similar to: memory leak (PR#5476)

Dear R-group members, I use: platform i386-pc-mingw32 arch x86 os Win32 system x86, Win32 status major 1 minor 4.1 year 2002 month 01 day 30 language R I try to fit a 2 compartment model. The compartments are open, connected to each other and

Jesus how do u post something, it always comes back :( -----Original Message----- From: Rend, Jon (Jon) % [mailto:rend@agere.com] Sent: Tuesday, October 29, 2002 8:05 AM To: 'samba@lists.samba.org' Subject: [Samba] (no subject) On friday we changed our smb.conf file to test the security model that uses DOMAIN authenticacion. It worked fine testing two seperate usernames from Multiple

David, If you are referring to the solution that would be: rapply(list(test), eval, envir = fenv) I thought I explained in the question that the above code does not work. It does not throw an error, but the behavior is no different (at least in the output or result). Using the above code still results in the x object not being stored in fenv on 3.1.2. Dayne On Wed, Jul 15, 2015 at 4:40 PM,

On Jul 15, 2015, at 12:51 PM, William Dunlap wrote: > I think rapply() was changed to act like lapply() in this respect. > When I looked at the source of the difference, it was that typeof() returned 'language' in 3.2.1, while it returned 'list' in the earlier version of R. The first check in rapply's code in both version was: if (typeof(object) != "list")

In 3.1.2 eval does not store the result of the bquote-generated call in the given environment. Interestingly, in 3.2.1 eval does store the result of the bquote-generated call in the given environment. In other words if I run the given example with eval rather than evalq, on 3.1.2 "x" is never stored in "fenv," but it is when I run the same code on 3.2.1. However, the given

Hi, I have a question about applying a function recursively through a list. Suppose I have a list where the different elements have different levels of recursion: > test.list<-list("I"=list("A"=c("a", "b", "c"), "B"=c("d", "e", "f"), "C"=c("g", "h", "i")), +

Is there a way to map NT names to UNIX names when they are not the same. 95% of our are which is great but we have a few that are different. For example, we have NT user "bigboy" who's Unix account is "smallboy", how can I make an association, oh learned 1's. Thanks, Jon :-) agere systems Office 651-675-3064* 1230 Northland DriveF Cell Phone

hi all members, please, i need you help... now a i´m working with veronoi polygons in a area with projections, but i need cut the polygons left. On other words, i need cut the polygons in the worked area. R help say that use the command voronoi.findrejectsites, but in this command i need put the numbers, any way...this command not cut!! do you can help me? Thank you for help me! José Bustos

for a simple example: x <- list() x[["a"]] <- list(a=c(1,2,3),b=c(3,4,5)) x[["b"]] <- list(a=c(6,7,8),b=c(9,10,11)) lapply(x,sum) this fails w/ Error in FUN(X[[1L]], ...) : invalid 'type' (list) of argument Just wondering if I have overlooked something obvious. one can also do: lapply(x,lapply,sum) but that assumes that you already know how many levels

I wrote a R script say called computeCovarMatrix.R and i want to call and run this piece from Excel visual basic. does anyone know how to do that? thanks, KZ [[alternative HTML version deleted]]

I have a modem in my system that comes up with this in lspci: 01:07.0 Communication controller: Agere Systems 56k WinModem (rev 01) What programs under CentOS, if any, can use this modem and how? Thanks. mhr -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://lists.centos.org/pipermail/centos/attachments/20070807/fbeb461b/attachment-0001.html>

Hello, I was building a R addin for Excel. I was able to build R.dll, export to Rdll.lib and wrap it in a Excel addin (.xll) format. Most basic functions work fine within Excel except functions that use LAPACK, e.g. eigen, solve etc. But if you use solve(..., LINPACK = T). That's fine. So apparently the problem is with loading the shared library ../modules/lapack.dll. I read one of the

Hi all, I was wondering whether it is possible to use the lapply() function to alter the value of the input, something in the spirit of : a1<-runif(100) a2<-function(i){ a1[i]<-a1[i-1]*a1[i];a1[i] } a3<-lapply(2:100,a2) Something akin to a for() loop, but using the lapply() infrastructure. I haven't been able to get rapply() to do this. The reason is that the "real"

A common process when data is obtained in an Excel spreadsheet is to save the spreadsheet as a .csv file then read it into R. Experienced users might have learned to be wary of dates (as I have) but possibly have not experienced what just happened to me. I thought I might just share it with r-help as a cautionary tale. I received an Excel file giving patient details. Each patient had an ID

I found the following strange behavior using qnorm() and pnorm(): > x<-8.21;x-qnorm(pnorm(x)) [1] 0.0004638484 > x<-8.22;x-qnorm(pnorm(x)) [1] 0.01046385 > x<-8.23;x-qnorm(pnorm(x)) [1] 0.02046385 > x<-8.24;x-qnorm(pnorm(x)) [1] 0.03046385 > x<-8.25;x-qnorm(pnorm(x)) [1] 0.04046385 > x<-8.26;x-qnorm(pnorm(x)) [1] 0.05046385 > x<-8.27;x-qnorm(pnorm(x))

dear all, here's a couple of questions that puzzled me in these last hours: ##### issue 1 qnorm(1-10e-100)!=qnorm(10e-100) qnorm(1-1e-10) == -qnorm(1e-10) # turns on to be FALSE. Ok I'm not a computer scientist but, # but I had a look at the R inferno so I write: all.equal(qnorm(1-1e-10) , -qnorm(1e-10)) # which turns TRUE, as one would expect, but all.equal(qnorm(1-1e-100) ,

Hi, This problems has bothered me for the lase couple of hours. > 1e-100==0 [1] FALSE > (1-1e-100)==1 [1] TRUE How can I tell R that 1-1e-100 does not equal to 1, actually, I found out that > (1-1e-16)==1 [1] FALSE > (1-1e-17)==1 [1] TRUE The reason I care about this is that I was try to use qnorm() in my code, for example, > qnorm(1e-100) [1] -21.27345 and if I want to

Assuming I have a firewire card with a supported chipset, is there anything special I need to do in order for the kernel to recognize the card? Shouldn't kudzu "wake up" and configure the card when I boot up after installing it? This is a brand spanking new 4.4 system and a supported Agere chipset firewire card. I'm having trouble tickling devices connected to the card.

Hi, does the shapiro wilk test in R-1.3.0 work correctly? Maybe it does, but can anybody tell me why the following sample doesn't give "W = 1" and "p-value = 1": R> x<-1:9/10;x [1] 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 R> shapiro.test(qnorm(x)) Shapiro-Wilk normality test data: qnorm(x) W = 0.9925, p-value = 0.9986 I can't imagine a sample being

Hello All I am looking for high precision values for the normal distribution in the tail,(1e-10 and 1 - 1e-10) as the R package that I am using sets any number which is out of this range to these values and then calls the qnorm and qt function. What I have noticed is that the qnorm implementation in R is not symmetric when looking at the tails. This is quite surprising to me, as it is well known