similar to: prediction problem

We have a wireless network that uses 802.1x authentication, in which domain joined computers use their machine credentials to connect. Windows machines do this automatically, and until recently Linux computers could join using wicd, wpa-supplicant, and a simple script that would retrieve the machine password with tdbdump. ( specifically tdbdump -k SECRETS/MACHINE_PASSWORD/DOMAIN

Hello subscribers, I have a very strange question regarding SSL setup on gluster storage. I have create a common CA and sign certificate for my gluster nodes, placed host certificate, key and common CA certificate into /etc/ssl/, create a file called secure-access into /var/lib/glusterd/ Then, I start glusterd on all nodes, system work fine, I see with peer status all of my nodes. No problem.

Dear R experts, I am having difficulty using loops productively and would like to please ask for advice. I have a dataframe of ids and groups. I would like to break down the dataframe into groups, find the unique sets of ids, then reassemble. My thought was to use a loop, but I have been unable to finish this loop in a logical way. I would like to find the unique ids for group 1, group 2,

Sí, también... Para las permutaciones, n=r. Y con el parámetro "repeats.allowed" controlas si son con o sin repetción: #---------------------- > #Permutaciones *con repetición* > permutations(n=3, r=3, v=x, repeats.allowed=TRUE) [,1] [,2] [,3] [1,] "azul" "azul" "azul" [2,] "azul" "azul" "rojo" [3,]

Ya me extrañaba a mi! Mañana a primera hora miro todo lo que me comentas. Ahora estoy con ecuaciones no lineales y ya veo que hay que cargar librerias Muchas gracias. Un saludo El 23 de marzo de 2015, 0:08, Carlos Ortega <cof en qualityexcellence.es> escribió: > Hola, > > Por precisar un par de detalles: > > > - Con el paquete gtools se pueden generar: > - las

Hola amigos, muchas gracias por vuestra ayuda. Entonces veo que mi sorpresa era legítima. Por todos vuestros mails la conclusión es que: - En el módulo base de R no incluye combinatoria elemental, ni siquiera el número combinatorio Cm,n hay que cargar el paquete *combinat* - Y para las variaciones con repetición el paquete* gtools* - Y aún así no tenemos ni las combinaciones ni las

Hola Jorge, gracias por ayudarme antes de empezar. Ayer me fui a cama con tan solo escribir el título "Ecuaciones no lineales" Básicamente lo que voy a buscar es lo clásico, es decir, resolver cualquier ecuación no lineal, ya sea polinómica o trascendente, con una o varias incógnitas. Ejemplo típico: x^2 + y^2 = 1 y = sin x Si me van surgiendo dudas, aquí estaré, no lo dudéis. Por

Hola Miguel, Sí se pueden obtener las variaciones con y sin repetición en R. Eso sí están un poco escondidas... Se pueden calcular de esta forma: #---------------------- > #Cargar el paquete gtools > library(gtools) > #Definir el conjunto sobre el que se hará el cálculo > x <- c('rojo', 'azul', 'verde') > #Utilizar la función "permutations()"

Hi, I'm back on the list ;-) I seem to be having some trouble getting W2K machines to join the domain in 3.0.1rc2. I haven't looked at this in detail since 2.2.8a but it looks like the account gets created in LDAP and then it has trouble setting the password appropriately. I believe this is the relevant part of the log: api_rpcTNP: samr op 0x3a - api_rpcTNP: rpc command:

With llc, the size of the names section can vary widely depending on the value of -DLLVM_TARGETS_TO_BUILD. Enabling coverage shouldn't increase the name section size much. I only see one place where this happens, and it's relatively cold: http://lab.llvm.org:8080/coverage/coverage-reports/llvm/coverage/Users/buildslave/jenkins/sharedspace/clang-stage2-coverage-R at

i know this is not about R. After applying quantile regression with t=0.5,0.6 on the data set WBC( Wisconsin Breast Cancer)with 678 observations and 9 independent variables(inp1,inp2,...inp9) and 1 dependent variable(op) i have got the following results for beta values. when t=0.5(median regression) beta values b1=0.002641,b2=0.045746,b3=0.

Buenas, Tengo dos data.frame DF1 color numero verde 2 rojo 4 azul 3 y DF2 color verde verde verde rojo rojo azul Quieo que se añada en el segundo dataframe el contenido del DF1 .El ejemplo puesto est trivial y parece que se podria resolver fácilmente con un par de ifelse, pero en la realidad existen más de 4000 registros diferentes para el DF1. ¿Como puedo

Hi, I created the following example of a xyplot. The plot actually looks ok apart from that the x-axis is pretty squeezed/clinched. I tried aspect="fill" already but I want to have all 3 sub plots next to each other. I tried loads of different scaling varieties but with no significant result... library(lattice) N <- 6 d <-

Hi, You might need to check library(boot).? I have never used that before.? So, I can't comment much.? It is better to post on R-help list.? I had seen your postings on Nabble in the past.? Unfortunately those postings were not accepted in R-help.? You have to directly post at ? r-help at r-project.org after registering at: https://stat.ethz.ch/mailman/listinfo/r-help ?

I am fitting models to the responses to a questionnaire that has seven yes/no questions (Item). For each combination of Subject and Item, the variable Response is coded as 0 or 1. I want to include random effects for both Subject and Item. While I understand that the datasets are fairly small, and there are a lot of invariant subjects, I do not understand something that is happening

Hi, my data set is data.frame(id, yr, y, l, e, k). I would like to estimate Lee and Schmidts (1993, OUP) model in R. My colleague wrote SAS code as follows: ** procedures for creating dummy variables are omitted ** ** di# and dt# are dummy variables for industry and time ** data a2; merge a1 a2 a; by id yr; proc sysnlin maxit=100 outest=beta2; endogenous y; exogenous l e k

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On Fri, Aug 25, 2017 at 10:06:59PM +0000, James Zuelow via samba wrote: > We have a wireless network that uses 802.1x authentication, in which domain joined computers use their machine credentials to connect. > > > Windows machines do this automatically, and until recently Linux computers could join using wicd, wpa-supplicant, and a simple script that would retrieve the machine

Hi all, I'm using a certain  procedure to calculate the value of some variable(Bayes risk),B. So I got the values B1, B2, ........, B1000, each under certain input values and using a long procedure. Now, I want to put the values I got in a nummerical vector and find their minimum value. I think c( ) should work.For example if I have only 10 values I could have used

Hi, Using S=1000 and simdata <- replicate(S, generate(3000)) #If you want both "m1" and "m0" #here the missing values are 0 res1<-sapply(seq_len(ncol(simdata.psm1)),function(i) {x1<-merge(simdata.psm0[,i],simdata.psm1[,i],all=TRUE); x1[is.na(x1)]<-0; x1}) res1[,997:1000] #????? [,1]???????? [,2]???????? [,3]???????? [,4]??????? #x1??? Numeric,3000 Numeric,3000