Displaying 20 results from an estimated 20000 matches similar to: "Was confused with options(error = expression(NULL)) in example(stop)"
2012 Dec 06
2
factor(x, exclude=y) if x is a factor
I found this part in the documentation of 'factor'.
'factor(x, exclude=NULL)' applied to a factor is a no-operation
unless there are unused levels: in that case, a factor with the
reduced level set is returned. If 'exclude' is used it should
also be a factor with the same level set as 'x' or a set of codes
for the levels to be excluded.
2013 Jan 28
1
Suggestions for 'diff.default'
I have suggestions for function 'diff.default' in R.
Suggestion 1: If the input is matrix, always return matrix, even if empty.
What happens in R 2.15.2:
> rbind(1:2) # matrix
[,1] [,2]
[1,] 1 2
> diff(rbind(1:2)) # not matrix
integer(0)
> sessionInfo()
R version 2.15.2 (2012-10-26)
Platform: i386-w64-mingw32/i386 (32-bit)
locale:
[1] LC_COLLATE=English_United
2010 Jul 08
2
strsplit("dia ma", "\\b") splits characterwise
\b is word boundary.
But, unexpectedly, strsplit("dia ma", "\\b") splits character by character.
> strsplit("dia ma", "\\b")
[[1]]
[1] "d" "i" "a" " " "m" "a"
> strsplit("dia ma", "\\b", perl=TRUE)
[[1]]
[1] "d" "i" "a" " "
2016 May 30
1
factor(x, exclude=NULL) for factor x; names in as.factor(<integer>)
In R 3.3.0 (also in R 2.7.2), the documentation on 'factor', in "Details" section, has this statement.
'factor(x, exclude = NULL)' applied to a factor is a no-operation unless there are unused levels: in that case, a factor with the reduced level set is returned.
It is not true for a factor 'x' that has NA. In that case, if levels of 'x' doesn't
2018 Apr 29
2
Result of 'seq' doesn't use compact internal representation
> .Internal(inspect(1:10))
@300e4e8 13 INTSXP g0c0 [NAM(3)] 1 : 10 (compact)
> .Internal(inspect(seq(1,10)))
@3b6e1f8 13 INTSXP g0c4 [] (len=10, tl=0) 1,2,3,4,5,...
> system.time(1:1e7)
user system elapsed
0 0 0
> system.time(seq(1,1e7))
user system elapsed
0.05 0.00 0.04
It seems that result of function 'seq' doesn't use compact
2013 Apr 30
3
Subset of a 'table' divided by a 'table' is a 'table', but printed by 'print.default'
This is just info.
I recently got something like this.
> x <- factor(c("A","A","B","B"), levels=c("A","B"))
> y <- factor(c("a","b","a","b"), levels=c("a","b"))
> table(x, y)[, "a"] / table(x)
x
A B
0.5 0.5
attr(,"class")
[1]
2012 Sep 03
1
Typo (?) in 'aggregate.formula'
In the code for 'aggregate.formula', there is
if (as.character(formula[[2L]] == "."))
I believe that it is meant to be
if (as.character(formula[[2L]]) == ".")
However,
if (as.character(formula[[2L]] == "."))
gives the expected result.
Tracing:
- formula[[2L]] == "."
is equivalent to
as.character(formula[[2L]]) == "."
From the help page for
2018 Apr 29
1
Result of 'seq' doesn't use compact internal representation
Thanks -- I'll commit a fix after some testing.
Best,
luke
On 04/29/2018 06:22 AM, Duncan Murdoch wrote:
> On 28/04/2018 11:11 PM, Suharto Anggono Suharto Anggono via R-devel wrote:
>>> .Internal(inspect(1:10))
>> @300e4e8 13 INTSXP g0c0 [NAM(3)]? 1 : 10 (compact)
>>> .Internal(inspect(seq(1,10)))
>> @3b6e1f8 13 INTSXP g0c4 [] (len=10, tl=0) 1,2,3,4,5,...
2016 Sep 26
2
Undocumented 'use.names' argument to c()
By "an argument named 'use.names' is included for concatenation", I meant something like this, that someone might try.
> c(as.Date("2016-01-01"), use.names=FALSE)
use.names
"2016-01-01" "1970-01-01"
See, 'use.names' is in the output. That's precisely because 'c.Date' doesn't have 'use.names', so
2017 Nov 04
1
ans[nas] <- NA in 'ifelse' (was: ifelse() woes ... can we agree on a ifelse2() ?)
Removal of
ans[nas] <- NA
from the code of function 'ifelse' in R is not committed (yet). Why?
--------------------------------------------
On Mon, 28/11/16, Martin Maechler <maechler at stat.math.ethz.ch> wrote:
Subject: Re: [Rd] ifelse() woes ... can we agree on a ifelse2() ?
