Displaying 20 results from an estimated 2000 matches similar to: "CI for wilcoxon test (PR#895)"
2001 Apr 05
1
PR#896
Sorry to all that are angry about the form of my previous mail. I
didn't realise what would happen :((.
Here it is in (hopefully) plain text (if my mailer doesn't spoil it again):
##############
Dear developers,
I have a problem with some discrepancy between R 1.2.1 for
Windows and R 1.2.2 (and less) for Linux. While trying to correct
the wilcox.test (see my previous bug report) I
2002 Jun 07
2
Hope fo help - functions, fits and for cycles
I need a little piece of advice concerning passing data frames
into the functions. As I do a lot of similar fits at a time, I'd like to
write a small function doing the fits for all relevant variables
automatically. However, I usually get error messages of the
following kind:
(I present here a part of a test code).
#####################################################
# Data set:
2010 Sep 24
3
Odds ratio from Logistic model in R
Hi, I am new to R. Anyone can explain the following from R-help or
anyone can direct me how to calculate odds ratio from logistic model in
R. Thank you very much. Guoya
Stefano <stecalza at tiscalinet.it
<https://stat.ethz.ch/mailman/listinfo/r-help> > writes:
>Hi all.
>
>A simple question.
>Is there a function to compute the Odds Ratio and its confidence
intervall,
2011 Apr 06
1
metaplot
Dear all,
I have a four variable: Stuy.Name, OR, 95%LCI and 95%UCI and I would like to
create a meta analysis plot. I can't use meta.MH function in metaplot
because I do not have
n.trt, n.ctrl, col.trt, col.ctrl are not available! Is there an alternative
way to do it?
Many thanks in advance,
Cheba
[[alternative HTML version deleted]]
2014 Sep 08
3
problema con los cambios de marcas temporales en el eje X
Muchísimas gracias Carlos, de verdad que te agradezco la ayuda, pero no es lo que voy buscando. Quiero colocar en el eje de abscisas la secuencia temporal de los meses, es decir, agosto septiembre, octubre, etc? pero no las fechas de las toma de datos, sino que aparezca la marca de un mes, y la siguiente marca sea la del siguiente mes, etc?, y además que las muestras estén separadas de acuerdo con
2014 Sep 08
2
problema con los cambios de marcas temporales en el eje X
Muchas gracias Carlos, previo a mi correo, entre las pruebas que hice estaba una parecida a la que apuntas de la siguiente manera:
attach (Libro1)
plot (xbar~as.Date(fechas,"%d/%m/%y"), ylim=c(400,660), xaxt="n", type="b", pch=19,cex=1)
xlabels<-strptime(fecha,format="%d/%m/%Y")
axis.Date (1,at=xlabels,format="%b-%y")
2014 Sep 08
3
problema con los cambios de marcas temporales en el eje X
Hola de nuevo, acabo de encontrar la solución. He creado una variable ficticia con los días 1 de cada mes en la secuencia temporal que quería y después he actuado de la siguiente manera
attach(Libro1)
plot (xbar~as.Date(fecha,"%d/%m/%y"), type="b", pch=19,cex=2,xaxt="n")
xlabels<-strptime(ofeje, format = "%d/%m/%y")
axis.Date(1,
2014 Sep 07
3
problema con los cambios de marcas temporales en el eje X
Estimada Comunidad, solicito vuestra ayuda en un tema quizás un poco tonto, pero no logro dar con la tecla.
Estoy intentando hacer una gráfica de la evolución temporal de una variable (xbar) a lo largo del tiempo.
La secuencia que he hecho es la siguiente:
attach(Libro1)
plot (xbar~as.Date(fechas,"%d/%m/%y"), ylim=c(400,650), type="b", pch=19,cex=1)
2009 Mar 22
1
barplot2 x-axis
Dear R users,
I am trying to build a barplot2 graph however I can't find a way of defining
the scale for the x-axis.
I would like to show in my x-axis only the numbers 0, 25, 50, 75 etc. (so
far R is giving me a random scale hard to interpret and it doens't look
nice...). Could anyone advise me on how to do this please, it would be a
great help! Thank you.
Below I show the code I have
2005 Dec 06
3
Coefficient of association for 2x2 contingency tables
Hi,
Found no measure of association or correlation for 2x2 contingency tables in
fullrefman.pdf or google. Can someone point to a package that implements such
calculations?
Thanx.
