similar to: find date between two other dates

HI all, My I am trying to convert character date (mm/dd/yy) to YYYY-mm-dd date format in one of the columns of my data file. The first few lines of the data file looks like as follow head(Atest,10);dim(Atest) ddate 1 19/08/21 2 30/04/18 3 28/08/21 4 11/10/21 5 07/09/21 6 15/08/21 7 03/09/21 8 23/07/18 9 17/08/20 10 23/09/20 [1] 1270076 1 I am using the following

I am trying to calculate the median of each row of a data frame where the data frame consist of columns of class Date. Below are my test data and best attempt at using apply. I didn't see a solution via Google or the Baron search site. I'd be grateful for any suggestions or solutions. I'm using R 2.0.0 on Mac OS X. Thank you, Stephen Weigand ### Test data date1 <- c(1000,

On 2024-06-09 4:39 p.m., Val wrote: > HI all, > > My > I am trying to convert character date (mm/dd/yy) to YYYY-mm-dd date > format in one of the columns of my data file. > > The first few lines of the data file looks like as follow > > head(Atest,10);dim(Atest) > ddate > 1 19/08/21 > 2 30/04/18 Those aren't legal months in the first entry.

I would like to import only datas of my table where DATE>today-7days. But my datas in Oracle are 'dates' and in R are 'characters'. now_7<-format(Sys.time()-(7*60*60*24), "%Y-%m-%d 00:00:00") How to do? -- View this message in context: http://r.789695.n4.nabble.com/Compare-date-Oracle-with-Sys-time-tp4635624.html Sent from the R help mailing list archive at

I am attempting to join several dataframes that summarize sampling effort for different samples into one large data.frame/table. I have looked at the merge command, but have not been clever enough to figure out how to get it to do what I want. A simplified example of what I am trying to do: The dataframes I have look like this (they were generated using the table command) species1.effort

i have a data frame with 2 columns of dates. with str(dataframe) i have ensured myself that they were indeed formatted as dates. one column has NA's in it. the aim is now to make a third column that chooses date1 if it is a date, and choose date2 if it is a NA. i am trying df$date3=ifelse(is.na(df$date1), df$date2, df$date1). this leads to unexpected behaviour: the resulting column is

Hi All, I have an script in R which accepts user inputs for certain parameters, particularly dates, which the user inputs as character strings. eg: > date1 <- "2009-01-21" The script later parses the input via the as.Date function: > as.Date(date1) However, as.Date encounters an error when the string does not represent an actual date. eg: > date1 <-

Hi list, I'm sure the explanation must be laughably simple to the experts out there, but I just could figure it out. I have a simple data frame that looks like, >head(da.off) DDate OffP 1 2005-01-01 41.23 2 2005-01-02 44.86 3 2005-01-03 44.86 4 2005-01-04 43.01 5 2005-01-05 45.47 6 2005-01-06 48.62 where the first column DDate currently is character, and OffP is numeric. I want

Hi, I need to reshape my dataframe from a long format to a wide format. Unfortunately, I have a continuous date variable which gives me headaches. Consider the following example: > id=c("034","034","016","016","016","340","340") > date=as.Date(c("1997-09-28", "1997-10-06", "1997-11-04",

Dear all, I have a data similar to this: myframe<- data.frame (ID=c("Ernie", "Ernie","Ernie","Ernie"), Timestamp=c("24.09.2012 08:00", "24.09.2012 09:00", "24.09.2012 10:00", "25.09.2012 10:00"), Longitude=c("8.481","8.482","8.483","8.481"),

Hello all, Can somebody point me to references or provide some code on dealing with this date issue. Basically, I have two vectors of values that represent dates. I want to convert these values into a date format and subtract the differences to show elapsed time in days. More specifically, here is the example: Date1 Date2 032398 061585 032398 061585 111694 101994 111694

Hi Maria Rule 1 make sure your data is in the right format dat <- source("G:/1/savedat.txt") > dat $value Location Date Zn2 upper.zn lower.zn 1 upstream 2016-04-27 29.92477 55.59800 13.912207 2 spill 2016-04-27 12.84040 22.07006 6.964934 3 downstream 2016-04-27 22.49673 41.60901 11.739109 4 upstream 2016-06-28 23.98425 45.60219 10.690640 5

Dear all, Thank you very much for the help. ylim=c(-5, 80) worked.? Regarding the reproducible example, I used dput () and saved the file as txt. It is not the first time that I used this way and normally it works. Because when I try to attach a .csv file with the data, most of the time it doesn't go through.? I will know for the next time.? Many thanks. Regards,Maria ???? 2:11 ?.?.

Hi everybody, I am beginer in R and I need your precious help. I want to create a small function in R as in sas to retrieve date. I have a file with data that import in R. DATE PAYS nb_pays.ILI. 1 24/04/2009 usa 0 2 24/04/2009 usa 0 3 24/04/2009 Mexique 0 4 24/04/2009

Dear Maria The file you attached to your first e-mail did come through but I think some people on the list must have missed it. Michael On 12/09/2017 12:54, Maria Lathouri via R-help wrote: > Dear all, > Thank you very much for the help. ylim=c(-5, 80) worked. > Regarding the reproducible example, I used dput () and saved the file as txt. It is not the first time that I used this way

Hi all, I'm having a little bit of trouble with some date conversions and am hoping someone can help me out. Thanks in advance. OK, I have two sources of data that provide date info in a csv file differently. I've attached a small zipped file with two text files that illustrate both. (Is it ok to send attachments to this list? Not sure. It's very small.) I need to be able to

The zoo package as a merge function which merges a set of zoo objects result<-merge(zoo1,zoo2,...) Assume your zoo objects are already collected in a list # make a phony list to illustrate the situation. ( hat tip to david W for constructing a list in a loop) ddat <- as.list(rep("", 20)) ytd<-seq(3,14) for(i in 1:20) { + ddat[[i]] <- zoo(data,ytd ) + } ddat [[1]] 1 2

Hello, probably a newbie question, but i didnt find any information on plotting/regressing w.r.t. a date data type. My trials were unfruitful. Can anyone help ? Thanks in advance! Here is my interaction with R: > tabelle date number date2 1 2009-01-1 1673 2009-01-01 2 2009-12-1 2111 2009-12-01 3 2010-7-1 2487 2010-07-01 4 2013-2-1 4301 2013-02-01 > regression.punkte<-lm(tabelle$number

[answers inline] On 18 August 2017 at 20:08, Dagmar <Ramgad82 at gmx.net> wrote: > > myframe<- data.frame (ID=c("Ernie", "Ernie","Ernie","Ernie"), > Timestamp=c("24.09.2012 08:00", "24.09.2012 09:00", "24.09.2012 10:00", > "25.09.2012 10:00"),

Thank you for providing the example code... for the request of running it multiple times it would have helped if you could have confirmed that the example ran through without errors... there were a lot of mistakes in it. Look into using the reprex package to check your example next time. I don't do this kind of analysis... I really don't know what to expect from the functions. The