similar to: The interpretation of lm(y~x)?

Displaying 20 results from an estimated 70 matches similar to: "The interpretation of lm(y~x)?"

2013 Feb 08
1
Contrasts for a data
Hi, I am using a data called Rail in the nlme package. The data contains two variables: Rail and Travel. >Rail Grouped Data: travel ~ 1 | Rail Rail travel 1 1 55 2 1 53 3 1 54 4 2 26 5 2 37 6 2 32 7 3 78 8 3 91 9 3 85 10 4 92 11 4 100 12 4 96 13 5 49 14 5 51 15 5 50 16 6 80
2006 Aug 03
1
how to use the EV AND condEV from BMA's results?
Dear friends, In R, the help of "bic.glm" tells the difference between postmean(the posterior mean of each coefficient from model averaging) and condpostmean(the posterior mean of each coefficient conditional on the variable being included in the model), But it's still unclear about the results explanations, and the artile of Rnews in 2005 on BMA still don't give more detail on
2005 Aug 08
1
chisq.test
Hi I am trying to use this function. Can anyone show me how I would input the following example? Chi-Squared = (40-30)^2 + (20-30)^2 + (30-30)^2 30 30 30 = 3.333 + 3.333 + 0 = 6.666 (p value = 0.036) I want to be able to use different denominators so can you show me how I can do it to accommodate these rather than assuming they are all the
2005 May 23
1
comparing glm models - lower AIC but insignificant coefficients
Hello, I am a new R user and I am trying to estimate some generalized linear models (glm). I am trying to compare a model with a gaussian distribution and an identity link function, and a poisson model with a log link function. My problem is that while the gaussian model has significantly lower (i.e. "better") AIC (Akaike Information Criterion) most of the coefficients are not
2008 Jan 12
2
glm expand model to more values
Hi I have the problem with fitting curve to data with lm and glm. When I use polynominal dependiency, fitted values from model are OK, but I cannot recive proper values when I use coefficents to caltulate this. Let me present simple example: I have simple data.frame: (dd) a: 1 2 3 4 5 6 b: 3 5 6 7 9 10 I try to fit it to model: model=glm(b~poly(a,3),data=dd) I have following data
2014 Aug 12
4
[LLVMdev] Explicit template instantiations in libc++
Most of libc++ doesn't have explicit template instantiations, which leads to a pretty significant build time and code size cost when using libc++, since a large number of common templates will be emitted by the compiler and coalesced by the linker. Notably, in include/__config, we have: #ifndef _LIBCPP_EXTERN_TEMPLATE #define _LIBCPP_EXTERN_TEMPLATE(...) #endif whereas before
2012 Nov 19
6
loop to subtract arrays / error
Hi everyone, I am having trouble with creating a loop to subtract arrays. In R, this is what I have done: > Vobsr <- read.csv("Observed_Flow.csv", header = TRUE, sep =",") # see data > below > Vsimr <- read.csv("1000Samples_Vsim.csv", header = TRUE, sep =",") # see > data below > Vobsr <- as.matrix(Vobsr[,-1]) # remove column 1 from
2012 Mar 20
2
Constraint Linear regression
Hi there, I am trying to use linear regression to solve the following equation - y <- c(0.2525, 0.3448, 0.2358, 0.3696, 0.2708, 0.1667, 0.2941, 0.2333, 0.1500, 0.3077, 0.3462, 0.1667, 0.2500, 0.3214, 0.1364) x2 <- c(0.368, 0.537, 0.379, 0.472, 0.401, 0.361, 0.644, 0.444, 0.440, 0.676, 0.679, 0.622, 0.450, 0.379, 0.620) x1 <- 1-x2 # equation lmFit <- lm(y ~ x1 + x2) lmFit Call:
2016 Jul 07
4
Help with nouveau driver
Is that an error that prevents anything from working? It's probably expected... On Thu, Jul 7, 2016 at 2:07 PM, abcd <abcdeluxe at web.de> wrote: > Thanks for the quick help! > > Indeed a kernel update resolved the issue, there one problem left > though: I get an error: > > Xorg.0.log: Couldn't load sub module "fb". > > I can't find out what
2007 Mar 29
1
ccf time units
Hi, I am using ccf but I could not figure out how to calculate the actual lag in number of periods from the returned results. The documentation for ccf says:"The lag is returned and plotted in units of time". What does "units of time" mean? For example: > x=ldeaths > x1=lag(ldeaths,1) > results=ccf(x,x1) > results Autocorrelations of series 'X', by lag
