Displaying 20 results from an estimated 10000 matches similar to: "axis.Date language"
2006 Jan 27
3
substituting an object not found
Is there any function in R like
is.not.found(x, y)
meaning if you can't find object x, then use object
y??
Mikkel Grum
2010 Dec 28
4
batch file output
I run a batch file with the following command in Windows XP:
C:\R\R-2.12.1\bin\Rterm.exe --no-save --no-restore <C:\users\me\file.R> C:\users\me\file.out 2>&1
Is there any way to get only the output of R in file.out, without getting all the code from file.R too?
Any help greatly appreciated,
Mikkel
2007 Dec 30
3
Date formats
Is the following expected behaviour for a date used in
an ifelse function?
> date <- Sys.Date()
> date
[1] "2007-12-30"
> ifelse(TRUE, date-1, date)
[1] 13876
> ifelse(FALSE, date-1, date)
[1] 13877
> ifelse(TRUE, as.character(date-1), date)
[1] "2007-12-29"
> if (TRUE) {date}
[1] "2007-12-30"
It would seem more natural to me if a date produced
2006 Jan 02
1
"7:9, 12:14" in dataframe to c(7:9, 12:14)
I want to do something like df[df$b %in% df2[i, 2], ]
where df$b is a numeric vector and df2[i, 2] is a
factor with
levels like "7:9, 12:14". For example:
a <- c(paste("A", 1:10, sep = ""), paste("B", 1:10,
sep = ""))
b <- 1:20
df <- as.data.frame(cbind(a, b))
df$b <- as.numeric(levels(df$b))[as.integer(df$b)]
f <-
2004 Dec 31
2
Supressing empty sections with Sweave
Dear useRs,
I'm writing regular survey reports using Sweave. Each
report has several sections along the lines of:
\section*{Disease X}
<<MapX,fig=TRUE,echo=FALSE>>=
image(vectorx,vectory,matrixz)
@
Notes with or without Sexpr{a}.
\vfill
\pagebreak
\section*{Disease Y}
<<MapY,fig=TRUE,echo=FALSE>>=
...etc.
Often one or more of the diseases is not observed (all
2007 Aug 07
2
backslash c
How do I get output with "\color{blue}", i.e. with
only one backslash???
> "\color{blue}"
[1] "color{blue}"
Warning messages:
1: '\c' is an unrecognized escape in a character
string
2: unrecognized escape removed from "\color{blue}"
> "\\color{blue}"
[1] "\\color{blue}"
>
Any help greatly appreciated.
Best regards,
2005 Jun 01
3
x[x$a=="q",,drop=TRUE]
I'm trying to select a subset of a dataframe while
dropping some factors. While the dataset gets smaller
all Factor levels remain and I need to get rid of
them. Strangely enough, I am almost certain that the
same code on the same data worked OK earlier today -
and it is not the first time that I'm not able to
replicate earlier results with this command (I know, I
might just be going
2002 Jan 08
6
Subsets without NA
Is there a way of removing all rows with missing values from a data frame?
I usually use
subset(x, var1!="NA")
and repeat for each variable. It would be nice to be able to do it in one
fell swoop. Also, surprisingly, it doesn't always work. Sometimes I'm left
with an empty set even though not all rows have missing values for the
variable.
Cheers,
mikkel
Mikkel Grum,
2001 Aug 13
3
subset syntax
Can anyone tell me what's wrong with this command??
xx<-subset(x,LOCAL.NAME==c("Chifumbata","Chikota"),select=c(13,16,19,23,26,2
9,30,33:48))
Warning message:
longer object length
is not a multiple of shorter object length in: LOCAL.NAME ==
c("Chifumbata", "Chikota")
both of the following commands work fine
2003 Sep 02
1
Plotting dates
I'm trying to plot observations against observation dates and getting julian
dates along the x-axis:
library(date)
Week<-as.date(c("05/02/03","05/09/03","05/16/03","05/23/03","05/30/03","06/0
7/03","06/14/03"))
Leafminers<-c(0,2,5,10,4,6,5)
Diglyphus<-c(0,0,4,5,7,3,1)
LeafDig<-cbind(Week,Leafminers,Diglyphus)
2017 Nov 14
1
Dates to numeric in for loop
Hi
Can anyone explain why a date becomes numeric when you loop over a series
of dates?
