similar to: Compare two matrices in r

Hi all, I want to find all the mappings of one graph in another graph, based on their vertex labels Is there any way to do this in igraph based on vertex labels. (as far as i know Igraph allows the subgraph isomorphism based only on vertex and edge colors) Eg: graph 1: x(1) x(2) x(2) y(3) y(4) x(1) z(5) x(2) graph 2: x(1) y(2) # the brackets contain the corresponding vertex ids i would like my

Dear all, I would like to generate 500 matrices of 20 numbers from standard normal distribution with names x1,x2,x3,….x500.   I tried with loop for, but I don’t know how to name matices : for (i in 1:500)  {    x[[i]] <- matrix(rnorm(20), 4)     } Any suggestion? Thanks,  Blaž [[alternative HTML version deleted]]

Dear all, I have some trouble with special characters while building my R package. I tried to follow the usual LATEX format, but could not fix the problem: For instance, for "greater than or equal", I tried "\geq", but R says that this is an unknown macro. Could anyone direct me how to solve this issue? Best Ozgur ----- ************************************ Ozgur ASAR

Hello R-Experts, I am facing the problem that I have to estimate several parameters for a lot of different dependent variables. One single regression looks something like this: y = beta0 + beta1 * x1 + beta2 * x2 + beta3 * x1 * x2 + beta4 * x4 + beta5 * lag(x4,-1) where y is the dependent variable and xi are the independent ones. Important to me are the different estimates of betai and their

Hello, I have a dataframe (Lx) with 5 Lb, and 5 Lw variables. I want to create several variables according to the loop presented below (data attached). Lx <- read.csv("Lx.csv", header=T, sep=",") for (i in 1:20) { Lx$sb1[i] <- Lx$Lb1[i+1]/Lx$Lb1[i] Lx$sb2[i] <- Lx$Lb2[i+1]/Lx$Lb2[i] Lx$sb3[i] <- Lx$Lb3[i+1]/Lx$Lb3[i] Lx$sb4[i] <-

Hi, Your mistake seems to be in sum(v[1:x]) You create "x" as a vector but your treat it as a single number. v[1:x] expects "x" to be a single number and only considers its first element which is 1. If I understand your query correctly, the following might handle your problem: sum.vec <-NULL for (x in 1:1000){ t <- rbinom(1000, 1, 0.5) v <- replace(t,t==0,-1)

Dear all, Actually I could not decide who to contact, then decided to post here. If not appropriate sorry for that. I have written some functions in R which might be supposed to available in the base package but not available. I am wondering that how can I submit those functions to that package? Best Ozgur ----- ************************************ Ozgur ASAR Research Assistant Middle East

Hi group, I've been thinking of calculating euclidean distance between each column of a data frames that each consists of standardized numerical columns. However, I don't know if there's a way of summarizing the overall distance by some kind of metrics. If anyone know a proper way of doing so and/or a package I would greatly appreciate your suggestions. Thanks very much! Kel --

Dear all, I want to concatenate the elements of two vectors such as a<-c("a1","a2") b<-c("b1","b2") and obtain "a1b1", "a1b2","a2b1","a2b2" I tried the paste and paste0 functions, but they yielded elementwise concatenation such as "a1b1","a2b2" I am wondering that is there an efficient

Dear all, I want to manipulate a character string such as ex<-"cbind(data$response1,data$response2)" in R in two ways: 1) extracting the "response1" portion of ex 2) replacing "$" with "." I am wondering that is it possible efficiently doing these in R? Best Ozgur -- View this message in context:

It is not really a bug but a strange choice. When the option freq=F chosen, hist should plot relative frequency. It plots proportional to relative frequency by the factor of bin width. Is there a reason for this? A more normal choice seems to be to have it independent of the bin width. Yash Mittal University of Arizona ---------------------------------------------------------------- This

platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32 status major 1 minor 7.1 year 2003 month 06 day 16 language R I have a Dell Inspiron 4000 laptop with Windows ME. I recently installed the 1.7 version of R. The following commands are from my

hello, I try to run simulation of levene's test to find the p-value but the error of replacement has length zero occur, could anyone help me to fix this problem? asim <- 1000 pv<-rep(NA,asim) for(i in 1:asim) {print(i) set.seed(i) g1 <- rnorm(20,0,2) g2 <- rnorm(20,0,2) g3 <- rnorm(20,0,2) x <- c(g1,g2,g3) group<-as.factor(c(rep(1,20),rep(2,20),rep(3,20))) library(Rcmdr)

https://bugzilla.mindrot.org/show_bug.cgi?id=1285 Vladimir Rutsky <rutsky.vladimir at gmail.com> changed: What |Removed |Added ---------------------------------------------------------------------------- CC| |rutsky.vladimir at gmail.com -- You are receiving this mail because: You are watching the assignee of

Hello, Has anyone wrote a how-to or a guick guide on how to encrypt an existing partition/disk using gbde? I've tried to search in the net but i cudn't find any. Is it possible to just move the existing data on my disk, cleanup the disk and encrypt using gbde, attach to the system, then move back the data to the now encrypted disk. Thanks, - ronnel

Hello, I want to use the function barplot do display several group of bars. A standard example is given at this link http://onertipaday.blogspot.com/2007/05/make-many-barplot-into-one-plot.html But in their example the 4 groups of bars are all composed of 8 bars. I want to be able do display the same kind of graph but where the number of bars in each group are not the same. For example the

Dear list users, I have a data frame as below specified. From the 1st of May to the 30th of September of several years (e.g. from 2004 to 2011) I have a frequency of accidents. I need the mean of accidents divided by weeks (i.e. the mean of accidents from the 1st to the 7th of May of all the years, from the 8th to the 14th of May, ..., from the 29th to the 31st of May, from the 1st to the 7th of

Dear R users, I'd like to remove some descriptions when I use "filter". > filter(1:10, rep(1, 3)) Time Series: Start = 1 End = 10 Frequency = 1 [1] NA 6 9 12 15 18 21 24 27 NA That is, I want only this [1] NA 6 9 12 15 18 21 24 27 NA Thank you in advance. Kathie -- View this message in context:

Hi Do I have to load/download the whole package over and over again everytime when I use the R-Project? It often prompt me the error message "could not find function"- but I'm rather sure I have used the function before so I'm not entirely sure it couldn't find it again when I shut down the computer or so. Is it to do with directory or clashing with other software? Any

Dear R community, I am a beginner using the sciplot package to graph barplots. I would like to be able to graph two x factors (Sampling.year and Period). Sampling.year: 2006, 2007, 2008, 2009 Period: First, Second, Total The parameter "group" is the different species I looked at. They can be seen in the legend. The parameter "response" is the Average percentage