Displaying 20 results from an estimated 9000 matches similar to: "0.5 != integrate(dnorm,0,20000) = 0"
2018 Mar 23
1
Integrate erros on certain functions
In the help for ?integrate:
>When integrating over infinite intervals do so explicitly, rather than
just using a large number as the endpoint. This increases the chance of a
correct answer ? any function whose integral over an infinite interval is
finite must be near zero for most of that interval.
I understand that and there are examples such as:
## a slowly-convergent integral
integrand
2010 Nov 17
2
Numerical integration
Hi!
I was wondering if there are any other functions for numerical integration,
besides 'integrate' from the stats package, but which wouldn't require the
integrand to be vectorized. Oh, and must be capable of integrating over
(-inf,+inf).
Thanks in advance,
Eduardo Horta
[[alternative HTML version deleted]]
2010 Dec 02
4
Integral of PDF
The integral of any probability density from -Inf to Inf should equal 1, correct? I don't understand last result below.
> integrate(function(x) dnorm(x, 0,1), -Inf, Inf)
1 with absolute error < 9.4e-05
> integrate(function(x) dnorm(x, 100,10), -Inf, Inf)
1 with absolute error < 0.00012
> integrate(function(x) dnorm(x, 500,50), -Inf, Inf)
8.410947e-11 with absolute error <
2011 Nov 10
2
performance of adaptIntegrate vs. integrate
Dear list,
[cross-posting from Stack Overflow where this question has remained
unanswered for two weeks]
I'd like to perform a numerical integration in one dimension,
I = int_a^b f(x) dx
where the integrand f: x in IR -> f(x) in IR^p is vector-valued.
integrate() only allows scalar integrands, thus I would need to call
it many (p=200 typically) times, which sounds suboptimal. The
2009 Aug 07
1
Gauss-Laguerre using statmod
I believe this may be more related to analysis than it is to R, per se.
Suppose I have the following function that I wish to integrate:
ff <- function(x) pnorm((x - m)/sigma) * dnorm(x, observed, sigma)
Then, given the parameters:
mu <- 300
sigma <- 50
m <- 250
target <- 200
sigma_i <- 50
I can use the function integrate as:
> integrate(ff, lower= -Inf, upper=target)
2002 Jun 28
1
integrate function fails! (PR#1718)
Full_Name: José Enrique Chacón
Version: 1.5.0 and 1.3.1
OS: Windows Millenium
Submission from: (NULL) (158.49.28.155)
Dear reader:
I was trying to evaluate the L2 error produced when estimating the density
function N(0,1) from a sample of size 100 using a kernel density estimate. It
produced a strange value. You can reproduce the process by typing
samp<-rnorm(100)
2009 Dec 18
1
Numerical Integration
Dear @ll. I have to calculate numerical integrals for triangular and trapezoidal figures. I know you can calculate the exactly, but I want to do it this way to learn how to proceed with more complicated shapes. The code I'm using is the following:
integrand<-function(x) {
print(x)
if(x<fx[1]) return(0)
if(x>=fx[1] && x<fx[2]) return((x-fx[1])/(fx[2]-fx[1]))
2011 Oct 06
2
Titles changing when a plot is redrawn
I ran into a problem with titles on graphs. I wanted a graph with
multiple subplots, with each having a title that involved both
a Greek letter and an identifier for each graph. Below is a
simplified version of code to do this. The graph appears fine,
with the first graph having "i=1" in the title, and the second
graph having "i=2" in the title. However, when I resize the
2013 Feb 05
1
integrate: Don't do this?
When I run the following function
HQ2 <- function(n) {
nv <- 6 * sqrt(n)
fcn <- function(z) {
pchisq(z^2 / 36, n - 1) * dnorm(nv - z)
}
## I want the integral from 0 to infinity:
f.Inf <- integrate(fcn, 0, Inf)
## Doc: "Don't do this":
f.100 <- integrate(fcn, 0, 100)
cbind(f.Inf, f.100)
}
I get, for n = 9 and
2004 May 05
4
Discontinuities in a simple graph (machine precision?)
Hi,
I've got an ugly but fairly simple function:
mdevstdev <- function(a){
l <- dnorm(a)/(1-pnorm(a))
integrand <- function(z)(abs(z-l)*dnorm(z))
inted <- integrate(integrand, a, Inf)
inted[[1]]/((1- pnorm(a))*sqrt((1 + a*l - l^2)))
}
I wanted to quickly produce a graph of this over the range [-3,3] so I
used:
plotit <-function(x=seq(-3,3,0.01),...){
2011 Jun 25
1
integration function
Hi all,
Can anyone please take a look at the following two functions.
