similar to: CPU usage while running R code

Dear all I use a 64 bit Windows7 system with 16 GB memory. I have run an R script in batch mode with the following command: R CMD BATCH masterassignment_2012_11_09.r --save The execution was terminated with the following error message: Error in memory.size(size) : don't be silly!: your machine has a 4Gb address limit I never get this error message in an interactive session

Dear all I am trying to build a package, and get the error message: ""packaging into .tar.gz failed"". I have also installed the same package directly from a locally created zip file. In this case, the package is put correctly under C:\R\R-2.15.0\library. However, when I check the package, I get another error message, stating "ERROR: compilation failed for package".

Dear all I have written a function in C++ , equil_distC, that I am calling from an R script. In the last few days, R has repeatedly crashed when calling this function, or delivered obviously wrong outputs. However, when I restarted R after the crash, the results turned out to be OK most of the time although I had not modified the C++ code. Although the code runs correctly now, I am not sure

Dear all, I have problems loading a library in the 64 version of R. The following happens: · I have a file, equildistC.cpp, which contains a few lines of C++ code. · I have compiled the file using the following commands: PATH =

Dear all, I am encountering problems with the application of ddply within the body of a self-defined function. The script is the following: moncostcarmoto <- function(costtype){ costaux_result <- data.frame() for (purp in PURPcount){for (per in PERcount){ costcarin =

Dear all I have written a function, "calibrateCES", in which a function is called, "BPGC", which was written in the enclosure of "calibrateCES". Until the most recent version of my program, "calibrateCES" always used "BPGC" as planned. Following a modification which does not affect "BPGC" directly (although it does affect one of the

Dear all, in last weeks you discussed about R vs SAS. I want to ask your opinion about a comparison between R and SPSS. I don't know this software, but some weeks ago I went to a presentation of this product. I found it really user-friendly with GUI (even if I'd prefer command line) and very usefull and simple to use in creation and managing tables, OLAP tecniques, pivot table. What you

Dear Mr. or Ms.,   I would like to use the R-software to run the zero inflated mixed model and hurdle mixed model. But I do not know how to do? Would you please tell me the code and data format?   I will be very appreciated if you can help me. Thank you very much.   Best regards,   Sincerely, Xiongqing Zhang [[alternative HTML version deleted]]

Hi Since 2006, I used in my departement a Samba solutions based on NT4 style PDC, 2 BDCs and some files servers, desserving one hunderd persons. The backends for passwords and idd are a master and two slave openldap. Now i have to integrate a much larger organisation, an University Hospital, running with Windows AD. For political reasons, I should not maintain DCs anymore, but I will still

--- On Mon, 3/12/12, aleksandr shfets <a_shfets at mail.ru> wrote: > From: aleksandr shfets <a_shfets at mail.ru> > Subject: Fwd: Re[2]: [R] B-spline/smooth.basis derivative matrices > To: "Vassily Shvets" <shv736 at yahoo.com> > Received: Monday, March 12, 2012, 5:15 PM > > > > -------- ???????????? ????????? > -------- > ?? ????:

Sorry to keep asking elementary questions......I appreciate the help. I am trying to create a dotchart with the rows sorted according to the values, rather than the labels. When I try prof <- c('Accountant', 'Administrative assistant', 'Garment worker', 'Cook', 'Dentist', 'General practictioner', 'Graduate student', 'High level

dear all, This is a probably a silly question. If I type > grep("x",c("a.x" ,"b.x","a.xx"),value=TRUE) [1] "a.x" "b.x" "a.xx" Instead, I would like to obtain only "a.x" "b.x" How is it possible to get this result with grep()? many thanks for your attention, best, vito --

Dear R-users, I've built these functions usefell for me to import/export data from/to Excel: importa.da.excel<-function(){read.delim2("clipboard", dec=",") ## questa funzione consente di importare dati da Excel in R ## selezionare in Excel le celle che contengono i dati, ## compresi in nomi delle colonne ## Autore: Vito Ricci email:vito_ricci at yahoo.com ## Data di

dear all, Is the following intentional? Am I missing anything in documentation? d<-data.frame(y=rnorm(10,5,.5),exp=rnorm(10), age=rnorm(10)) formula(lm(exp(y)~exp+age, data=d)) #--> exp(y) ~ exp + age formula(lm(exp(y)~., data=d)) #--> exp(y) ~ age variable 'exp' (maybe indicating "experience") is not included in the model. The same happens with 'log' (and

Functions are first class objects, so some kind of collision is bound to happen if you do this... so don't. -- Sent from my phone. Please excuse my brevity. On January 30, 2018 3:11:56 AM PST, "Vito M. R. Muggeo" <vito.muggeo at unipa.it> wrote: >dear all, >Is the following intentional? Am I missing anything in documentation? >

For example: When I take a sample of 5 from 10 columns, I want to exclude from the sample column 1 from being chosen. How do I do this? -- View this message in context: http://r.789695.n4.nabble.com/Want-to-exclude-a-column-when-using-sample-function-tp2287988p2287988.html Sent from the R help mailing list archive at Nabble.com.

dear all, When I use all.vars(), I am interest in extracting only the variable names.. Here a simple example all.vars(as.formula(y~poly(x,k)+z)) returns [1] "y" "x" "k" "z" and I would like to obtain "y" "x" "z" Where is the trick? many thanks vito -- ==================================== Vito M.R. Muggeo Dip.to Sc

Dear UseRs, maybe is a silly question: how can I get Empirical CDF values from an object created with ecdf()?? Using print I obtain: Empirical CDF Call: ecdf(t) x[1:57] = 4.1, 4.4, 4.5, ..., 491.3, 671.27 Thanks in advance. Regards, Vito Diventare costruttori di soluzioni Became solutions' constructors "The business of the statistician is to catalyze the scientific

dear all, I am stuck on the following problem. Give a string like ss1<- "z:f(5, a=3, b=4, c='1:4', d=2)" or ss2<- "f(5, a=3, b=4, c=\"1:4\", d=2)*z" I would like to remove all entries within parentheses.. Namely, I aim to obtain respectively "z:f()" or "f()*z" I played with sub() and gsub() but without success.. Thank you very

Well... ?terms.formula says: "data: a data frame from which the meaning of the special symbol . can be inferred. It is unused if there is no . in the formula." So this seems to me to be an obscure bug, as I have found no warning against this admittedly confusing but still, I think, legal syntax. Note: > d <- data.frame(log = runif(10), x = 1:10) > y <- rnorm(10,5) >