similar to: pearson residuals in glm for binomial response (PR#1175)

Displaying 20 results from an estimated 600 matches similar to: "pearson residuals in glm for binomial response (PR#1175)"

2009 Jan 10
1
Setting a contingency table
Hi, I want to set a make a contingency table which will look like this.. The problem is that I can't  set the table like the following.                      col1     col2       Total     row1              a         b         n10                      rp1       rp2        100                      cp1       cp2       rtp1   ---------------------------------------------     row2            
2017 Oct 12
1
Recurrence plots in R using different colours
Hello, I am an absolutely beginner with regards to R, so forgive me for my potentially very stupid questions. I have been attempting to create recurrence plots using R. The data I am using is based on a mutually exclusive and exhaustive coding scheme with over 40 individual codes which can be assigned to 6 higher order categories. When I carry out the usual rqa command, my plot is pretty much
2012 Jan 31
0
(gang?)block layout question, and how to decipher ZDB output?
Hello, all I''m "playing" with ZDB again on another test system, the rpool being uncompressed with 512-byte sectors. Here''s some output that puzzles me (questions follow): # zdb -dddddddd -bbbbbb rpool/ROOT/nightly-2012-01-31 260050 ... 1e80000 L0 DVA[0]=<0:200972e00:20200> DVA[1]=<0:391820a00:200> [L0 ZFS plain file] fletcher4 uncompressed
2011 Sep 06
1
Question about Natural Splines (ns function)
Hi - How can I 'manually' reproduce the results in 'pred1' below? My attempt is pred_manual, but is not correct. Any help is much appreciated. library(splines) set.seed(12345) y <- rgamma(1000, shape =0.5) age <- rnorm(1000, 45, 10) glm1 <- glm(y ~ ns(age, 4), family=Gamma(link=log)) dd <- data.frame(age = 16:80) mm <- model.matrix( ~ ns(dd$age, 4)) pred1 <-
2008 Nov 19
1
F-Tests in generalized linear mixed models (GLMM)
Hi! I would like to perform an F-Test over more than one variable within a generalized mixed model with Gamma-distribution and log-link function. For this purpose, I use the package mgcv. Similar tests may be done using the function "anova", as for example in the case of a normal distributed response. However, if I do so, the error message "error in eval(expr, envir, enclos) :
2012 Jun 08
2
Consulta GLM
Estimados amigos, Estoy familiarizándome con los modelos lineales generalizados en R. Estoy interesado en realizar un análisis lig linear y me gustaría saber cuáles son o como extraer los valores correspondientes al chi cuadrado en el análisis para cada grupo y para las interacciones. Desde ya muchas gracias y disculpas si la pregunta es muy básica, adjunto los comandos que estoy utilizando. Si
2012 Jun 08
2
Consulta sobre GLM-log linear
Estimados amigos, Estoy familiarizándome con los modelos lineales generalizados en R. Estoy interesado en realizar un análisis lig linear y me gustaría saber cuáles son o como extraer los valores correspondientes al chi cuadrado en el análisis para cada grupo y para las interacciones. Desde ya muchas gracias y disculpas si la pregunta es muy básica, adjunto los comandos que estoy utilizando. Si
2012 Jun 08
2
Consulta sobre GLM-log linear
Estimados amigos, Estoy familiarizándome con los modelos lineales generalizados en R. Estoy interesado en realizar un análisis lig linear y me gustaría saber cuáles son o como extraer los valores correspondientes al chi cuadrado en el análisis para cada grupo y para las interacciones. Desde ya muchas gracias y disculpas si la pregunta es muy básica, adjunto los comandos que estoy utilizando. Si
2008 May 08
2
poisson regression with robust error variance ('eyestudy
Ted Harding said: > I can get the estimated RRs from > RRs <- exp(summary(GLM)$coef[,1]) > but do not see how to implement confidence intervals based > on "robust error variances" using the output in GLM. Thanks for the link to the data. Here's my best guess. If you use the following approach, with the HC0 type of robust standard errors in the
2010 Aug 20
3
Deviance Residuals
