similar to: Applying a function to a column of a data frame

R-Help community, I understand that data.frames can hold elements of type double, string etc but NOT objects (such as a matrix etc). This is not convenient for me in the following situation. I have a function that takes 2 inputs and returns a vector: testfun <- function (x,y) seq(x,y,1) I have a data.frame defined as follows: testframe<-data.frame(xvalues=c(2,3),yvalues=c(4,5)) I would

Hello all R gurus, I have a following problem which I hope someone will help me to solve. I have a data.frame in form similar to below. > testframe<-data.frame("Name"=c("aa","aa","aa","aa","aa","bb","bb","bb","bb","bb"),"Value"=c(1,100,1,1,1,100,100,100,100,1))

Hi All I have a dataframe: myframe<-data.frame(ID=c("first","second"),x=c(1,2),y=c(3,4)) And I have a function myfun: myfun<-function(x,y) x+y I would like to write a function myfun2 that takes myframe and myfun as parameters and returns a list as below: mylist $first [1] 4 $second [2] 6 Could you please help me with this? Doesn't seem like the

With rw2010dev I get a strange protect(): protection stack overflow error with a small data frame which otherwise is usable: If anybody wants to have a look I can provide an RData file with the problematic data frame. Doesn't seem to be necessary, the following simulated example generates the error: > testmat <- matrix(1:80, 20,4) > dim(testmat) [1] 20 4 > str(testmat) int

Hi (Duncan?), The other day I noticed some characters will cause errors in R CMD CHECK because of parse_Rd(), and AFAIK, these chars include '%', '{' and '}'. For example, note the comments in the example section: %~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~% \name{testfun} \Rdversion{1.1} \alias{testfun} \title{ A Test } \description{ A test } \usage{ testfun() } \value{ NULL }

All, I am not understanding the scoping used in foreach when it is used inside a function. I keep getting "could not find function" errors for functions that are in memory when I try to use foreach within a function call. I have a simple example below. "testFun" is in memory and works when called by foreach directly, but when I place foreach in a function called

Dear R users, I am running R-2.15.1 in Linux Slackware64-14.0. Here is my minimal working example: testfun <- function (x) { a <- 0; sapply(X="a", FUN=get, envir=sys.frame(which=x)); } Inside R, that is R called from within a Linux terminal, the following code works: testfun(x=5) print(testfun(x=6)) But within rkward the above code fails and the following works: testfun(x=1)

Dear All, I have three classes of questions about generating random numbers with different packages (windows xp 32bit R). . 1. Suppose I would like to use package *foreach*, can I use current Sys.time as a seed? Although I can get the time up to1e-6 second precesion, the code below dose not work well on a local machine with two cores. ################# library(foreach) library(snow)

Hi Luke, Ah - I see - thank you! This at least points me to a way on how to "fix" this. I tried setting the srcref attribute to NULL, but the hash value is still different and so is the serialization. So this looks like it is one difference, but not all of them Even if all differences were identified - it still leaves me with different behavior between interactive and batch-mode,

Hello R Community, I have the following design question. I have a data set that looks like this (shortened for the sake of example). Gender Age M 70 F 65 M 70 Each row represents a person with an age/gender combination. We could put this data into a data frame. Now, I would like to do some actuarial analysis on this data set. To do so, I need to create and store

First, thanks to all who helped me with my question about rescaling axes on the fly. Using unlist() and range() to set the axis ranges in advance worked well. I've since plotted about 300 datasets with relative ease. Now I'm trying to fit a lossy oscillator resonance to (the square root of) a lorentzian (testframe$y is oscillator amplitude, testframe$x is drive frequency): lorentz

Full_Name: Robert Denham Version: R-2.4.1 OS: Windows Xp Submission from: (NULL) (61.88.57.1) R gui exits without warning when I run a function which has an argument with a default that is not found. This was a result of an error in a function I wrote, but I thought that it should exit more gracefully than it does. Here is an example: testfun <- function(aa=aa) { aa <-

Dear R community, My question is not a quick fix one but it would be helpful if you have any advice for me. I have a large data set of many locations in the US and all of these locations are expressed in coordinates (longitudes and latitudes). I need a tool which returns the state that each location is situated in. So the program should return me a vector of state names (eg. NY,CA,OH, etc).

Hi, I posted this question to the regular help list, but it seems to be this is probably a question that is better addressed on r-devel. Sorry for the double posting. I am using hash-values to cache certain results in R. This caching also depends on the hash-value of the function that is being cached (calculated using the digest package). I noticed that computations that should already be cached

Dear all, Why does not the three-dot accept arguments from the parent environment? I am just confused with this error, can someone give me a hint? > rm(list=ls()) > testFun <- function(a, ...) + { + if(a){ + print(a) + }else + { + print(b) + } + } > > myTask <- function(a) + { + b <- 3 + testFun(a, b = b) + } >

Hi Gabriel, thanks for your reply - it does solve the problem of my toy function, but does come with some other problems though. a) as.list(f)[[1]] yields an expression, not a function. In order to go the route you are suggesting, I would more likely use "deparse" in order to get the original back b) and more seriously - as.list strips the environment of the function (and thus

Greetings, I am attempting to run a function, which produces a vector and requires two input variables, across two nested factor levels. I can do this using by(X, list(factor1, factor2), function), however I haven't found a simple way to extract the list output into an organized vector form. I can do this using nested loops but it isn't exactly an optimal approach. Thank you

I am trying to use a custom S4 object in my C code and I cannot get the access to its slots working. The following is a toy example, but even this crashes. In R I have: setClass("pd", representation(data="numeric")) x <- new("pd", data=1:5) test <- function(pd.obj) { res <- .C("TestFun", pd.obj) res} test(x) (Of couse

Dear guRus, I'd like to learn how to make a function recognize the name of an object/vector given as argument If I have : testFun <- function(x,y) plot(x,y, main=paste("plot of",names(x),"and",names(y)) ) # this just a simple example ... a1 <- 5:8 b1 <- 9:6 testFun(a1,b1) # Returns the plot, but not the names of the objects/vectors given as arguments, # but

First, here's the problem I'm working on so you understand the context. I have a data frame of travel activity characteristics with 70,000+ records. These activities are identified by unique chain numbers. (Activities are part of trip chains.) There are 17,500 chains. I use the chain numbers as factors to split various data fields into lists of chain characteristics with each element of