The answer does not seem to be right.
Thank you very much!
f1 <- function(x)
{integrand <- function (x, mu){
dnorm(x, mean=mu, sd=1)*dnorm(mu, mean=2, sd=1)
}
integrate(integrand, -Inf, Inf,x)$val
}
f2 <- function(x)
{integrand <- function (x, mu){
2006 Nov 18
1
Questions regarding "integrate" function
Hi there. Thanks for your time in advance.
I am using R 2.2.0 and OS: Windows XP.
My final goal is to calculate 1/2*integral of
(f1(x)^1/2-f2(x)^(1/2))^2dx (Latex codes:
$\frac{1}{2}\int^{{\infty}}_{\infty}
(\sqrt{f_1(x)}-\sqrt{f_2(x)})^2dx $.) where f1(x) and f2(x) are two
marginal densities.
My problem:
I have the following R codes using "adapt" package. Although "adapt"
2004 Jul 08
1
(PR#7070)
> version
_
platform i686-pc-linux-gnu
arch i686
os linux-gnu
system i686, linux-gnu
status
major 1
minor 7.1
year 2003
month 06
day 16
language R
Bug:
integrate(f,lower,upper,extra_args)
where
f <- function(x,extra_args)
{
body
}
integrate doesn't pass the extra arguments when calling f.
As a first check of this finding I integrated dnorm from
2011 May 30
1
Error in minimizing an integrand using optim
Hi,
Am not sure if my code itself is correct. Here's what am trying to do:
Minimize integration of a function of gaussian distributed variable 'x' over
the interval qnorm(0.999) to Inf by changing value of parameter 'mu'. mu is
the shift in mean of 'x'.
Code:
# x follows gaussian distribution
# fx2 to be minimized by changing values of mu
# integration to be done over
2013 Jul 16
2
Problem following an R bug fix to integrate()
I have been told by the CRAN administrators that the following code generated
an error on 64-bit Fedora Linux (gcc, clang) and on Solaris machines (sparc,
x86), but runs well on all other systems):
> fn <- function(x, y) ifelse(x^2 + y^2 <= 1, 1 - x^2 - y^2, 0)
> tol <- 1.5e-8
> fy <- function(x) integrate(function(y) fn(x, y), 0, 1,
2016 Dec 08
2
require(..., quietly=TRUE) does not suppress warning
Hi,
The `quietly` argument of `require` is documented as follows:
quietly: a logical. If ?TRUE?, no message confirming package
attaching is printed, and most often, no errors/warnings are
printed if package attaching fails.
However:
> require(foo, quietly=TRUE)
Warning message:
In library(package, lib.loc = lib.loc, character.only = TRUE, logical.return = TRUE, :
2018 Feb 06
2
question with integrate function
Hi all,
The function h below is a function of c and it should be a monotone
increasing function since the integrand is nonnegative and integral is
taken from c to infinity. However, as we can see from the plot, it is not
shown to be monotone. Something wrong with the usage of integrate function?
Thanks so much for your help.
Hanna
h <- function(c){
g <- function(x){pnorm(x-8.8,
2012 Jun 24
2
Win 64 package build - ERROR: loading failed for 'x64'
I have developed an R package that works under Win32, but when I attempt to build it on Win64,
I get ERROR: loading failed for 'x64'
More precisely, I developed and tested the package under Win32 and it works. But when I move
to a 64 bit Windows 7 (Home Premium) system, and attempt to build both 32 bit and 64 bit packages,
the 32 bit package seems to build, but the 64 bit build
2011 Jun 06
2
Taking Integral and Optimization using Integrate, Optim and maxNR
Dear All, Hello!
I have some questoins in R programming as follows:
Question 1- How to take the integral of this function with respect to y, such that x would appear in the output after taking integral.
f(x,y)=(0.1766*exp(-exp(y+lnx))*-exp(y+lnx))/(1-exp(-exp(y+lnx))) y in (-6.907,-1.246)
It is doable in maple but not in R. At least I could not find the way.
p.s: result from maple is:
2016 Dec 08
3
wish list: generalized apply
Dear All,
I regularly want to "apply" some function to an array in a way that the arguments to the user function depend on the index on which the apply is working. A simple example is:
A <- array( runif(160), dim=c(5,4,8) )
x <- matrix( runif(32), nrow=4, ncol=8 )
b <- runif(8)
f1 <- function( A, x, b ) { sum( A %*% x ) + b }
result <- rep(0.0,8)
for (i in 1:8) {