similar to: Loop over several Variables, add on question

Hi all, I have 4 matrices, each having 5 columns and 4 rows .....denoted by B1,B2,B3,B4. I have generated a vector of 7 indices, say (1,2,4,3,2,3,1} which refers to the index of the matrices to be chosen and then appended one on the top of the next: like, in this case, I wish to have the following mega matrix: B1over B2 over B4 over B3 over B2 over B3 over B1. 1> How can I achieve this?

Dear all, Without a loop, I would like transform 3 numeric vectors empty of 0/1 of same length Vec1 : transform 1 to A and 0 to "" Vec2 : transform 1 to B and 0 to "" Vec3 : transform 1 to C and 0 to "" to obtain only 1 vector Vec who is the paste of the 3 vectors (Ex : ABC, BC, AC, AB,...) Any idea ? Thank you for your help -- Michel ARNAUD

Hello again, Let say I have following vector: set.seed(1) Vec <- sample(LETTERS[1:5], 10, replace = TRUE) Vec Now with each repeated letter, I like to add suffix programatically. Therefore I want to get following vector: c("B", "B1", "C", "E", "B2", "E1", "E2", "D", "D1", "A") Can somebody

Dear R developers, I am developing an R package which returns strings with new line codes. I am not sure if I should use "\r\n" or "\n" in my returned strings on Windows platforms. What is the recommended best practice for package developers (and code in base R) for coding new lines in strings? And just out of curiosity: What is the reason (or history) for preferring

Dear list member, I think that I have detected a strange behavior of the save() command: > year <- "2000" > assign(paste0("Var_", year), list(A=10, B=20)) > get(paste0("Var_", year)) $A [1] 10 $B [1] 20 # At this point all is ok, I have created a list of name Var_2000 > save(paste0("Var_", year), file=paste0("Var_", year,

On 2017-05-24, Duncan Murdoch wrote: > > I think the test is wrong because in the first case you are working in a > locale where that character is representable. In my locale it is not, so x1 > is converted to UTF-8, and everything compares equal. > > An explicit conversion of x1 to UTF-8 should fix this, i.e. replace > > x1 <- path.expand(paste0("~/",

I ''m having a problem identical to one encountered on this list awhile back: >I''m trying to configure dsmark qdisc on 2.6.11.4 user mode linux and >tc from iproute2-2.6.11-050314. > > >I think I have some mismatch in my setup since adding dsmark qdisc >fails *unless* I specify "set_tc_index" argument which I believe should >be optional:

Ni idea de eso; te lo agradezco. Seguramente lo voy a terminar usando bastante. Pregunto: ahí debería hacer todas las operaciones propias del sistema? No me encuentra el script, y se me hace raro. Capaz que pasa al sistema desde la carpeta en la que está el script de R, no desde el wd de R. Ahora me toca salir y después intentar probar y que funcione. Gracis de vuelta Hau idatzi du Marcelino De

Hola, amigos Se me acabo la sapienza. A ver: tengo un sript de Python script.py que neesita sus argumentos arg1 arg2 arg3, si desde la consola del sistema me pongo en la carpeta en la que lo tengo y hago: $ script.py arg1 arg arg3 Funciona perfecto. Pero desde R no lo consigo (entiendo que por no saber) Lo hago así (copio y pego): dir <- getwd() setwd('data/row/directoriocondatos/')

Hello again, Let say I have following vector: Vec <- c("0.0365780769", "(1.09738648244378)", "(0.812507787221523)", "0.5778069963", "(0.452456601362355)", "-1.8900812605", "-1.8716093762", "0.0055217041", "-0.4769192333", "-2.4133018880") Now I want to convert this vector to numeric vector. I

On 2017-05-24, Duncan Murdoch wrote: [...] > Okay, how about if we weaken the test? [...] > try > > stopifnot(path.expand(paste0("~/", filename)) == > paste0(path.expand("~/"), filename)) > Nope: > ## path.expand shouldn't translate to local encoding PR#17120 > filename <- "\U9b3c.R" > >

Hi all, I would like to use a loop for tasks that occurs repeatedly: # Groups # Umsatz <= 0: 1 (NICHT kaufend) # Umsatz > 0: 2 (kaufend) for (year in c("2011", "2012", "2013", "2014", "2015")) { paste0("Kunden$Kunde_real_", year) <- (paste0("Kunden$Umsatz_", year) <= 0) * 1 +

Hi, I am failing make check in r72721 at the end of reg-tests-1d.R. The relevant block of code is ## path.expand shouldn't translate to local encoding PR#17120 filename <- "\U9b3c.R" print(Encoding(filename)) x1 <- path.expand(paste0("~/", filename)) print(Encoding(x1)) x2 <- paste0(path.expand("~/"), filename) print(Encoding(x2)) stopifnot(identical(

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA512 Hi all, I wanted to set up my first (private) R-package and wondered if there was a function to prompt() for multiple aliases in one Rd-file, e.g. to create something like the normal distribution manual page encompassing rnorm, dnorm,... As I didn't find it, I modified prompt.default() and wrote a small function to do this job, called

The generic rule is that R is not a macro language, so looping of names of things gets awkward. It is usually easier to use compound objects like lists and iterate over them. E.g. datanames <- paste0("aa_", 2000:2007) datalist <- lapply(datanames, get) names(datalist) <- datanames col1 <- lapply(datalist, "[[", 1) colnum <- lapply(col1, as.numeric) (The 2nd

Hi R-users! Being new to R, and a fairly advanced Stata-user, I guess part of my problem is that my mindset (and probably my language as well) is wrong. Anyway, I have what I guess is a rather simple problem, that I now without success spent days trying to solve. I have a bunch of datasets imported from Stata that is labelled aa_2000 aa_2001 aa_2002, etc. Each dataset is imported as a matrix, and

Hi! Thanks for the replies! I understand people more accustomed to R doesn't like looping much, and that thinking about loops is something I do since I worked with Stata a lot. The syntax from Peter Dalgaard was really clever, and I learned a lot from it, even though it didn't solve my problem (I guess it wasn't very well explained). My problem was basically that I have a data matrix

Hi Jesus, You probably want: assign(paste0("model",i),lm(y~x,data=get(paste0("variable",i)))) Jim On Sat, Aug 5, 2017 at 7:01 PM, Jes?s Para Fern?ndez <j.para.fernandez at hotmail.com> wrote: > Hi there, > > > Imagine I want to use a variable created with assign,but automatically. I have an issue with that. What I do is: > > > #create in a loop the

I have an lapply function call that I want to parallelize. Below is a very simplified version of the code: url_base <- "https://cloud.r-project.org/src/contrib/" files <- c("A3_1.0.0.tar.gz", "ABC.RAP_0.9.0.tar.gz") res <- parallel::mclapply(files, function(s) download.file(paste0(url_base, s), s)) Instead of download a couple of files in parallel, I get a

Um, if you insist on doing it that way, at least use assign(varname, as.vector(get(varname))) -pd > On 4 Dec 2017, at 22:46 , Love Bohman <love.bohman at sociology.su.se> wrote: > > Hi! > Thanks for the replies! > I understand people more accustomed to R doesn't like looping much, and that thinking about loops is something I do since I worked with Stata a lot. The