--
Alexandre Santos Aguiar
- consultoria para pesquisa em sa??de -
R Botucatu, 591 cj 81
tel 11-9320-2046
fax 11-5549-8760
www.spsconsultoria.com
2005 Aug 26
1
Help in Compliling user -defined functions in Rpart
I have been trying to write my own user defined function in Rpart.I
imitated the anova splitting rule which is given as an example.In the
work I am doing ,I am calculating the concentration index(ci) ,which
is in between -1 and +1.So my deviance is given by
abs(ci)*(1-abs(ci)).Now when I run rpart incorporating this user
defined function i get the following error message:
Error in
2011 Oct 13
0
xyplot() and confidence interval polygons
Dear all,
I'm trying to replicate the panel function behaviour that Deepayan and
others discuss here:
https://stat.ethz.ch/pipermail/r-help/2007-April/130779.html
and Oscar Lamigueiro refers to here and provides sample code for:
http://www.r-bloggers.com/confidence-bands-with-lattice-and-r/
where a polygon is generated around lines on panels to display the
confidence interval bounds for
2002 Nov 03
1
Ansari-Bradley test (PR#2252)
Full_Name: Wei Xu
Version: 1.5.1
OS: WindowsME
Submission from: (NULL) (63.215.238.92)
The P-value for a two.sided test is not consistent with the confidence
interval.
For example, P-value=0.1372, but the 95% CI doesn't include the H0 value(1).
> x
[1] 0.80 0.83 1.89 1.04 1.45 1.38 1.91 1.64 0.73 1.46
> y
[1] 1.15 0.88 0.90 0.74 1.21
>
2000 Oct 19
2
Multiple outputs of a function
Hello everybody,
I'm writting some functions for experimental designs. The one I'm
working on is similar to "fac.design" on Splus.
The problem I have is with the form of the output :
When the argument fraction is submitted, Splus gives something like :
A B C
1 - - -
2 + + -
3 + - +
4 - + +
Fraction : ~A:B:C
The first part of this output is the
2012 Jun 26
2
MuMIn - assessing variable importance following model averaging, z-stats/p-values or CI?
Dear R users,
Recent changes to the MuMIn package now means that the model averaging command (model.avg) no longer returns confidence intervals, but instead returns zvalues and corresponding pvalues for fixed effects included in models.
Previously I have used this package for model selection/averaging following Greuber et al (2011) where it suggests that one should use confidence intervals from
2009 Feb 02
1
wilcoxon test with bonferroni correction
Hi!
I need to run a wilcoxon (Mann-whitly, in fact) test with bonferroni
correction, as I am running 10 consecutive wilcoxon test not
independent, and I know that bonferroni will partially correct for
this problem, but I have no idea how to do it with R, I have been
looking in the archive but couldn't understand how to do it.
The format I am using at the moment is
r4_o <-
[1]
2005 Nov 23
2
wilcoxon.test?
Hello there,
I would like to do a Wilcoxon matched pairs signed rank sum test in R
and tried the function wilcoxon.test. Is it in the "base" library? If
not, please let me know which library it is in.
Thank you in advance for your help
Lisa Wang
Biostatistician
Princess Margaret Hospital
Toronto, Ca
2011 Oct 31
2
one sample Wilcoxon test using 'coin'
Hi,
R allows me to run a one sample Wilcoxon test like this:
wilcox.test(c(1,3.5,2.1,4,1.5,5), mu=2, exact=TRUE)
The function 'wilcoxsign_test' from the package 'coin' should (I
suppose) be able to calculate exact p values even if there are ties in
the ranks. However, I couldn't find information on how to run a one
sample test using 'wilcoxsign_test' like in the
2011 Apr 13
2
Wilcoxon rank sum in unbalanced design
Hi everyone!
I need to perform a Wilcoxon rank sum test, but I have some ties and the
groups have different size also. When I deal with ties I use the
wilcox.exact function, how can I solve the different size problem using this
function?
thanks
net
--
View this message in context: http://r.789695.n4.nabble.com/Wilcoxon-rank-sum-in-unbalanced-design-tp3447400p3447400.html
Sent from the R help
2012 Nov 25
2
Finding the Degrees of Freedom in a Wilcoxon Test
Dear R-ers,
I am currently running some Wilcoxon tests in R-64.
How do I find the degrees of freedom in the output I am receiving?
> wilcox.test(good$TRUE, good$x4a, paired=FALSE)
Wilcoxon rank sum test with continuity correction
data: good$TRUE and good$x4a
W = 2455, p-value < 2.2e-16
alternative hypothesis: true location shift is not equal to 0
Thank you,
Stephen.