similar to: seekViewport error

list(...) I can not get at the grid viewports in a ggplot2 plot. I know there is supposed to be a viewport called "panel_1_1" but downViewport() can't find it. Has the viewport been popped? I had a quick look at the functions involved (eg ggplot_plot) but there is no obvious problem there. > library(ggplot2) > qplot(1:10, 1:10) > current.viewport() viewport[ROOT] >

Hi, I am having trouble plotting a series of dendrograms using lattice and grid code as found in Paul Murrells book R Graphics. This is the error message I recieve: Error in downViewport.vpPath(vpPathDirect(name), strict, recording = recording) : Viewport 'plot1.panel.1.1.off.vp' was not found I have attached the code and also my data file. Should anyone have any suggestions then

Hello, I have a multi-page display each consisting of two-panels above each other. I need to draw a line from the top panel to bottom panel. Using current.vpTree() i find that "plot1.panel.1.2.vp" and "plot1.panel.1.1.vp" are the top and bottom ones respectively. I am using the following code(inspired by Paul Murrell's R Graphics) to draw a line. (All the

A year ago I had posted this code https://stat.ethz.ch/pipermail/r-devel/2005-June/033508.html and the associated discussion was that there would be a print.trellis argument that could be used to eliminate the need for with.vpPath or with.viewport there. I assume that that is what draw.in= in print.trellis is for. When I try it I get an error. I did notice that ?print.trellis says draw.in=

I am setting up base plots -- one in viewport A and and one in B. This part works fine. But if I go back to A after having done B and add horizontal lines it seems to not use the correct coordinates. How do I tell it to resume using A's coordinates? I am already using par(fig = gridFIG()) but it seems that that's not enough to reestablish them. What happens is that when I go back to

I am setting up base plots -- one in viewport A and and one in B. This part works fine. But if I go back to A after having done B and add horizontal lines it seems to not use the correct coordinates. How do I tell it to resume using A's coordinates? I am already using par(fig = gridFIG()) but it seems that that's not enough to reestablish them. What happens is that when I go back to

I'm trying to create a layout with named viewports that I can use for other functions. I create the viewport tree that I want, and a list of grobs with the viewports describing where they should go. library(grid) vp <- vpTree( viewport(layout=grid.layout(2,2), name="layout"), children=vpList( viewport(layout.pos.col = 1, layout.pos.row=1, name="tl"),

Hi, I recently created a function which uses grid with a viewport constructed with grid.layout() to position four plots on a plot device. My question is what's the best way to programatically traverse each element of the viewport? The grid is 5x5 and the four plots occupy positions (2,2), (4,2), (2,4), and (4,4). Here's the viewport code: pushViewport( viewport(

The following code, though not brilliant, works on an A4 page. It might look odd on other devices of a very different size. =============X8------- cut here ---------------------------- require(grid) wide <- 15 vps <- grid.layout(nrow = 3, ncol = 4, widths = unit(rep(1, 4), rep("null", 4)), heights = unit(c(99, 1, 99),

Hi Deepayan and everyone, I need to add a common legend to a group of latice graphs, I have tried different ways using viewport and grid.draw without success. Here is what I have: plot.new() library(grid) library('IDPmisc') print(plot1, split=c(1,1,2,4), more=TRUE) print(plot4, split=c(2,1,2,4), more=TRUE) print(plot2, split=c(1,2,2,4), more=TRUE) print(plot5, split=c(2,2,2,4),

Forgot to send to the list. Begin forwarded message: > From: Saptarshi Guha <saptarshi.guha@gmail.com> > Date: September 19, 2008 1:43:50 PM GMT-04:00 > To: Gabor Grothendieck <ggrothendieck@gmail.com> > Subject: Re: [R] Lines between panels in lattice > > Certainly. > > x=cbind(runif(10),rnorm(10),c(rep(1,5),rep(2,5))) >

Hello, I created several plot with ggplot2 dev mode. Now I want to combine the plots in a grid e.g. 2x2 with a fixed size of the output. What I am doing at the moment is: grid.newpage() pushViewport(viewport(layout = grid.layout(nrow=2, ncol=2, widths = unit(c(7.5,6.5), "cm"), heights = unit(rep(5, 2), "cm")))) print(plot1, vp = viewport(layout.pos.row = 1,

Hi, I just try to draw multiple plots in one page using R, I used par command. For example I have 7 plots, but instead of arranging them in the default way plot1 plot2 plot3 plot4 plot5 plot6 plot7 I want them in this order plot1 plot2 plot3 plot4 plot5 plot6 plot7 Could somebody tell me how to do this, please? Thanks so many. Suyan

Dear colleagues I'm using data that looks like .test and .test1 below to draw two mosaic plots with cell labelling (the row percentages from the tables). When I take out the pop=FALSE commands in the mosaic commands and comment out the two lines labelling the cells, then the plots are laid out exactly as I'd like: side-by-side. But I do require the cell labelling and the pop=FALSE

Estimados miembros de la lista. Estoy trabajando con la función mosaic del paquete vcd. Cómo puedo hacer para ver el contenido fe la función y modificar algunos de sus argumentos? Muchas gracias, Manuel -- *Manuel Spínola, Ph.D.* Instituto Internacional en Conservación y Manejo de Vida Silvestre Universidad Nacional Apartado 1350-3000 Heredia COSTA RICA mspinola@una.ac.cr

Dear all, I would like to underline only the colnames in a table as e.g. grid.draw(tableGrob(head(iris, 10), name="test")) I can imagine you should use grid.edit or so, bu I can't figure out how... Does anyone have a suggestion? Thanks Robbert windows xp R 2.10.1 -- View this message in context:

i was trying to do a for loop for plotting the histograms , but it doesnt work properly > library(lattice) > columns <- 8:153 > plots <- vector("list", length(columns)) > j <- 0 > for (i in columns) + { + plots[[ j <- j+1 ]] <- histogram( ~ data[,i] | data[,2],ylab = "Frequency", + xlab = "Score", xlim = c(1,5), ylim =

The code below displays three graphs in three rows and one column but: 1. I want to remove the space between the graphs (I tried playing with position= arg to print.trellis but it seems quite difficult to get the right values and all my attempts had space between them or had overlapping graphs. Is there a better way to do this? 2. the widths of the plots are not the same even though I specified

I get the following error message followed by instability in R after the error message: Error: Cannot pop the top-level viewport (grid and graphics output mixed?) Have reduced something much more complex in my code to a simple test case. I run the following and then resize the window: X = seq (1,10) Y = X^2 opar <- par(no.readonly=TRUE, mar = c(2.5, 3.1, 1, 2)) grid.newpage()

Dr Murrell and others, It seems grid.ls() fails after any use of grid.remove(). It gives an infinite recursion error even in the simplest cases, and no matter what arguments are passed to grid.ls. > library(grid) > grid.newpage() > grid.lines(name="foo") > grid.ls() foo > grid.remove("foo") > grid.ls() Error: evaluation nested too deeply: infinite recursion