similar to: segfault interest?

Displaying 20 results from an estimated 8000 matches similar to: "segfault interest?"

2007 Nov 16
2
expand.grid overflows?
>cbn<-as.matrix(expand.grid( rep( list(0:1), 50))) Error in rep.int(rep.int(seq_len(nx), rep.int(rep.fac, nx)), orep) : invalid 'times' value In addition: Warning message: In rep.int(rep.int(seq_len(nx), rep.int(rep.fac, nx)), orep) : NAs introduced by coercion But I'm only interested in cbn matrix rows where: cbn<- cbn[rowSums(cbn)==5,] Is there a way to evaluate it
2010 Mar 30
2
Problem with expand.grid() function
Hi, good morning, I got following error which looks strange to me while executing this code : > temp <- expand.grid(rep(list(c(1,0)),40)) Error in rep.int(rep.int(seq_len(nx), rep.int(rep.fac, nx)), orep) : invalid 'times' value In addition: Warning message: In rep.int(rep.int(seq_len(nx), rep.int(rep.fac, nx)), orep) : NAs introduced by coercion However if I put a small
2017 Jul 13
0
Quadratic function with interaction terms for the PLS fitting model?
> On Jul 13, 2017, at 10:43 AM, Bert Gunter <bgunter.4567 at gmail.com> wrote: > > poly(NIR, degree = 2) will work if NIR is a matrix, not a data.frame. > The degree argument apparently *must* be explicitly named if NIR is > not a numeric vector. AFAICS, this is unclear or unstated in ?poly. I still get the same error with: library(pld) data(gasoline) gasTrain <-
2013 May 31
1
R 3.0.1 : parallel collection triggers "long memory not supported yet"
Dear R developers: ... 7: lapply(seq_len(cores), inner.do) 8: FUN(1:3[[3]], ...) 9: sendMaster(try(lapply(X = S, FUN = FUN, ...), silent = TRUE)) Selection: .....................Error in sendMaster(try(lapply(X = S, FUN = FUN, ...), silent = TRUE)) : long vectors not supported yet: memory.c:3100 admittedly, my outcome will be a very big list, with 30,000 elements, each containing data frames
2011 Aug 30
1
"Negative length vector" error in simple merge
Hi, I'm trying to take a vector (length almost 2,000,000) and merge it with a data frame of the same length. I'm trying to do it solely based on index, and not any other factors. The vector is called "offense", and the data frame is just called "data". I went with the simplest option: merge(data,offense) but it always gives me the same error: Error in
2013 Jan 07
3
multiple versions of function
dear R experts: I want to define a function the calculates the black-scholes value. it takes 5 named parameters, BS <- function(S,K,dt,rf,sigma) {} . let's presume I want to be able to call this not only with my 5 numeric vectors BS( sigma=0.3, S=100, K=100, dt=1, rf=0.1 ) and BS( 100, 100, 1, 0.1, 0.3), but also with a data frame that contains the variables alll in a neat data frame
2011 Oct 11
2
SLOW split() function
dear R experts: ?apologies for all my speed and memory questions. ?I have a bet with my coauthors that I can make R reasonably efficient through R-appropriate programming techniques. this is not just for kicks, but for work. for benchmarking, my [3 year old] Mac Pro has 2.8GHz Xeons, 16GB of RAM, and R 2.13.1. right now, it seems that 'split()' is why I am losing my bet. ?(split is an
2008 Feb 07
1
Problems reshaping data with cast()
Hi, I'm trying to cast() some data, but keep on getting the following error... > norm.all.melted.height <- transform(all.melted.height, + norm.height = value / ave(value, SNP, Pool, FUN = max) + ) Warning messages: 1: In FUN(X[[147L]], ...) : no non-missing arguments to max; returning -Inf 2: In FUN(X[[147L]],
2009 Oct 12
1
Loading data to Trellis barchart plot.
Dear all, I have a question about loading the data to barchart plot. I know this could be a very easy question, but I just can not get my head around. What I need to do is to create a trellis plots barchart style (horizontal bar), with levels of one variable (ie. variable “colour” in my example) as ylab and frequency as xlab on each trellis plot. The trellis plots is separated based on
2012 Mar 30
4
list assignment syntax?