2016 Jul 08
0
Help with nouveau driver
Thanks for the help so far, I have already solved the main problem, but sadly it seems I can't find out the last step. I hope you can help me there... Here ist the important part: It is trying to load some nvidia module, although i have already done apt-get purge nvidia* [ 4.636] (II) LoadModule: "glx" [ 4.638] (II) Loading /usr/lib/xorg/modules/extensions/libglx.so [
2010 Jul 22
0
Please advise acf and pacf in order to determine order of Arima
I have data as below.Please let me know how the ACF and Pacf used to determine the order od arima model. Is there any rules need to be followed to determine order.Please advise > turkey.price.ts Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec 2001 1.58 1.75 1.63 1.45 1.56 2.07 1.81 1.74 1.54 1.45 0.57 1.15 2002 1.50 1.66 1.34 1.67 1.81 1.60 1.70 1.87 1.47 1.59 0.74 0.82
2007 Jan 30
0
lme : Error in y[revOrder] - Fitted : non-conformable arrays
Greetings R-helpers, I am attempting to fit an lme() while specifying a correlation structure, but I'm getting into trouble long before I get to that point. I am receiving the error: Error in y[revOrder] - Fitted : non-conformable arrays It doesn't seem to matter how simple or complex the model I specify is, it always gives this same error message. This makes me suspect something is
2016 Jul 08
1
Help with nouveau driver
Thanks for the help so far, I have already solved the main problem, but sadly it seems I can't find out the last step. I hope you can help me there... Here ist the important part: It is trying to load some nvidia module, although i have already done apt-get purge nvidia* [ 4.636] (II) LoadModule: "glx" [ 4.638] (II) Loading /usr/lib/xorg/modules/extensions/libglx.so [
2010 Jul 06
1
acf
Hi list, I have the following code to compute the acf of a time series acfresid <- acf(residfit), where residfit is the series when I type acfresid at the prompt the follwoing is displayed Autocorrelations of series ?residfit?, by lag 0.0000 0.0833 0.1667 0.2500 0.3333 0.4167 0.5000 0.5833 0.6667 0.7500 0.8333 1.000 -0.015 0.010 0.099 0.048 -0.014 -0.039 -0.019 0.040 0.018
2006 Sep 17
2
histogram frequency weighing
Fellow R-helpers, Suppose we create a histogram as follows (although it could be any vector with zeroes in it): R> lenh <- hist(iris$Sepal.Length, br=seq(4, 8, 0.05)) R> lenh$counts [1] 0 0 0 0 0 1 0 3 0 1 0 4 0 2 0 5 0 6 0 10 0 9 0 4 0 [26] 1 0 6 0 7 0 6 0 8 0 7 0 3 0 6 0 6 0 4 0 9 0 7 0 5 [51] 0 2 0 8 0 3 0 4 0 1 0 1 0 3
2006 Nov 23
2
random effect question and glm
consider p as random effect with 5 levels, what is difference between these two models? > p5.random.p <- lmer(Y ~p+(1|p),data=p5,family=binomial,control=list(usePQL=FALSE,msV=1)) > p5.random.p1 <- lmer(Y ~1+(1|p),data=p5,family=binomial,control=list(usePQL=FALSE,msV=1)) in addtion, I try these two models, it seems they are same. what is the difference between these two model. Is
2010 Oct 29
2
wilcox.test; data type conversion?
I'm working on a quick tutorial for my students, and was planning on using Mann-Whitney U as one of the tests. I have the following (fake) data grade <- c("MVG", "VG", "VG", "G", "MVG", "G", "VG", "G", "VG") sex <- c( "male", "male", "female", "male",
2005 Mar 10
2
Logistic regression goodness of fit tests
I was unsure of what suitable goodness-of-fit tests existed in R for logistic regression. After searching the R-help archive I found that using the Design models and resid, could be used to calculate this as follows: d <- datadist(mydataframe) options(datadist = 'd') fit <- lrm(response ~ predictor1 + predictor2..., data=mydataframe, x =T, y=T) resid(fit, 'gof'). I set up a
2001 Mar 10
3
Problem With Model.Tables Function
I am using R for the first time in one of my classes. My students have alerted me to a problem for which we have not found an answer. We find that some means returned by the model.tables function are not correct when missing data is present in analysis of variance problems. We have duplicated the problem using R 1.2.0, 1.2.1, and 1.2.2 under Windows 98 and several distributions of Linux (Redhat