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I want to produce some boxplots (and qqnorm plots) for each of a series of groups. It is easy to produce the boxplots or qqplots by groups using either by() or tapply(), but the moment that I want unique labels for each boxplot, I seem to be stuck using a for loop to achieve the effect. For example: tapply(fstat$femur, fstat$race, boxplot) by(fstat$femur, fstat$race, boxplot) gives nicely

Hey, all. Got an SNOM 820 in the other day to kick the tires. As with many phones, provisioning it was a bit of a PITA. The biggest problem, as far as I could tell, was that their firmware just doesn't seem that stable, and is sometimes hard to get to. - I managed to corrupt the firmware twice; fortunately, instead of bricking the phone, there's a fairly easy-to-use "rescue

Hi AJ, Am 06.06.2016 um 10:14 schrieb A J Stiles: > But why not call an AGI script, have this check the caller ID against a MySQL > database and return a status -- blocked or not -- in a variable? Then you can > manage individual number blocking in a much cleaner, more extensible fashion. > > Feel free to ignore me if it sounds like I'm suggesting you walk all the way > to

On Tue, Mar 6, 2018 at 9:20 AM, Roman Popov <ripopov at gmail.com> wrote: > I wonder if abi::__cxa_demangle guarantees unambigous names? >>> >> >> No, it does not. >> > > Interesting. Can you give an example of type where it fails? > I can't construct one out of thin air, but i believe someone cited one to you on the gdb mailing list. It's

Hi C?line, Looks like you are looking for a statistical test between two sets of distributions, such as KS test, for example, generate histogram for each row in an identical way and run KS test. But if you are after simple difference you may use compare package ( https://cran.r-project.org/web/packages/compare/index.html). Best, -m PS: Data is already plural :) datas does not exist. On 12

Yes of course, I can share this short view of the datas. Here is the head() of data100, containing all the trees with a final value higher than 100?: CV11 CV12 CV13 CV14 CV15 CV21 CV22 CV23 CV24 CV25 CV26 CV31 CV32 CV33 CV41 CV42 CV43 CV44 CV51 CV52 IN11 IN12 IN13 1291 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1083 0 4 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 3919 0 0 0 0 0 0 0 0 0 0 0 2 0

Another tale of a forgotten CC, damn, so here it goes... -------- Original Message -------- Date: Thu, 28 Jul 2011 14:35:03 +0200 From: Chris <chris at s-4-u.net> To: Justin Finkelstein <justin at redwiredesign.com> Subject: Re: [Xapian-discuss] Writing a Quick Start Guide to Xapian Hey Xapian list, i (unfortunately) have to agree, that the current Xapian docs are

On Tue, Mar 6, 2018 at 9:49 AM Daniel Berlin <dberlin at dberlin.org> wrote: > On Tue, Mar 6, 2018 at 9:20 AM, Roman Popov <ripopov at gmail.com> wrote: > >> I wonder if abi::__cxa_demangle guarantees unambigous names? >>>> >>> >>> No, it does not. >>> >> >> Interesting. Can you give an example of type where it fails?

Google are holding a GSoC "Doc Camp" this year the week before the annual mentor summit - the dates for Doc Camp are 17-21 October, and the location is Google HQ in Mountain View, California, USA. A major part of this will be several Book Sprints for writing Quick Start guides for specific organisations taking part in GSoC. They're currently inviting proposals, and I'd like to

Hello group, For my PhD I'm working on a spatial sampling grid. I do have two data sets which I'd like to compare using cross-correlograms or cross-variograms. Is this an option in one of the R-packages? I've been searching the R-help archive and the available package-documentations, but I can't find how to do this. Thanks in advance, Ren?.

Dear all, I generated a Correlograms and used the panel.ellipse (confidence ellipse and smoothed line) option. Is there a way to get instead of the smoothed line the linear regression? Thanks, As hz -- View this message in context: http://r.789695.n4.nabble.com/Correlograms-and-linear-regression-tp2331071p2331071.html Sent from the R help mailing list archive at Nabble.com.

Hello, I have time series and need to draw simple and partial correlograms with associated Q-statistics (the same as in EViews). Can I do it in R? Thanks --------------------------------- [[alternate HTML version deleted]]

I would like to make a correlogram in which I also have a correlation matrix instead of one of the panels. Is that possible? -- View this message in context: http://r.789695.n4.nabble.com/Correlograms-tp4283245p4283245.html Sent from the R help mailing list archive at Nabble.com.

I'm trying to make correlograms using corrgram. See below for a simple example. #### library(corrgram) data(baseball) vars1 <- c("Assists","Atbat","Errors","Hits","Homer","logSal") vars2 <- c("Putouts","RBI","Runs","Walks","Years")

Dear colleagues, Where I can find tools for drawing correlograms (graphical representations of autocorrelation and partial autocorrelation functions)? Thank you, Max --- This message contains no viruses. Guaranteed by Kaspersky Anti-Virus. www.antivirus.lv

Hello, I am trying to plot a few correlograms on the same figure, with the function corrgram() from the package corrgram. However, the function does not seem to use the base graphic system, as setting out the multiple figure layout with, e.g., par(mfrow=c(2, 2,)) does not work. Does anybody know a workaround for this? Many thanks in advance for any advice best giuseppe -- Giuseppe Pagnoni,

> > I wonder if abi::__cxa_demangle guarantees unambigous names? >> > > No, it does not. > Interesting. Can you give an example of type where it fails? I'm currently working on hardware construction library for C++ (similar to Chisel (which is written in Scala)). And since C++ has no standardized reflection, I use DWARF as a source of reflection metadata. And in case of

Hi, I'm doing cross-correlation correlograms with the ncf package. I have four study sites ; four correlograms. I'd like to get the same y scale for the four of them... only, using "ylim=c(-1,1)" does not change the y scale never and I don't know why. I tried with plot() too. Is there another option to change the ylim in plots ? Example with only one correlog (all work

Perhaps a bit off-topic (I asked on the rescue list -- http://web.archiveorange.com/archive/v/OaDWVGdLhxWVWIEabz4F -- and was told to try here), but I am kinda shooting in the dark: I have been finding online scattered and vague info stating that this card can be made to work with a sparc solaris 10 box (http://old.nabble.com/eSATA-or-firewire-in-Solaris-Sparc-system-td27150246.html is the

Do you have a simplified example with a code? It is not clear to me what do you mean by tree but if you refer to tree data structure, maybe you could change the data structure to tree (https://cran.r-project.org/web/packages/data.tree/vignettes/data.tree.html) and try to write comparison of two tree objects. It might be easier that data.frame alone. On 12 September 2017 at 12:27, C?line L?scher