> dt <- Sys.Date()
> dt
[1] "2017-11-14"
> class(dt)
[1] "Date"
> dts <- dt - 1:0
> class(dts)
[1] "Date"
>
> for (i in dts) {
+ print(i)
+ print(class(i))
+ print(as.Date(i, "1970-01-01"))
+ print(class(as.Date(i,
2002 Jan 08
3
colour coding and different point types in a plot
I'm trying to plot four different sorghum types on a plot using a different
colour/symbol combination for each sorghum type (TYPBOTA in the script
below). What am I doing wrong?:
plot(xx$LATITUDE,xx$SFD1,
points(xx$SFD1,xx$LATITUDE,
col=1:4[codes(xx$TYPBOTA)],pch=c(4,3,1,2)[codes(xx$TYPBOTA)])
grid()
I get the following error message
Error in 1:4[codes(xx$TYPBOTA)] : NA/NaN argument
2007 Aug 17
2
Date format on x-axis
Dear R users,
Plotting question from a R beginner...
When I try to plot a response through time, for example:
>Date<-c("2006-08-17", "2006-08-18", "2006-08-19", "2006-08-20")
>response<-c(4,4,8,12)
>as.Date(Date)
>plot(Date,response)
The dates on the graphic appear in spanish. This I guess is the default
way of plotting because my
2003 Jan 07
2
Extracting means for given strata from dissimilarity object
Is there a way of extracting mean distance or dissimilarity for a given
strata from a 'dist' or 'dissimilarity' object, e.g. extract mean distances
for each species in Anderson's iris data?
data(iris)
iris.dist<-dist(iris[,1:4])
then what?
Mikkel Grum, PhD
Genetic Diversity Scientist
International Plant Genetic Resources Institute (IPGRI)
Sub-Saharan Africa Group
***
2007 Nov 24
2
truncated fields with RODBC
I'm changing some functions from storing data in
SQLite (using RSQLite) to storing it in PostgreSQL
(using RODBC). When trying to store very long
character fields I get the following message:
> sqlSave(pg, Grids, rownames = FALSE, append =
TRUE)
Warning messages:
1: In odbcUpdate(channel, query, mydata, paramdata,
test = test, verbose = verbose, :
character data truncated in column
2001 Aug 21
4
looking for a smarter way
I have two problems where I've come up with some code that will do the
analysis that I want, but it looks pretty clumsy. In the first case, I
calculate the variance on five different columns for each of 14 clusters and
get them into one matrix. I get the job done, but I would have thought that
it could be done in one or two lines, not six, and be generalized so that it
didn't matter how
2004 Dec 21
1
scheduling R tasks under windows
I'm trying to schedule R tasks in Windows Server 2003.
I can run the following from the DOS prompt without
any difficulty:
c:\Reports>c:\r\rw2001\bin\rterm.exe --no-restore
--no-save <test.R> test.out
where test.r has two lines: library(tools);
Sweave("rlr.Rnw").
When I try to run the same from the task scheduler, I
fill in the dialogue box as follows:
Run:
2006 Mar 15
3
"\r" with RSQLite
What am I doing wrong, or is the \r that I'm getting
in the example below a bug?
> a <- (1:10)
> b <- (LETTERS[1:10])
> df <- as.data.frame(cbind(a, b))
>
> df
a b
1 1 A
2 2 B
3 3 C
4 4 D
5 5 E
6 6 F
7 7 G
8 8 H
9 9 I
10 10 J
> library(RSQLite)
> drv <- dbDriver("SQLite")
> con <- dbConnect(drv, dbname = "Test")
2006 Mar 15
3
"\r" with RSQLite
What am I doing wrong, or is the \r that I'm getting
in the example below a bug?
> a <- (1:10)
> b <- (LETTERS[1:10])
> df <- as.data.frame(cbind(a, b))
>
> df
a b
1 1 A
2 2 B
3 3 C
4 4 D
5 5 E
6 6 F
7 7 G
8 8 H
9 9 I
10 10 J
> library(RSQLite)
> drv <- dbDriver("SQLite")
> con <- dbConnect(drv, dbname = "Test")
2010 Mar 18
5
language!!!
Hi,
there´s something that really bothers me about R and after hours and hours of internet research, I´m still stuck with the same problem: I installed R and it is in Spanish, as the system on my work. I would really like it in English and there seems to be no way to change that!?! I´m doing an abroad internship, so my Spanish is far from perfect and my tutorial is in English.
Is there any