Displaying 20 results from an estimated 5000 matches similar to: "Comparing factor level measurments"
2012 Jul 18
3
Subsetting problem data
Hello, I need to subset my data to only look at the parts that have "holes"
in it. I already have a formula to get rid of inconsistencies, but now I
need to look only at the problem data to reconfigure it. In my data set
where there are multiple "cycles" per "patient," and I want to highlight
the patients who have a variable was not measured every cycle.
Here's a
2012 Jun 06
3
Combine subsets by factor level
I'm attempting to change a data set by compressing rows into columns.
Currently there are several rows that all have information about one
"patient," but at different cycles. I'm trying to make each patient only
have one row in the data set.
Does anyone know a good way to combine data sets by factor level? I've
separated the groups into different subsets by cycle, but not
2005 Mar 28
2
Generating list of vector coordinates
Hi.
Can anyone suggest a simple way to obtain in R a list of vector
coordinates of the following form? The code below is Mathematica.
In[5]:=
Flatten[Table[{i,j,k},{i,3},{j,4},{k,5}], 2]
Out[5]=
{{1,1,1},{1,1,2},{1,1,3},{1,1,4},{1,1,5},{1,2,1},{1,2,2},{1,2,3},{1
,2,4},{1,2,
5},{1,3,1},{1,3,2},{1,3,3},{1,3,4},{1,3,5},{1,4,1},{1,4,2},{1,4,3},
{1,4,
2007 Sep 13
2
beginner's questions ... sorry
I have 316 files. Each file represents a patient's breathing track
(respiratory signal recorded for a variable number of cycles). All files
have the same are made up of a header followed by a variable number of
records.
Each record contains 7 comma separated fields.
The patient ID is recorder in the header which is stripped off when reading
the file into a R data.frame.
Since I need to keep
2010 Feb 06
1
duplicating records
Dear friends,
I need to fill in (duplicate the whole record) the missing days with the
same record values as long as AE is the same value (i.e. "1"), once AE
value changes, the process of duplication should proceed with the new AE
value till it changes again. e.g. I need to fill in records: day 18-day
44, all the records are carried with the new AE value of "0".
At the
2011 Mar 23
2
Estimating correlation in multiple measures data
Dear R-helpers,
This may sound simple to you, but I'm a beginner in this, so please be
forgiving.
I have a following problem: two analytes were measured in patient's
blood on 4 occasions: ProteinA and ProteinB. How to correctly evaluate
correlation between ProteinA and ProteinB?
I tried:
x <- data.frame(Patient.ID=rep(1:10, each=4), Visit=rep(c(1:4),10),
ProteinA=rnorm(m=10,
2007 Jan 07
2
different points and lines on the same plot
Dear all,
I have following data called "paitent"
day patient1 patient4 patient5 patient6
0 -0.27842688 -0.04080808 -0.41948398 -0.04508318
56 -0.22275425 -0.01767067 -0.30977249 -0.03168185
112 -0.08217659 -0.26209243 -0.29141451 -0.09876170
252 0.08044537 -0.26701769 0.05727087 -0.09663701
where each patient have response values at four time
points. I want to
2007 Jul 24
1
function optimization: reducing the computing time
Dear useRs,
I have written a function that implements a Bayesian method to
compare a patient's score on two tasks with that of a small control
group, as described in Crawford, J. and Garthwaite, P. (2007).
Comparison of a single case to a control or normative sample in
neuropsychology: Development of a bayesian approach. Cognitive
Neuropsychology, 24(4):343?372.
The function (see
2007 Jan 08
1
Boxplot issue
Dear R-users,
I have a data frame containing 2 colums: column 1 is
the patient numbers (totally 36 patients), column 2 is
patient's response values (each patient has 100
response values). If I produce a boxplot for each
patient on the same graph in order to compare them
against each other then the boxplots are very small.
How can I instead of creating one graph containing 36
boxplots,
2010 Feb 26
3
Preserving lists in a function
Dear R users,
A co-worker and I are writing a function to facilitate graph plotting in R. The function makes use of a lot of lists in its defaults.
