similar to: reference counting bug: overwriting for loop 'seq' variable

Dear friends, How do I stop partial matching of list names? e.g., x <- list(AAAA="aaaaa", BBBBB="bbbbb") is.null(x$A) #returns FALSE even though there is no element A. if(is.null(x$A)) {result <- x$BBBB} else {result <- x$A} result #is aaaa even though there is no x$A element x <- list(CCCC="aaaaa", BBBBB="bbbbb") if(is.null(x$A))

Hi, I've got a relatively simple tinc setup. I've got two "servers" that are on the public internet that act as routers for three "clients" that are behind NATs. Those servers are called aaaaa and bbbbb the clients are xxxxx, yyyyy and zzzzz Unfortunatly the servers have problems accepting a connection from the clients syslog on aaaaa: Sep 29 18:28:58 schuerrer

Hi All, I'm just wanting to check that my understanding of the settings is correct as my web searches are finding a lot of dated information. If I want a Centos 6 sendmail system act as the secondary MX for domain bbbbb.co.uk do I just add a Connect:bbbbb.co.uk RELAY statement into /etc/mail/access and restart sendmail Obviously I have the DNS MX records for the domain are

Thanks for the dput... #### reproducible example of split-apply-combine ### dta <- structure(list(date = structure(c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 20L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 20L, 21L, 22L, 23L, 24L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L), .Label = c("2012-01-25 18:00:00",

On Thu, 26 Oct 2017, Thomas Adams wrote: > Hi Jeff, > > Thank you for the suggestions -- I appreciate your help. Unfortunately, the > result2 has two problems... > > (1) there are now 3 date columns (it looks like 2 cols are merged into 1 > col) No, there are two date columns. Result2 includes the grouping value as a row name (pulled from the names of the dta2list items

Hi Jeff, Thank you for the suggestions -- I appreciate your help. Unfortunately, the result2 has two problems... (1) there are now 3 date columns (it looks like 2 cols are merged into 1 col) (2) the output rows should not have any of the basistime dates repeated (maybe I misstated the problem); I need the max fcst value by basistime, but also list the date value for that row; for example:

Thanks Rowland - appreciated. I have checked the ldbsearch result and both groups look to be pretty much exactly the same to me, one of them is shown below (I have sanitised some of the output, replacing parts with 123/a/b/c, but the rest of the output is byte for byte as seen) In the time between posting my original message and checking again just now, however, I have the following additional

Hello all! I've been struggling with is for many hours today; I'm close to getting what I want, but not close enough... I have a dataframe consisting of two date-time columns followed by two numeric columns. what I need is the max value (in the first numeric column) based on the 2nd date-time column, which is essentially a factor. But, I want the result to provide both date-time values

Hi all, I am using RStudio. I wanted to copy and past an expression/line. I highlighted it, and then copied and pasted: The result was not the line that I wanted, instead, it was the line above... For example: I have three lines: aaaaa bbbbb ccccc .... I highlighted "bbbbb" and copied, but the pasted outcome was "aaaaa"... What happened? Thanks al ot! [[alternative

I''m having trouble understanding Ruby''s concept of scope. Could someone explain the difference between the following 2 programs. They both return the same output "aaaaaaaa", but I''m just not sure about self in #1. Is self.day and self.title referring to and setting class variables or are they instance variables? Thanks in advance. # 1. class Session

Hi, In the Sweave output for summary for several types of model objects and also for the comparison of models with anova, I find that that the display of the call(s) or formula does not obey the width option, even with keep.source=TRUE set, so that a long formula will overshoot the margins in the document. I would like to know if there is a good way to correct that. Looking at the print.summary

Hi Is there any function to do bitwise or/and/xor on long bit vectors? "aaaaa" "0000000000000000000000000000000000000000000000000000000000000000......................" "bbbbb" "0000000000000000000000000000001000000000000100000000100000001100......................" "ccccc"

I need to create 100 variable ,whose name is id.1,id.2~~~~id.100 then I need to let a vector say id<-c(id.1,id.2....id.100) any easy way to do this? thanks a lot~ [[alternative HTML version deleted]]

Dear Community, I have been using two types of survival programs to analyse a data set. The first one is an R function called aftreg. The second one an STATA function called streg. Both of them include the same analyisis with a weibull distribution. Yet, results are very different. Shouldn't the results be the same? Kind regards, J -- View this message in context:

Hi, one short question: Is it possible for the zaptel driver to deal with multiple phone numbers on one single E1 PRI line? I could make my carrier route +49 xxx aaaaa-zzz and +49 xxx bbbbb-zzz and others down one single PRI trunk to our asterisk box terminating in a Digium TE410P. Does the driver handle this and can I put calls coming in all on the same physical interface put into

Hello, It's an alternative to use SAS by function in R? I want to plot d histograms by plot.from example bellow: Thank you! plot d 1 1 16.3 2 1 25.0 3 1 57.8 4 1 17.0 5 2 10.8 13 2 96.4 17 3 76.0 18 3 32.0 19 3 11.0 20 3 11.0 24 3 106.0 25 3 12.5 21 4 19.3 22 4 12.0 26 4 15.0 27 5 99.3 32 7 11.0 36

One of our R users here just showed me the following problem while investigating the return value of a while loop. I added some information on a similar bug in for loops. I think he was using 2.9.0 but I see the same problem on today's development version of 2.10.0 (svn 48703). Should the semantics of while and for loops be changed slightly to avoid the memory buildup that fixing this to

On Fri, Feb 13, 2015 at 9:57 AM, Ken Smith <kens at kensnet.org> wrote: > Hi All, > > I'm just wanting to check that my understanding of the settings is correct > as my web searches are finding a lot of dated information. > > If I want a Centos 6 sendmail system act as the secondary MX for domain > bbbbb.co.uk do I just add a > > Connect:bbbbb.co.uk

On Fri, February 13, 2015 10:57, Ken Smith wrote: > Hi All, > > I'm just wanting to check that my understanding of the settings is > correct as my web searches are finding a lot of dated information. > > If I want a Centos 6 sendmail system act as the secondary MX for > domain > bbbbb.co.uk do I just add a > > Connect:bbbbb.co.uk RELAY > >

Dear R-User, Appreciate any helps. It looks simple, but I don't have a clue. Given that I have a dataframe of tree population with three variables: sp=species , d0=initial_size grow=growth increment from initial size per year How can I calculate the future growth increment of each tree for the next 3 years. The following Rscript was written, #---------- a0 <-