similar to: lm combined with splines

Hi I've 3 iax connections to my provider , each of them have own DID , PH1<----| | \/ PH2<-->|-----| <---------------------------> |----|<-- DID1 | A1 | <---------------------------> |ISP |<-- DID2 PH3<-->|-----| <---------------------------> |----|<-- DID3 I had iax phone on each of this connection , but now I want to terminate all

Hi, I'm working on OpenCL and I'm using clang as compiler (based on clang 3.7.0). I have a issue, I'm generating a bitcode file (that I can print before before the generation). But when I'm trying to read it again with clang, I have this issue: "error: Invalid record" How can I managed to know where it comes from? Thank you, Romaric Here is what is print before the

I have a simple cdr configured with the default tables, here is a row of a good cdr report calldate | clid | src | dst | dcontext | channel | ect ..... ect .... 2008-08-29 10:16:49 | "C. BOUTON" <40> | 40 | XXXXXXXXXXX | phonesystems | SIP/40-08776938 | ect ..... ect .... I have replaced the number by

I'm trying to build a vector (fitting systems of equations) and I'm having a little trouble getting the response variables from a list of formulas... bdgmodel <- lbdg ~ d1sqr + ld1 + lhg hgmodel <- lhg ~ ht2 + lht + whc inst <- ~ d1sqr + ld1 + ht2 + lht + whc systemeq <- list( bdgmodel, hgmodel ) # manually generate the y matrix... y <- cbind( matrix( lbdg ),

Hi, I have a data.frame with many variables for which I am performing the mean by subgroup, for a pair of variables at a time, where one of them for each pair defines the subgroup. The subgroups in the x$cm1 are 0, 1 and 2. x ph1 cm1 0.2345 2 1.2222 1 2.0033 0 0.0000 2 1.0033 1 0.2345 0 1.2222 2 2.0033 0 0.0000 1 1.0033 2 > meanbygroup <- as.vector(with(x, by(x$ph1, x$cm1, mean)))

Dear All, I am analysing some data for a colleague (not my data, gotta be published so I cannot divulge). My response variable is the number of matings observed per day for some fruitlies. My factors are: Day: the observations were taken on 9 days Regime: 3 selection regimes Line: 3 replicates per selection regime. I have 81 observations in total The lines are coded A to I, so I do not need

Hi folks. If I have the following in my "data" event pH1 pH2 1 4.0 6.0 2 4.3 5.9 3 4.1 6.1 4 4.0 5.9 and on and on..... for about 400 events Is there a way I can get R to plot event vs. pH1 and event vs. pH2 and then do a loess or lowess line for each?? Thanks in advance David [[alternative HTML version deleted]]

The `examples' section says plot.mlm # to see how the "NotYetImplemented" # reference is made automagically ^ Best, Torsten

Dear Sir/madam, I'm getting a problem with a R-code which calculate Fisher Information Matrix for Hybrid Censored Weibull Distribution. My problem is that: when I take weibull(scale=1,shape=2) { i.e shape>1} I got my desired result but when I take weibull(scale=1,shape=0.5) { i.e shape<1} it gives error : Error in integrate(int2, lower = 0, upper = t) : the integral is probably

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Hello, Is HTTP basic authentication the only way for icecast to perform authentication ? With a link like http://username:password at example.com:8000/mystream (HTTP basic authentication) it has a number of problems regarding browsers. Chrome for security reasons does not follow the link and shows a popup asking to enter the credentials but this destroys user experience for a site with a

I have a recurring graphics issue that I've not been able to resolve with R. If I make a series of regression estimates and then plot the estimated function for the regression lines over a scatter plot of the data, e.g., using a sequence of plot( ) and lines ( ) similar to those below

Hi, On 01/13/2015 03:47 PM, dtouch3d completely wrote: > Is HTTP basic authentication the only way for icecast to perform > authentication ? With a link like > > http://username:password at example.com:8000/mystream > No, you are misunderstanding HTTP auth. Parameters in the URL is not the only way and has been largely out of fashion since the end of the last millennium. Most

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Hello all, I am working on a longitudinal study of children in the UK and trying the PAN package for imputation of missing data, since it fulfils the critical criteria of taking into account individual subject trend over time as well as population trend over time. In order to validate the procedure I have started by deleting some known values ?we have 6 annual measures of height on 300 children

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Hi List, I have to compare a relationship between y and x for two locations. I found logistic regression fits both datasets well, but I am not sure how to test if relationships for both sites are significantly different. I searched the r site, however no answers exactly match the question. I used Tukey's HSD to compare two means, but the relationship in my study was not simply linear. So I

The subject says it all really. Question 1. Here is some code created to illustrate my problem, can anyone spot where I'm going wrong? Question 2. The reason I'm following a manual specification of models relates to the fact that in reality I am using mgcv::gam, and I'm not aware that dredge is able to separate individual smooth terms out of say s(a,b). Hence an additional request,

Hi there, I have a data frame as listed below: > Ca.P.Biomass.A P Biomass 1 334.5567 0.2870000 2 737.5400 0.5713333 3 894.5300 0.6393333 4 782.3800 0.5836667 5 857.5900 0.6003333 6 829.2700 0.5883333 I have fit the data using logistic, Michaelis?Menten, and linear model, they all give significance. > fm1 <- nls(Biomass~SSlogis(P, phi1, phi2, phi3), data=Ca.P.Biomass.A)

Hi R Users, When I use package lme4 for mixed model analysis, I can't distinguish the significant and insignificant variables from all random independent variables. Here is my data and result: Data: Rice<-data.frame(Yield=c(8,7,4,9,7,6,9,8,8,8,7,5,9,9,5,7,7,8,8,8,4,8,6,4,8,8,9), Variety=rep(rep(c("A1","A2","A3"),each=3),3),