similar to: Merging data in arrays

Hi all, I am performing hundreds of kruskal wallis tests and trying to figure out how to create a file of the p.values I obtain. This is the code I use for the tests: A2<-kruskal.test(X2~treatment) A3<-kruskal.test(X3~treatment) A4<-kruskal.test(X4~treatment) A5<-kruskal.test(X5~treatment) A6<-kruskal.test(X6~treatment) A7<-kruskal.test(X7~treatment)

I would like to compare two data sets saved as text files (example below) to determine if both sets are identical(or if dat2 is missing information that is included in dat1) and if they are not identical list what information is different between the two sets(ie output "a1", "a3" as the differing information). The overall purpose would be to remove "a1" and

We have a wireless network that uses 802.1x authentication, in which domain joined computers use their machine credentials to connect. Windows machines do this automatically, and until recently Linux computers could join using wicd, wpa-supplicant, and a simple script that would retrieve the machine password with tdbdump. ( specifically tdbdump -k SECRETS/MACHINE_PASSWORD/DOMAIN

Dear friends Hope you all are fine. Suppose we have a list of arrays. a1=c(4,4,4,4,0,4,4,4,0,3,3,0,0,0,0,0); a1=array(a1,dim=c(4,4)); a2=c(4,4,4,4,0,4,4,4,0,3,3,0,0,0,0,0); a2=array(a2,dim=c(4,4)); a3=c(4,4,4,4,0,3,3,4,0,4,4,0,0,0,0,0); a3=array(a3,dim=c(4,4)); a4=c(4,4,4,4,4,0,3,3,3,3,0,4,4,4,0,0,0,0,0,0); a4=array(a4,dim=c(5,4)); a5=c(4,4,4,4,4,0,4,4,4,4,0,3,3,3,0,0,1,1,0,0);

Dear colleagues, I'd like to reshape a datafame in a long format to a wide format, but I do not quite get what I want. Here is an example of the data I've have (dat): sp <- c("a", "a", "a", "a", "b", "b", "b", "c", "d", "d", "d", "d") tr <- c("A",

I have a data set with four columns and need to make boxplots from them. Data is as follows: tank Tanks Total cons_hat 1 a a4 5.651017 5.59 2 a a5 5.017499 5.29 3 a a6 4.894238 4.69 4 c c4 3.986347 3.40 5 c c5 4.099442 3.58 6 c c6 4.150522 3.64 7 h h4 5.187792 6.32 8 h h5 6.713422 6.44 9 h h6 5.168555

I was working with the rmetrics portfolioBacktesting function and dug into the code to try to find why my formula with 113 items, i.e. A1 thru A113, was being truncated and I only get 85 items, not 113. Is it due to a string length limitation in R or is it a bug in the strsplit or gsub functions, or in my string? I'd very much appreciate any suggestions ============Input script:

Dear R friends, I know that this topic has been mulled over before, and that there is a substantial difference between the convergence criteria for JMP and those for R. I apologize that this is somwehat raking cold coals. Summary: A model/data combination achieves convergence in JMP, and survives a reasonably rigorous examination (sensible parameter estimates, well-behaved surface,

I have this typical problem of joining a number of vectors with similar names - a1, a2,..., a10 - which should be concatenated into one. Using c(a1,a2,a3,a4,a5,a6,a,a8,a9,a10) naturally works, but I would like to do it with less manual input. My attempts to use paste() gives a vector of the vector names, see below. The question is how to do the the concatenation? Any suggestions?