Cc: R-devel at r-project.org, maechler at stat.math.ethz.ch
Date: Monday, 28 November, 2016, 10:00
2017 Aug 19
1
Issues of R_pretty in src/appl/pretty.c
Yes, they work now.
I mentioned them partly because the commit description said overflow for large n and partly to be considered for regression tests.
--------------------------------------------
On Sat, 19/8/17, Martin Maechler <maechler at stat.math.ethz.ch> wrote:
Subject: Re: [Rd] Issues of R_pretty in src/appl/pretty.c
Cc: r-devel at r-project.org
Date: Saturday, 19 August, 2017,
2016 Aug 14
2
table(exclude = NULL) always includes NA
useNA <- if (missing(useNA) && !missing(exclude) && !(NA %in% exclude)) "ifany"
An example where it change 'table' result for non-factor input, from https://stat.ethz.ch/pipermail/r-help/2005-April/069053.html :
x <- c(1,2,3,3,NA)
table(as.integer(x), exclude=NaN)
I bring the example up, in case that the change in result is not intended.
2016 Aug 15
1
table(exclude = NULL) always includes NA
>>>>> Martin Maechler <maechler at stat.math.ethz.ch>
>>>>> on Mon, 15 Aug 2016 11:07:43 +0200 writes:
>>>>> Suharto Anggono Suharto Anggono <suharto_anggono at yahoo.com>
>>>>> on Sun, 14 Aug 2016 03:42:08 +0000 writes:
>> useNA <- if (missing(useNA) && !missing(exclude) && !(NA %in%
2018 Mar 24
1
Function 'factor' issues
I am trying once again.
By just changing
f <- match(xlevs[f], nlevs)
to
f <- match(xlevs, nlevs)[f]
, function 'factor' in R devel could be made more consistent and back-compatible. Why not picking it?
--------------------------------------------
On Sat, 25/11/17, Suharto Anggono Suharto Anggono <suharto_anggono at yahoo.com> wrote:
Subject: Re: [Rd] Function
2013 Jan 28
1
Minor issue in code of 'diffinv.vector' in R 2.15.2
In R 2.15.2 (and not before), in the definition of function 'diffinv.vector' in package stats, there is
difference <- as.integer(differences)
I believe
differences <- as.integer(differences)
is intended, because 'difference' is not referenced anywhere. However, without conversion of 'differences' to integer, 'diffinv.vector' in R 2.15.2 works OK.
Also,
2019 May 30
2
stopifnot
Here is a patch to function 'stopifnot' that adds 'evaluated' argument and makes 'exprs' argument in 'stopifnot' like 'exprs' argument in 'withAutoprint'.
--- stop.R 2019-05-30 14:01:15.282197286 +0000
+++ stop_new.R 2019-05-30 14:01:51.372187466 +0000
@@ -31,7 +31,7 @@
.Internal(stop(call., .makeMessage(..., domain = domain)))
}
2016 Sep 10
1
table(exclude = NULL) always includes NA
Looking at the code of function 'table' in R devel r71227, I see that the part "remove NA level if it was added only for excluded in factor(a, exclude=.)" is not quite right.
In
is.na(a) <- match(a0, c(exclude,NA), nomatch=0L) ,
I think that what is intended is
a[a0 %in% c(exclude,NA)] <- NA .
So, it should be
is.na(a) <- match(a0, c(exclude,NA),
2016 May 28
1
complex NA's match(), etc: not back-compatible change proposal
On 'factor', I meant the case where 'levels' is not specified, where 'unique' is called.
> factor(c(complex(real=NaN), complex(imaginary=NaN)))
[1] NaN+0i <NA>
Levels: NaN+0i
Look at <NA> in the result above. Yes, it happens in earlier versions of R, too.
On matching both NA and NaN, another consequence is that length(unique(.)) may depend on order.
2012 Nov 16
1
Help page on '$': 'warnPartialMatchAttr' should be 'warnPartialMatchDollar'
http://stackoverflow.com/questions/6065724/assigning-value-to-a-variable-that-has-a-dot-in-the-name made me realize this.
The context is 'a' is assigned to ret$log.id, but then ret$log returns "a" and ret$l also returns "a".
There is a comment from Charles on the question:
"Also see options(warnPartialMatchDollar=T) if you want to track these."
But, in
2017 May 18
2
stopifnot() does not stop at first non-TRUE argument
>From an example in http://www.uni-muenster.de/ZIV.BennoSueselbeck/s-html/helpfiles/nargs.html , number of arguments in '...' can be obtained by
(function(...)nargs())(...) .
I now realize that sys.call() doesn't expand '...' when the function is called with '...'. It just returns the call as is. If 'stopifnot' uses sys.call() instead of match.call() , the