similar to: Typo (?) in 'aggregate.formula'

I have suggestions for function 'diff.default' in R. Suggestion 1: If the input is matrix, always return matrix, even if empty. What happens in R 2.15.2: > rbind(1:2) # matrix [,1] [,2] [1,] 1 2 > diff(rbind(1:2)) # not matrix integer(0) > sessionInfo() R version 2.15.2 (2012-10-26) Platform: i386-w64-mingw32/i386 (32-bit) locale: [1] LC_COLLATE=English_United

I found this part in the documentation of 'factor'. 'factor(x, exclude=NULL)' applied to a factor is a no-operation unless there are unused levels: in that case, a factor with the reduced level set is returned. If 'exclude' is used it should also be a factor with the same level set as 'x' or a set of codes for the levels to be excluded.

\b is word boundary. But, unexpectedly, strsplit("dia ma", "\\b") splits character by character. > strsplit("dia ma", "\\b") [[1]] [1] "d" "i" "a" " " "m" "a" > strsplit("dia ma", "\\b", perl=TRUE) [[1]] [1] "d" "i" "a" " "

In example for function 'stop' in R, there is options(error = expression(NULL)) with comment # don't stop on stop(.) << Use with CARE! >> I was interested, wanted to know how "don't stop on stop(.)" was. So, I tried it. Typing example(stop) at the R prompt and pressing ENTER give this. > example(stop) stop> options(error = expression(NULL))

> .Internal(inspect(1:10)) @300e4e8 13 INTSXP g0c0 [NAM(3)] 1 : 10 (compact) > .Internal(inspect(seq(1,10))) @3b6e1f8 13 INTSXP g0c4 [] (len=10, tl=0) 1,2,3,4,5,... > system.time(1:1e7) user system elapsed 0 0 0 > system.time(seq(1,1e7)) user system elapsed 0.05 0.00 0.04 It seems that result of function 'seq' doesn't use compact

In R 3.3.0 (also in R 2.7.2), the documentation on 'factor', in "Details" section, has this statement. 'factor(x, exclude = NULL)' applied to a factor is a no-operation unless there are unused levels: in that case, a factor with the reduced level set is returned. It is not true for a factor 'x' that has NA. In that case, if levels of 'x' doesn't

This is just info. I recently got something like this. > x <- factor(c("A","A","B","B"), levels=c("A","B")) > y <- factor(c("a","b","a","b"), levels=c("a","b")) > table(x, y)[, "a"] / table(x) x A B 0.5 0.5 attr(,"class") [1]

Thanks -- I'll commit a fix after some testing. Best, luke On 04/29/2018 06:22 AM, Duncan Murdoch wrote: > On 28/04/2018 11:11 PM, Suharto Anggono Suharto Anggono via R-devel wrote: >>> .Internal(inspect(1:10)) >> @300e4e8 13 INTSXP g0c0 [NAM(3)]? 1 : 10 (compact) >>> .Internal(inspect(seq(1,10))) >> @3b6e1f8 13 INTSXP g0c4 [] (len=10, tl=0) 1,2,3,4,5,...

By "an argument named 'use.names' is included for concatenation", I meant something like this, that someone might try. > c(as.Date("2016-01-01"), use.names=FALSE) use.names "2016-01-01" "1970-01-01" See, 'use.names' is in the output. That's precisely because 'c.Date' doesn't have 'use.names', so

Removal of ans[nas] <- NA from the code of function 'ifelse' in R is not committed (yet). Why? -------------------------------------------- On Mon, 28/11/16, Martin Maechler <maechler at stat.math.ethz.ch> wrote: Subject: Re: [Rd] ifelse() woes ... can we agree on a ifelse2() ? Cc: R-devel at r-project.org, maechler at stat.math.ethz.ch Date: Monday, 28 November, 2016, 10:00

On 'factor', I meant the case where 'levels' is not specified, where 'unique' is called. > factor(c(complex(real=NaN), complex(imaginary=NaN))) [1] NaN+0i <NA> Levels: NaN+0i Look at <NA> in the result above. Yes, it happens in earlier versions of R, too. On matching both NA and NaN, another consequence is that length(unique(.)) may depend on order.

Yes, they work now. I mentioned them partly because the commit description said overflow for large n and partly to be considered for regression tests. -------------------------------------------- On Sat, 19/8/17, Martin Maechler <maechler at stat.math.ethz.ch> wrote: Subject: Re: [Rd] Issues of R_pretty in src/appl/pretty.c Cc: r-devel at r-project.org Date: Saturday, 19 August, 2017,

I am trying once again. By just changing f <- match(xlevs[f], nlevs) to f <- match(xlevs, nlevs)[f] , function 'factor' in R devel could be made more consistent and back-compatible. Why not picking it? -------------------------------------------- On Sat, 25/11/17, Suharto Anggono Suharto Anggono <suharto_anggono at yahoo.com> wrote: Subject: Re: [Rd] Function

Here is a patch to function 'stopifnot' that adds 'evaluated' argument and makes 'exprs' argument in 'stopifnot' like 'exprs' argument in 'withAutoprint'. --- stop.R 2019-05-30 14:01:15.282197286 +0000 +++ stop_new.R 2019-05-30 14:01:51.372187466 +0000 @@ -31,7 +31,7 @@ .Internal(stop(call., .makeMessage(..., domain = domain))) }

That, for example, complex(real=NaN) and complex(imaginary=NaN) are regarded as equal makes it possible that length(unique(as.character(x))) > length(unique(x)) (current code of function 'factor' doesn't expect it). Yes, an argument for the behavior is that NA and NaN are of one kind. On my system, using 32-bit R for Windows from binary from CRAN, the result of sapply(z, match,

useNA <- if (missing(useNA) && !missing(exclude) && !(NA %in% exclude)) "ifany" An example where it change 'table' result for non-factor input, from https://stat.ethz.ch/pipermail/r-help/2005-April/069053.html : x <- c(1,2,3,3,NA) table(as.integer(x), exclude=NaN) I bring the example up, in case that the change in result is not intended.

>>>>> Martin Maechler <maechler at stat.math.ethz.ch> >>>>> on Mon, 15 Aug 2016 11:07:43 +0200 writes: >>>>> Suharto Anggono Suharto Anggono <suharto_anggono at yahoo.com> >>>>> on Sun, 14 Aug 2016 03:42:08 +0000 writes: >> useNA <- if (missing(useNA) && !missing(exclude) && !(NA %in%

Another possible shortcut definition: assert <- function(exprs) do.call("stopifnot", list(exprs = substitute(exprs), local = parent.frame())) After thinking again, I propose to use ??? ? ? stop(simpleError(msg, call = if(p <- sys.parent()) sys.call(p))) - It seems that the call is the call of the frame where stopifnot(...) is evaluated. Because that is the correct context, I

In R 2.15.2 (and not before), in the definition of function 'diffinv.vector' in package stats, there is difference <- as.integer(differences) I believe differences <- as.integer(differences) is intended, because 'difference' is not referenced anywhere. However, without conversion of 'differences' to integer, 'diffinv.vector' in R 2.15.2 works OK. Also,

In R devel r72789, the added part in 'factor' documentation (factor.Rd) is the following. Undocumentedly for a long time, \code{factor(x)} loses all \code{\link{attributes}(x)} but \code{"names"}, and resets \code{"levels"} and \code{"class"}. In the code of function 'factor', names(x) is copied to the result. As I mentioned before, names(x) is _not_