On Fri, Mar 7, 2014 at 2:33 AM, Vieri <rentorbuy at yahoo.com> wrote: > So I take it it's more of a DHCP hack in which: > 1- client boots and gets DHCP response from 10.215.144.7 with PXE syslinux info > 2- client loads pxelinux.0 menu and selects menu that chains to Altiris PXE menu except, instead of calling pxechain.com or pxechn.c32 with the Altiris server's IP address,

Hello, I have got the following problem: > setwd("C:/temp") > library(xlsReadWrite) > MyData <- read.xls(file="Mappe1.xls", colNames = TRUE,dateTimeAs = "isodatetime") > attach(MyData) > MyData name value times 1 A1 2 2006-05-12 2 A2 3 2006-05-16 3 A3 1 2006-05-12 4 A4 4 2006-05-12 5 A5 2

I'm trying to run the generalized least square approach for my 2-additive problem, unfortunately this error appeared. I have tried to figure out the error from the mailing list but couldn't find the solution. Any help is highly appreciated. This is my source code: >a1 <- c(76.18, 61.84, 60.4, 69.09) > a2 <- c(51.01, 50.39, 87.62, 52.03) > a3 <- c(80.08, 48.49, 90.86,

Hello I have a data set like below: plate.id well.id Group HYB rlt1 1 P1 A1 Control SKOV3hyb 0.190 2 P1 A2 Control SKOV3hyb 0.210 3 P1 A3 Control SKOV3hyb 0.205 4 P1 A4 Control SKOV3hyb 0.206 5 P1 A5 Control SKOV3hyb 0.184 385 P1 A1 ovca SKOV3hyb 0.184 386 P1 A2 ovca SKOV3hyb 0.229 387

Hello subscribers, I have a very strange question regarding SSL setup on gluster storage. I have create a common CA and sign certificate for my gluster nodes, placed host certificate, key and common CA certificate into /etc/ssl/, create a file called secure-access into /var/lib/glusterd/ Then, I start glusterd on all nodes, system work fine, I see with peer status all of my nodes. No problem.

Dear R user: I am studying the allele data of two populations. the following is the data: a1 a2 a3 a4 a5 a6 a7 a8 a9 a10 a11 a12 a13 a14 a15 a16 a17 pop1 0.0217 0.0000 0.0109 0.0435 0.0435 0.0000 0.0109 0.0543 0.1739 0.0761 0.1413 0.1522 0.1087 0.0870 0.0435 0.0217 0.0109 pop2 0.0213 0.0213 0.0000 0.0000 0.0000 0.0426 0.1702 0.2128 0.1596 0.1809 0.0957 0.0745 0.0106

How can I do something like this: <a id=a7 style="cursor: pointer;" onClick = "new Effect.Fade (''li''); Element.show(''a1'',''a2'',''a3'',''a5'',''a6''); onClick = "new Effect.Fade (''rp'');

Hello everyone! I have a data frame of 136 variables with 270 observations. I would like to create a new data frame such that each element of that data frame contains the maximum value of the 6 prior lags of the initial data frame. So for example, if my original data frame, A, were A1=c(7.72, 7.94, 7.56, 7.54, 0.93, 0.59, 7.21, 8.00, 7.19, 7.57)A2=c(4.27, 3.70, 3.80, 3.67, 3.83, 3.95, 4.02, 2.06,

Hello. I am wondering why I am getting NA for all in cors=sapply(pred,cor,y=resp). I suppose that each column in pred has NAs in them. Is there some way to fix this? Thanks > str(pred) 'data.frame':   200 obs. of  13 variables:  $ mnO2: num  9.8 8 11.4 4.8 9 13.1 10.3 10.6 3.4 9.9 ...  $ Cl  : num  60.8 57.8 40 77.4 55.4 ...  $ NO3 : num  6.24 1.29 5.33 2.3 10.42 ...  $ NH4 : num  578

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Hi, I want to encode Loongson ISA initially https://gist.github.com/xiangzhai/8ae6966e2f02a94e180dd16ff1cd60ac gslbx           $2,0($3,$4) It is equivalent to: dadd $1, $3, $4 lb $2,0($1) I just use  mem_simmptr  as the default value of  DAGOperand MO , because  MipsMemAsmOperand  use  parseMemOperand  to parse general  MemOffset  and only *one*  AnyRegister , for example: 0($1) But