Dear R wizards: is there a clean way to assign to elements in a list? what I would like to do, in pseudo R+perl notation is f <- function(a,b) list(a+b,a-b) (c,d) <- f(1,2) and have c be assigned 1+2 and d be assigned 1-2. right now, I use the clunky x <- f(1,2) c <- x[[1]] d <- x[[2]] rm(x) which seems awful. is there a nicer syntax? regards, /iaw ---- Ivo Welch
2009 Jun 25
2
stringsAsFactors has no impact in expand.grid()?
Hi I have the feeling, that the argument stringsAsFactors has no impact in the function expand.grid: a <- c("PR", "NC", "A2", "BS") b <- c(1, 0.5, 0.25, 0.125, 0.0625, 0.03125) class(expand.grid(css, fscs, stringsAsFactors=FALSE)[[1]]) [1] "factor" class(expand.grid(css, fscs, stringsAsFactors=TRUE)[[1]]) [1] "factor" Also, when
2012 May 09
2
big quasi-fixed effects OLS model
dear R experts---now I have a case where I want to estimate very large regression models with many fixed effects---not just the mean type, but cross-fixed effects---years, months, locations, firms. Many millions of observations, a few thousand variables (most of these variables are interaction fixed effects). could someone please point me to packages, if any, that would help me estimate such
2010 Jan 08
4
fast lm se?
dear R experts---I am using the coef() function to pick off the coefficients from an lm() object. alas, I also need the standard errors and I need them fast. I know I can do a "summary()" on the object and pick them off this way, but this computes other stuff I do not need. Or, I can compute (X' X)^(-1) s^2 myself. Has someone written a fast se() function? incidentally, I think
2010 Jun 11
3
lm without error
this is not an important question, but I wonder why lm returns an error, and whether this can be shut off. it would seem to me that returning NA's would make more sense in some cases---after all, the problem is clearly that coefficients cannot be computed. I know that I can trap the lm.fit() error---although I have always found this to be quite inconvenient---and this is easy if I have only
2013 Feb 07
4
Hard Stop?
is it possible to throw a stop() that is so hard that it will escape even tryCatch? /iaw ---- Ivo Welch (ivo.welch at gmail.com)
2012 May 31
2
print.data.frame to string?
dear R experts---is there a function that prints a data frame to a string? cat() cannot handle lists, so I cannot write cat("your data frame is:\n", df, "\n"). regards, /iaw ---- Ivo Welch (ivo.welch@gmail.com) [[alternative HTML version deleted]]
2011 Oct 10
5
multicore by(), like mclapply?
dear r experts---Is there a multicore equivalent of by(), just like mclapply() is the multicore equivalent of lapply()? if not, is there a fast way to convert a data.table into a list based on a column that lapply and mclapply can consume? advice appreciated...as always. regards, /iaw ---- Ivo Welch (ivo.welch at gmail.com)
2012 Dec 24
2
parallelized version of "by" and "ave"
Dear R experts--- Has anyone written parallel versions of "by" (i.e., mcby) and "ave" (i.e. mcave) ? I did ask a question like this a year ago, and then the answer was no. for those who are googling the group for the answer to this question, in the meantime, the poor man's version of "by" is mclapply( split( ds, factor ), FUN ) I don't know the poor
2010 Aug 22
2
on abort error, always show call stack?
Dear R Wizards---is it possible to get R to show its current call stack (sys.calls()) upon an error abort? I don't use ESS for execution, and it is often not obvious how to locate how I triggered an error in an R internal function. Seeing the call stack would make this easier. (right now, I sprinkle "cat" statements everywhere, just to locate the line where the error appears.) Of
2010 Aug 30
4
different interface to by (tapply)?
dear R experts: has someone written a function that returns the results of by() as a data frame? ??of course, this can work only if the output of the function that is an argument to by() is a numerical vector. presumably, what is now names(byobject) would become a column in the data frame, and the by object's list elements would become columns. it's a little bit like flattening the by()