Displaying 19 results from an estimated 19 matches similar to: "make check failure -- R 2.1.0 Windows XP SP2"
2003 Jun 18
0
fitting two nonlinear mixed models simulataneously
Dear R users,
Being a R-novice using version 1.7.0 I have not managed to solve the
following problem, so I turn to you:
I have 12 pairs nonlinear curves having some parameters (p1,p2,p3) in common
and others specific to one of the curves (p4a,p4b). I want to fit a
nonlinear mixed model with nmle with the random effects varying over the 12
samples (pairs). In order to be able to estimate the
2005 Nov 29
1
saving AIC of intermediate models in step
Hi all,
I'm fitting GLM's using the step or stepAIC procedures and I would
like to save the AIC of the intermediate models. I would appreciate
very much information about how todo this.
Best wishes
Germ??n L??pez
2012 Feb 06
1
Simple lm/regression question
I am trying to use lm for a simple linear fit with weights. The results
I get from IDL (which I am more familiar with) seem correct and
intuitive, but the "lm" function in R gives outputs that seem strange to me.
Unweighted case:
> x<-1:4
> y<-(1:4)^2
> summary(lm(y~x))
Call:
lm(formula = y ~ x)
Residuals:
1 2 3 4
1 -1 -1 1
Coefficients:
2011 Jan 20
6
Identify duplicate numbers and to increase a value
Hi everybody.
I want to identify duplicate numbers and to increase a value of 0.01 for each time that it is duplicated.
Example:
x=c(1,2,3,5,6,2,8,9,2,2)
I want to do this:
1
2 + 0.01
3
5
6
2 + 0.02
8
9
2 + 0.03
2 + 0.04
I am trying to get something like this:
1
2.01
3
5
6
2.02
8
9
2.03
2.04
Actually I just know the way to identify the duplicated numbers
rbind(x, duplicated(x) |
2008 May 27
1
lm() output with quantiative predictors not the same as SAS
I am trying to use R lm() with quantitative and qualitative predictors, but am
getting different results than those that I get in SAS.
In the R ANOVA table documentation I see that "Type-II tests corresponds to the
tests produced by SAS for analysis-of-variance models, where all of the
predictors are factors, but not more generally (i.e., when there are
quantitative predictors)." Is
2013 Oct 04
1
[Bug 70130] New: unable to compile fragment shader program
https://bugs.freedesktop.org/show_bug.cgi?id=70130
Priority: medium
Bug ID: 70130
Assignee: nouveau at lists.freedesktop.org
Summary: unable to compile fragment shader program
Severity: normal
Classification: Unclassified
OS: Linux (All)
Reporter: infyquest at gmail.com
Hardware: x86 (IA32)
2011 Apr 13
4
is this an ANOVA ?
Hi all,
I have a very easy questions (I hope). I had measure a property of plants, growing in three different substrates (A, B and C). The rest of the conditions remained constant. There was very high variation on the results.
I want to do address, whether there is any difference in the response (my measurement) from substrate to substrate?
Which is the easiest (most elegant) way to force "aov" to treat numerical variables as categorical ?
2010 Jun 14
2
Which is the easiest (most elegant) way to force "aov" to treat numerical variables as categorical ?
Hi R help,
Hi R help,
Which is the easiest (most elegant) way to force "aov" to treat numerical variables as categorical ?
Sincerely, Andrea Bernasconi DG
PROBLEM EXAMPLE
I consider the latin squares example described at page 157 of the book:
Statistics for Experimenters: Design, Innovation, and Discovery by George E. P. Box, J. Stuart Hunter, William G. Hunter.
This example use
2006 Jan 27
1
about lm restrictions...
Hello all R-users
_question 1_
I need to make a statistical model and respective ANOVA table
but I get distinct results for
the T-test (in summary(lm.object) function) and
the F-test (in anova(lm.object) )
shouldn't this two approach give me the same result, i.e
to indicate the same significants terms in both tests???????
obs.
The system has two restrictions:
1) sum( x_i ) = 1
2) sum(
1998 Mar 18
1
Strange Results of summary()
--l4Siqd0eqV
Content-Type: text/plain; charset=us-ascii
Content-Transfer-Encoding: 7bit
Hello,
I run the following job. Please, compare the results of summary and
table concerning berufl. From similar SPSS/PSPP runs, the result of
table is correct.
Did I misunderstand anything or is there a bug?
What does the difference come from?
What does '(other)' mean?
