similar to: degraded performance with rank()

? Fri, 12 Jul 2024 17:35:19 +0200 Hilmar Berger via R-devel <r-devel at r-project.org> ?????: > This can be finally traced to base::rank() (called from > xtfrm.default), where I found that > > "NB: rank is not itself generic but xtfrm is, and rank(xtfrm(x), ....) > will have the desired result if there is a xtfrm method. Otherwise, > rank will make use of ==, >,

Good evening, I recently have observed slow merges when combining multiple data frames derived from DataFrame and base::data.frame. I observed that the index column of intermediate tables was of class <AsIs> (automatically converted from character). The problem occurred mainly when using the sorted = T option in base::merge. This can be traced to xtfrm.AsIs being more than 100 times slower

Suppose I have a list of logicals, such as returned by lapply: Theoph$Dose[1] <- NA Theoph$Time[2] <- NA Theoph$conc[3] <- NA lapply(Theoph,is.na) Is there a direct way to execute logical "or" across all vectors? The following gives the desired result, but seems unnecessarily complex. as.logical(apply(do.call("rbind",lapply(Theoph,is.na)),2,"sum"))

Is there a conventional way to test for nested factors? I.e., if 'a' and 'b' are lists of same-length factors, does each level specified by 'a' correspond to exactly one level specified by 'b'? The function below seems to suffice, but I'd be happy to know of a more succinct solution, if it already exists. Thanks, Tim. --- "%nested.in%" <-

Hello everybody, it looks like the presense of some (do know know which) S4 methods for a given S4 class degrades the performance of xtfrm (used in 'order' in new R-devel) by a factor of millions. This is for classes that ARE derived from numeric directly and thus should be quite trivial to convert to numeric. Consider the following example: setClass("TimeDateBase",

Suppose I want to delete everything in my working directory that is not a function. It seems that sapply(ls(),is.function) always returns FALSE, because ls() returns objects of mode character. How do I evaluate is.function(), not on a character string, but on the object that character string represents? Thanks, Tim

Hi. I'm trying to find a systematic way to prevent assignment to names of existing functions. I've tried reassigning to the assignment operator, with mixed results. The function definition for "<-" below works as hoped for the demonstrated assignments to a and c. However, for the assignment based on the test function, it appears that the formal argument is not

Hi. I frequently convert date and time data to and from character representations. I'm frustrated with chron, because 'seconds' are required to create a time object (my input data never has seconds). More importantly, I cannot make chron print the format 12/30/2006 (which my output data requires). I really like the format flexibility of strftime() and strptime(), but of course

I see in the archives significant discussion about SAS, CDISC formats etc. for FDA, but no direct suggestion of adding a write.xport method to the foreign package. Are there significant barriers to doing so? [[alternative HTML version deleted]]

Hi. I have a vector of quantiles and a vector of probabilites that, when plotted, look very like the gamma cumulative distribution function. I can guess some shape and scale parameters that give a similar result, but I'd rather let the parameters be estimated. Is there a direct way to do this in R? Thanks, Tim. week <- c(0,5,6,7,9,11,14,19,39) fraction <-

? Sat, 27 Apr 2024 13:56:58 -0500 Jonathan Keane <jkeane at gmail.com> ?????: > In devel: > > max(numeric_version(c("1.0.1.100000000", "1.0.3.100000000", > "1.0.2.100000000"))) > [1] ?1.0.1.100000000? > > max(numeric_version(c("1.0.1.10000000", "1.0.3.10000000", > "1.0.2.10000000"))) > [1]

I have noticed a significant performance degradation using merge in 2.9.1 relative to 2.8.1. Here is what I observed: N <- 100000 X <- data.frame(group=rep(12:1, each=N), mon=rep(rev(month.abb), each=N)) X$mon <- as.character(X$mon) Y <- data.frame(mon=month.abb, letter=letters[1:12]) Y$mon <- as.character(Y$mon) Z <- cbind(Y, group=1:12) system.time(Out

r-devel, In a development version of the CRAN package metrumrg, I write ... require(reshape) setGeneric('cast') setOldClass(c('keyed','data.frame')) setMethod('cast','keyed', function ...) The result is satisfactory when sourcing the code directly, but when checking the package (which has 'reshape' as a dependency in the DESCRIPTION file) I get

In R devel, function 'factor' has been changed, allowing and merging duplicated 'labels'. Issue 1: Handling of specified 'labels' without duplicates is slower than before. Example: x <- rep(1:26, 40000) system.time(factor(x, levels=1:26, labels=letters)) Function 'factor' is already rather slow because of conversion to character. Please don't add slowdown.

I have found that order() fails in a rather arcane circumstance, as in this example: > foo <- I( c('x','\265g') ) > order(foo) Error in if (xi > xj) 1L else -1L : missing value where TRUE/FALSE needed > foo <-c('x','\265g') > order(foo) [1] 1 2 > sessionInfo() R version 3.1.1 (2014-07-10) Platform: x86_64-apple-darwin13.1.0 (64-bit)

Dear list-reader, by running the following script: library(zoo) sessionInfo() search() packageDescription("zoo") data(EuStockMarkets) dax <- as.zoo(EuStockMarkets[1:10, "DAX"]) daxr <- diff(log(dax)) identical(as.vector(qnorm(daxr)), qnorm(coredata(daxr))) qqnorm(coredata(daxr)) qqnorm(daxr) qqnorm() produces an error: > qqnorm(daxr) Fehler in if (xi == xj) 0L

Can anyone explain what I'm missing here? max(pp1 <- package_version(c("0.99999911.3","1.0.4","1.0.5"))) ## [1] ?1.0.4? max(pp2 <- package_version(c("1.0.3","1.0.4","1.0.5"))) ## [1] ?1.0.5? I've looked at ?package_version , to no avail. Since max() goes to .Primitive("max") I'm having trouble figuring out

Dear Ivan, thanks for the confirmation and the proposed patch. I just wanted to add some notes regarding the relevance of this: base::merge using by.x=0 or by.y=0 (i.e. matching on row.names) will automatically add a column Row.names which is I(row.names(x)) to the corresponding input table (using I() since revision 39026 to avoid conversion of character to factor). When this column is used

Hi, I'm currently in the process of writing an R-installation SOP for my company. As part of that process I'm using the recommendations from the 'R Installation and Administration' document, section 3.2, "Testing an installation". This is done on an XP machine, using the latest binary of 2.11.0. The binary is downloaded and then installed from the installer. I then

Dear all, actually, it is not clear to me why there is still a protection of the added Row.names column in merge using I(). This seems to stem from a time when R would automatically convert character vectors to factor in data.frame on insert. However, I can't reproduce this behaviour even in data.frames generated with stringsAsFactors = T in current versions of R. Maybe the I() inserted in r