Dear all, I am running a logistic regression and this is the output: glm(formula = educationUniv ~ brncntr, family = binomial) Deviance Residuals: Min 1Q Median 3Q Max # ???? ????? ?? ???????? -0.8825 -0.7684 -0.7684 1.5044 1.6516 Coefficients: Estimate Std. Error z value Pr(>|z|) (Intercept) -1.06869 0.01155 -92.487 <2e-16 *** brncntrNo
2004 Aug 19
1
The 'test.terms' argument in 'regTermTest' in package 'survey'
This is a question regarding the 'regTermTest' function in the 'survey' package. Imagine Z as a three level factor variable, and code ZB and ZC as the two corresponding dummy variables. X is a continuous variable. In a 'glm' of Y on Z and X, say, how do the two test specifications test.terms = c("ZB:X","ZC:X") # and test.terms = ~ ZB:X + ZC:X in
2009 Feb 26
1
logistic regression - unequal groups in R
I am getting a repeated error when I try to run a logistic regression in R 2.8.1 >(glm(prop1~x1,data=glm1,family=binomial("logit"),weights=nt1)) Error in model.frame.default(formula = prop1 ~ x1, data = glm1, weights = nt1, : invalid type (list) for variable 'x1' x1 is multistate categorical (3 categories). 2 of the categories have 12 observation, one has 9. Is this what
2006 Jul 13
1
step method in glm()
Hello, I estimaded two logit models via glm(). A null model (called glm00) and "full" model with all accessible covariates and interactions between them (glm1). Then I tried to get even better model by step procedure. I tried the following code: > step(glm00, scope=formula(glm1), method="both") and another one: > step(glm00, scope=formula(glm1),
2012 Jul 15
1
how to extract p-value in GenMatch function
Dear R-Users, I have a problem on extracting T-Stat and P-Value. I have written R-code below library("Matching") data("lalonde") attach(lalonde) names(lalonde) Y <- lalonde$re78 Tr <- lalonde$treat glm1 <- glm(Tr~age+educ+black+hisp+married+nodegr+re74+re75,family=binomial,data=lalonde) pscore.predicted <- predict(glm1) rr1 <-
2010 Jan 24
2
How to define degree=1 in mgcv
Hi, all I have a question on mgcv and ns. Now I want to compare the results from glm, gam and ns. Take a simple model y~x for example. glm1 = glm(y~x, data=data1) gam1 = gam(y~s(x), data=data1) ns1 = glm(y~ns(x),data=data1) In order to confirm the result from glm1 is consistent to those from gam1 and ns1, I want to define degree=1 in mgcv and ns. I am wondering if there is somebody can give me
2006 Aug 27
1
refer to objects with sequential names
Dear Listers, If I have several glm objects with names glm1, glm2.... and want to apply new data to these objects. Instead of typing "predict(glm1, newdata)..." 100 times, is there way I could do so in a loop? Thank you so much! wensui [[alternative HTML version deleted]]
2007 Feb 14
1
how to report logistic regression results
Dear all, I am comparing logistic regression models to evaluate if one predictor explains additional variance that is not yet explained by another predictor. As far as I understand Baron and Li describe how to do this, but my question is now: how do I report this in an article? Can anyone recommend a particular article that shows a concrete example of how the results from te following simple
2008 Feb 19
1
Referencing to an object within a function
I am encountering an error when I attempt to reference a glm model within a function. The function uses the segmented.glm command (package = segmented). Within the segmented.glm command one specifies an object, in this case a logistic regression model, and specifies a starting threshold term (psi). I believe this is an environment problem, but I do not have a solution. Any assistance
2010 Jun 03
1
compare results of glms
dear list! i have run several glm analysises to estimate a mean rate of dung decay for independent trials. i would like to compare these results statistically but can't find any solution. the glm calls are: dung.glm1<-glm(STATE~DAYS, data=o_cov, family="binomial(link="logit")) dung.glm2<-glm(STATE~DAYS, data=o_cov_T12, family="binomial(link="logit")) as
2004 May 07
1
contrasts in a type III anova
Hello, I use a type III anova ("car" package) to analyse an unbalanced data design. I have two factors and I would have the effect of the interaction. I read that the result could be strongly influenced by the contrasts. I am really not an expert and I am not sure to understand indeed about what it is... Consequently, I failed to properly used the fit.contrast function (gregmisc