However, we discovered that R does not necessarily preserve the defaults if we were to input them in the form of list() when initializing the function. For example, if you feed the function codes below into R:
myfunction=function(
list1=list
2012 Jan 02
4
Create variable with AND IF statement
Hello,
I'm using SPSS at work but really would like to switch to R. Right now I'm
trying to learn R in reproducing calculations I did with SPSS but am stuck
with something that is quite simple and comprehensible in SPSS-Syntax:
IF (variable1.fac = 0 AND variable2.num = 0) variable3=1.
IF (variable1.fac = 0 AND variable2.num >= 1) variable3=2.
IF (variable1.fac = 1 AND variable2.num =
2013 Apr 26
2
looking for a way to do appointment reminders
Hello,
My health care organization is looking for a way to do appointment
reminders. We currently have staff members who spend part of each day
manually calling patients to remind them of their upcoming appointments,
and we would like to automate this process.
Our electronic health record software would provide such information as
the patient's name, phone number, and day and time of
2009 Jul 30
3
What is the best method to produce means by categorical factors?
I am attempting to replicate some of my experience from SAS in R and assume
there are best methods for using a combination of summary(), subset, and
which() to produce a subset of mean values by categorical or ordinal
factors.
within sas I would write
proc means mean data=dataset;
class factor1 factor2
var variable1 variable2;
RUN;
producing an output with means for each variable by factor
2010 Jan 30
2
drawing a line that shifts from solid to broken
I am graphing longitudinal data from three time points. I'd like to draw a
solid line from point 1 to point 2, and then a dashed line from point 2 to
point 3. It works if I do it in two steps:
> first.vector <- c(mean(year1$variable1), mean(year2$variable1))
> second.vector <- c(NA, mean(year2$variable1), mean(year3$variable1))
> plot(first.vector, type="b",
2006 Jul 03
1
analogue of group option of SAS MIXED/random in R
Dear list,
I am trying to use lme to build the analogue of the following SAS MIXED
random specification:
random int+Variable1+Variable2 /subject = Subject group=Condition type=vc;
which gives a Condition-blocked heterogeneity in the random effects
variance-covariance matrix.
Needless to say, I have a hard time in specifying Condition-specific
heterogeneities in the variance-covariance
2009 Mar 24
2
Calculating percentage Missing value for variables using one object
Hi,
I have a dataset in which there are in all 250 variables and for each
variable the data is entered over the months.
I need to calculate the percentage of missing values for each variable over
each month and then plot a graph for that.
I am running the following code for doing the same
*ds <- read.csv(file="filepath", header=TRUE)
attach(ds)
may <-
2010 Feb 08
2
the hat ^ in regular expression
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Nom : non disponible
URL : <https://stat.ethz.ch/pipermail/r-help/attachments/20100208/52a6d080/attachment.pl>
2012 Jul 05
4
Exclude missing values on only 1 variable
Hello,
I have many hundred variables in my longitudinal dataset and lots of
missings. In order to plot data I need to remove missings.
If I do
> data <- na.omit(data)
that will reduce my dataset to 2% of its original size ;)
So I only need to listwise delete missings on 3 variables (the ones I am
plotting).
data$variable1 <-na.omit(data$variable1)
does not work.
Thank you
2011 Apr 07
3
Correlation Matrix
Listers,
I have a question regarding correlation matrices. It is fairly straight
forward to build a correlation matrix of an entire data frame. I simply use
the command cor(MyDataFrame). However, what I would like to do is construct
a smaller correlation matrix using just three of the variable out of my data
set.
When I run this:
cor(MyDataFrame$variable1,
2011 Apr 18
4
altering identity column
Hi there,
I have a huge dataframe containing 70,000 observations.
I have filtered this dataframe (let it's name be "transformed_dataframe") as I wanted to select only those observations which are greater than or equal to 60,001 regarding the very first identity column.
So I have a transformed dataframe now including 10,000 obeservations (from 60,001 - to 70,000) and if you send