similar to: set working directory to current source directory

Dear Deepayan and dear list, I notice a small inconsistency with the command completion of the R CMD check. --no-latex is deprecated sincs R 2.12.0 and defunct since 2.13.0 but the command line completion still suggests it: cb at cbdesktop:~/r-devel$ bin/R CMD check --no-<here I hit tab> --no-clean --no-examples --no-latex --no-vignettes --no-codoc --no-install

Dear Deepayan and dear list, I notice a small inconsistency with the command completion of the R CMD check. --no-latex is deprecated sincs R 2.12.0 and defunct since 2.13.0 but the command line completion still suggests it: cb at cbdesktop:~/r-devel$ bin/R CMD check --no-<here I hit tab> --no-clean --no-examples --no-latex --no-vignettes --no-codoc --no-install

Greetings. I'm teaching linear regression this semester and that means I write more functions for my regression support package "rockchalk". I'm at a point now were some fresh eyes would help, so if you are a student in a course on regression, please consider looking over my package overview document here: http://pj.freefaculty.org/R/rockchalk.pdf That tells how you can grab

In process of creating data package from an existing one. The current package has both raw data files and the associated RData objects created from them. Currently, the data subdirectory is 1.5Mb and the extdata is 5.4Mb. Never having created a data package before, how is this best done? Should the data package contain only the raw data, or the RData objects too (tightly coupled)? If the later,

Hi, I am Parthasarathy G , from IIT Maras ( India ). I am currently in third year of the undergraduate course. I would like to contribute to the R project. Can anyone guide me regarding this? Thanking you, Parthasarathy [[alternative HTML version deleted]]

Is there a 'proper' way of checking if cluster is active. For example, I create a cluster called .PBcluster > str(.PBcluster) List of 4 $ :List of 3 ..$ con :Classes 'sockconn', 'connection' atomic [1:1] 3 .. .. ..- attr(*, "conn_id")=<externalptr> ..$ host: chr "localhost" ..$ rank: int 1 ..- attr(*, "class")= chr

Dear all: I have a big data file of 60000 columns and 60000 rows like that: AA AC AA AA .......AT CC CC CT CT.......TC .......................... ......................... I want to transpose it and the output is a new like that AA CC ............ AC CC............ AA CT............. AA CT......... .................... .................... AT TC............. The keypoint is I can't read

I have packages where I know CRAN and other test platforms do not have all the resources to build the vignettes, for example, access to databases. Previously I think putting BuildVignettes: false in the DESCRIPTION file resolved this, by preventing CRAN checks from attempting to run the vignette code. (If it was not this, then there was some other magic I don't understand.) Now, when

Hi, all I would like to use R to perform k-means clustering on my data which included 33 samples measured with ~1000 variables. I have already used kmeans package for this analysis, and showed that there are 4 clusters in my data. However, it's really difficult to plot this cluster in 2-D format since the "huge" number of variables. One possible way is to project the

Hello! I am having an issue with the OrgMassSpecR package. I run my HPLC using a DAD detector. My raw data is exported form chemstation as a csv file. I then upload the csv into Rstudio no problem. Using the DrawChromatogram function, I get a nice chromatogram, and my retention time, peak area, and apex intensity values are given as well. The problem comes with the peak area value given. The

Dear R Developers, Recently filed (and dismissed ;) ) law suit by Astrolabe against tz database developers caused a lot of media-press and discussions and created some kind of precedence in the USA [3]. But also it imho showed that similar attacks might happen in the future, and possibly against data sets which are not that obviously "factual" thus after all might fall under copyright

Hi, I am currently analysis Raman spectroscopic data with the hyperSpec package. I consulted the documentation on this package and I found an example work-flow dedicated to Raman spectroscopy (see the address : http://hyperspec.r-forge.r-project.org/chondro.pdf) I am currently trying to remove outliers thanks to PCA just as they did in the documentation, but I get a message error I can't

Tom Roche Thu, 12 Jan 2012 11:56:25 -0500 >>> * I have access to the cluster [where I want to run R] configured >>> [in .ssh/config] such that I can `ssh t` from commandline. >>> 1 I can open an R file on the cluster with >>> `C-x C-f /t:/home/me/onlyOrigDN2.r` >>> from my laptop, and note the following >>> *Messages* >>> >

Hi all, What would be an efficient way to match rows of a matrix to a vector? ex: m<-matrix(1:9, nrow=3) m [,1] [,2] [,3] [1,] 1 4 7 [2,] 2 5 8 [3,] 3 6 9 ################################# which(m==c(2,5,8)) # I want this to return 2 ###################### Thanks, Sachin [[alternative HTML version deleted]]

Hi all, It seems like I cannot use normal 'if' for data frames. What would be the best way to do the following. if data$col1='high' data$col2='H' else if data$col1='Neutral' data$col2='N' else if data$col='low' data$col2='L' else #chuch a warning? Note that col2 was not an existing column and was newly assigned for this

I am using a similar dataset to the following: a= c("Fruits", "Adam","errorA", "steve", "errorS", "apples", 17.1,2.22, 3.2,1.1, "oranges", 3.1,2.55, 18.1,3.2 ) a_table=data.matrix(t(matrix(a,nrow=5))) I would like to plus minus every second column starting from errorA (using xtable/ hmisc) example output (ignoring

Hi all, I want to do the following: data<-data.frame(col1=c(1,2,3,4,5)) getcol2<-function(data){ data$col2[data$col1<=2]="L" } getcol2(data) Unfortunately in the above col2 does not appear in the final data. So how would you pass this by reference such that you would get it back? Thanks, Sachin [[alternative HTML version deleted]]

I am trying to develop a prognostic model using logistic regression. I built a full , approximate models with the use of penalization - design package. Also, I tried Chi-square criteria, step-down techniques. Used BS for model validation. The main purpose is to develop a predictive model for future patient population. One of the strong predictor pertains to the study design and would not

Hi all, I have a feeling the most efficient way to do the following is to use apply, but I'm still wrapping my head around the function. k=matrix(1:6,nrow=3) div=1:2 Questions is how do I get R to divide the first column by 1 (div[1]) and the second column by 2 (div[2]) k/div treats k as a vector and does the following (not what I want) >k/div [,1] [,2] [1,] 1 2 [2,]

Hi All, I have the following problem (read the commented bit below): a<-matrix(1:9,nrow=3) a [,1] [,2] [,3] [1,] 1 4 7 [2,] 2 5 8 [3,] 3 6 9 div<-1:3 apply(a,2,function(x)x/div) ##want to divide each column by div- instead each row is divided## [,1] [,2] [,3] [1,] 1 4.0 7 [2,] 1 2.5 4 [3,] 1 2.0 3