEFINITIVE\\nuova tabella terapia occupazionale mod <NA> 'emi tot 2006 OAI_60g TO FU1$' 2 c:\\TABELLE DEFINITIVE\\nuova

Hi, I have a problem with library (rpart) (and/or library(tree)). I use a data.frame with variables "pnV22" (observation: 1, 0 or yes, no) "JTemp" (mean temperature) "SNied" (summer rain) I used function "rpart" to build a model: library(rpart) attach(data.frame) result <- rpart(pnV22 ~ JTemp + SNied) I got the following tree: n=55518 (50

Dear List, I have a problem with RODBC on a Paradox-DB, sqlQuery, and special characters in table names. Unfortunately, some of the latter include the underscore <_>. And I am not able to change them. That's not a problem, when I quote the table name: > sqlQuery(channel2, 'SELECT * FROM "anmeldung-alt"') Btw, if I swap ' and " it does not work: >

Dear Everybody! I want to export data to LaTeX. As I want to employ the data as freely as possible I want to avoid the xtable-command and instead generate some List like \MyOwnPrettyCommand{Adam}{Auer}{17} \MyOwnPrettyCommand{Bertram}{Bauer}{14} \MyOwnPrettyCommand{Christoph}{Huber}{75} \MyOwnPrettyCommand{Damian}{Dorfer}{69} \MyOwnPrettyCommand{Emanuel}{Eder}{43} with \MyOwnPrittyCommand

To whom it may concern, I have a problem concerning the design of a histogram. How do I change the border widths of the bars of a histogram. The initial command is: hist (punkte,breaks=30, xlab="Punkte", ylab="H?ufigkeit", main="Histogramm", col= heat.colors(30), border= "red") I suspect that it has to do with the "lwd" command but can't

Hi, how can I import really big plain text data files (several GB) from an ERP-System (SAP-Tables) to R? The Header of these files are always similar, for example: Tabelle: T009 Angezeigte Felder: 7 von 7 Feststehende F??hrungsspalten: 2 Listbreite 0250 ---------------------------------------------------------------------- |X|MANDT|PERIV|XKALE|XJABH|ANZBP|ANZSP|LTEXT

salve a tutti, sentite, non riesco a capire i test automatizzati di Rails. Secondo il libro, il ciclo di vita di un test prevede che per ogni metodo ( che sarebbe in pratica un test da eseguire ) si verificano sempre 3 eventi: 1) la cancellazione di tutti i record della tabella in esame 2) il caricamento di tutti i dati di test elencati nel file di fixture della tabella ( ad esempio

Hi all, I'm having a little bit of trouble with some date conversions and am hoping someone can help me out. Thanks in advance. OK, I have two sources of data that provide date info in a csv file differently. I've attached a small zipped file with two text files that illustrate both. (Is it ok to send attachments to this list? Not sure. It's very small.) I need to be able to

Hi everybody, I am beginer in R and I need your precious help. I want to create a small function in R as in sas to retrieve date. I have a file with data that import in R. DATE PAYS nb_pays.ILI. 1 24/04/2009 usa 0 2 24/04/2009 usa 0 3 24/04/2009 Mexique 0 4 24/04/2009

Hello everybody, I have two datasets, observed and predicted. Since my observed dataset is not in regular intervals, I need to filter my predicted dataset based on the measurement date of my observed data. Here, is an example similar to what I have library(chron);library(zoo) DATE<- seq(as.Date("2009-01-01"), as.Date("2009-05-01"), by = 1) mydat<- rnorm(length(DATE),

Dear list, I have been struggling with this for some time now, and for the last hour I have been struggling to make a working example for the list. I hope someone out there have some experience with plotting longitudinal data that they will share. My data is some patient data with three different time stamps. First the patients are identified at different times (first time stamp). Second, they

I am trying to calculate the median of each row of a data frame where the data frame consist of columns of class Date. Below are my test data and best attempt at using apply. I didn't see a solution via Google or the Baron search site. I'd be grateful for any suggestions or solutions. I'm using R 2.0.0 on Mac OS X. Thank you, Stephen Weigand ### Test data date1 <- c(1000,

Hello all, Can somebody point me to references or provide some code on dealing with this date issue. Basically, I have two vectors of values that represent dates. I want to convert these values into a date format and subtract the differences to show elapsed time in days. More specifically, here is the example: Date1 Date2 032398 061585 032398 061585 111694 101994 111694

Hi, ?In the example you provided, it looks like the dates in Date2 happens first.? So, I changed it a bit.? DataA<- read.table(text=" ID,Status,Date1,Date2 ??? ??? ?????? 1,A,3-Feb-01,15-May-01 ??? ??? 1,B,15-May-01,16-May-01 ??? ??? 1,A,16-May-01,3-Sep-01 ??? ??? ??? ??? ??? 1,B,3-Sep-01,13-Sep-01 ??? ??? ??? ??? ??? 1,C,13-Sep-01,26-Feb-04 ??? ??? ??? ??? ???

Dear everybody! Please find attached a tiny R-program. It returns: [,1] [,2] [1,] 53.55 NA [2,] 53.55 NA [3,] 53.55 NA How can I manage the first column to show the second component not only of the first list in k??ste but of the second component of every list in k??ste respectively, such as to get the following array returned: [,1] [,2] [1,] 53.55 NA [2,] 53.87 NA [3,] 53.87

Full_Name: Alexander L. Belikoff Version: 2.8.1 OS: Ubuntu 9.04 (x86_64) Submission from: (NULL) (67.244.71.200) I'm trying to reshape the following data frame: ID DATE1 DATE2 VALUE_TYPE VALUE 'abcd1233' 2009-11-12 2009-12-23 'TYPE1' 123.45 ... VALUE_TYPE is a string and is a factor with only 2 values

I have following object : > date2 [,1] [,2] [1,] "apr" "1992" [2,] "aug" "1992" [3,] "dec" "1992" [4,] "feb" "1992" [5,] "jan" "1992" [6,] "jul" "1992" [7,] "jun" "1992" [8,] "mar" "1992" [9,] "may"