What about the strange
2010 May 31
1
Post-hoc tests for repeated measures in balanced experimental design
Hi,
I am performing experiments in the field of visual perception where
we often apply balanced designs. Within a group of normal subjects,
we vary different stimulus conditions (like contrast, luminance,
temporal frequency of stimulation) and derive some psychophysical or
electrophysiological results from our subjects. Often, the main
question is to test the effect of these parameters
2010 Jul 02
0
Powercom driver patch
Hello everybody!
I'm trying to use nut-2.4.1 with brand new UPS Powercom Imperial
IMD-825AP USB. I've faced a problem that the driver powercom despite
specifying type=IMP automatically re-detects the UPS as "KIN" and then
interprets raw data incorrectly. The same problem was reported by
other Powercom users on the official support forum (
http://forum.pcm.ru ).
I suppose the
2002 Dec 25
0
Part II Re: read.ssd {foreign} (Reading a permanent SAS d ataset into an R data frame)
Scot,
Thanks for the info. I will try your code out to
verify the result, but before I do that, will your
code (SAS and R) work with variable names that are
longer than 8 characters long without truncating the
variable name in R?
Also, I wonder about using your method or the PROC
EXPORT method with larger data sets. The data sets I
will be working with for the most part will not be
that large,
2012 Jul 18
2
loop searching the id corresponding to the given index (timestamp)
Hello,
I have the following loop for two data sets: diveData_2008 and
diveData_2009. It uses two other data: diveCond_all and fishTable. The
problem is at the point to identify the dive_id for the given index (index
is timestamp). It keeps on saying
for the1st loop
Error in fishReport$dive_id[i] <- dive_id : replacement has length zero
for the 2nd loop
Error in fishReport$dive_id[i + j] <-
2006 Sep 17
2
histogram frequency weighing
Fellow R-helpers,
Suppose we create a histogram as follows (although it could be any vector
with zeroes in it):
R> lenh <- hist(iris$Sepal.Length, br=seq(4, 8, 0.05))
R> lenh$counts
[1] 0 0 0 0 0 1 0 3 0 1 0 4 0 2 0 5 0 6 0 10 0 9 0 4 0
[26] 1 0 6 0 7 0 6 0 8 0 7 0 3 0 6 0 6 0 4 0 9 0 7 0 5
[51] 0 2 0 8 0 3 0 4 0 1 0 1 0 3
2007 Jun 01
2
lguest problem on boot of guest kernel
Hi !
Kenrel 2.6.21 (kernel.org)
Patch lguest-2.6.21-254.patch
Distro Slackware 11.0
GCC 3.4.6
GLIBC 2.3.6
HW model name : AMD Duron(tm) procu{s{
Module Size Used by
tun 7680 0
lg 54600 0
just started playing with lguest - patching, compiling and booting the
host-kernel goes ok - compiling lguest is ok as well after
2007 Jun 01
2
lguest problem on boot of guest kernel
Hi !
Kenrel 2.6.21 (kernel.org)
Patch lguest-2.6.21-254.patch
Distro Slackware 11.0
GCC 3.4.6
GLIBC 2.3.6
HW model name : AMD Duron(tm) procu{s{
Module Size Used by
tun 7680 0
lg 54600 0
just started playing with lguest - patching, compiling and booting the
host-kernel goes ok - compiling lguest is ok as well after
2011 May 17
3
Powercom issues in NUT (was: PowerCom BNT2000AT ups on nut 2.6.0 - second try)
Dino, Alexey,
there are a number of users suffering issues with your Powercom devices.
Could you (Dino, and Keven if possible) please have a look at the below one,
from Angela, and check for a fix?
I've scheduled to release 2.6.1 next week, and having that fixed is part of
the list.
2011/5/16 Angela Williams <angierfw at gmail.com>
> Hi All
>
> On Friday 13 May 2011 at
2003 Apr 24
2
R-1.7.0 build feedback: NetBSD 1.6 (PR#2837)
R-1.7.0 built on NetBSD 1.6, but the validation test suite failed:
Machinetype: Intel Pentium III (600 MHz); NetBSD 1.6 (GENERIC)
Remote gcc version: gcc (GCC) 3.2.2
Remote g++ version: g++ (GCC) 3.2.2
Configure environment: CC=gcc CXX=g++ LDFLAGS=-Wl,-rpath,/usr/local/lib
make[5]: Entering directory `/local/build/R-1.7.0/src/library'
>>> Building/Updating