similar to: Identifying the particular X or Y in a sorted list

I am following a document teaching how to use regression and right at the onset I get an R error. I understand that variables "conc" and "signal" should have the same length but I am using the what R manual suggests to drop the error and it is not cooperating. What gives? The manual says that the default is na.ombit by the way, not that it's addition does anything How

I would like to plot two data sets (frequency (y-axis) of mean values for 0-1(x=axis)) on a single histogram for comparison. The hist() only allow the overlay of two histograms, and although barplot() allows beside=TRUE, it does not show frequency values (like hist) but rather all of the values. Is there any way that I can use the hist() to plot two data sets similar to the barplot(). Any help or

Hello all, I'm just starting to learn R and I heard a good way of doing that was R Commander. For my work I use a lot of time series, so I installed (and loaded) R Commander with epack. When I go to Ts-Models, after loading my data, I click on ARIMA Models tab. I load my variable D1 Ln Demand (1st differenced ln demand). I set my regular and seasonal p d q settings hit run and I get: [1]

Hi, My error isErro em hist.default(dados[[1]], freq = TRUE, seq(0, 30, 0.5), prob = FALSE, : some 'x' not counted; maybe 'breaks' do not span range of 'x' hist(dados[[1]],seq(0, 30, 0.5), prob=TRUE, xlab="chuva (mm/dia)",ylab="frequência", main="", cex.lab=1.6, cex.sub=3,cex.axis=3,cex.main=6) Someone help me? [[alternative

Hello together, perhabs anyone of you, has an ideal, how i can do this: I have a matrix, like this one: [,1] [,2] [,3] [,4] abnr2 11425 11425 11555 11888 TIME 2 1 1 2 Cat 1 2 1

Hi all, I have some graphs where the values on the X and Y axes are by default in exponent form like 2e+05 or 1.0e+07. Is it possible to make them in a more readable form like 10M for 1.0e+07 or 200K for 2e+05? Thanks and Regards, - vihan

I am lousy at simple regex and I have not found a solution to a simple problem. I have a vector with some character values that I want to split. Sample data dd1 <- c( "XXY (mat harry)","XXY (jim bob)", "CAMP (joe blow)", "ALP (max jack)") Desired result dd2 <- data.frame( xx = c("XXY", "XXY", "CAMP",

Hello all, I would appreciate your thoughts on a seemingly simple problem. I have a database, where each row represent a single record. I want to aggregate this database so I use the aggregate command : D<-read.csv("C:\\Users\\test.csv") attach(D) by1<-factor(Class) by2<-factor(X) W<-aggregate(x=Count,by=list(by1,by2),FUN="sum") The results I

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Hi, I want to make a plot similar to sm1 (attached). The code I tried is: dcols <- densCols(x,y) smoothScatter(x,y, col = dcols, pch=20,xlab="A",ylab="B") abline(h=0, col="red") But it turned out to be s1 (attached) with big dots. I was wondering if anything wrong with my code. Thanks,Zhengyu -------------- next part -------------- A non-text

Hello R community, I am computing weighted average statistic by using ddply function: My data set is: N1 T1 S1 I1 C1 FY-4 ROE11 EPS11 MKT11 N1 T1 S1 I1 C1 FY-3 ROE12 EPS12 MKT12 N1 T1 S1 I1 C1 FY-2 ROE13 EPS13 MKT13 N1 T1 S1 I1 C1 FY-1 ROE14 EPS14 MKT14 N1 T1 S1 I1 C1 FY0 ROE15 EPS15 MKT15 N1 T1 S1 I1 C1 FY1 ROE16 EPS16 MKT16 N1 T1 S1 I1 C1 FY2 ROE17

Dear list, Is there a elegant way to name multiple ordered plot as A, B, C and D? Just put A, B, C and D on the top left corner of each plot. Usually I do it in Illustrator, but I think in R should there is a way. Could you please provide a example? Thank you very much in advance.

R-SIG-Debian I am very new to Linux so I probably am doing something stupid but I cannot seem to update to R 2.15 Using Ubuntu 12.02 Precise Penguin I realise that debian packages are not updated regularly so I tried to follow the insructions at the R-site So far, I have modified /etc/apt/sources.list to read ## R CRAN added 2012-06-12 deb http://probability.ca/cran/bin/linux/debian

Hi, Kbytes RSS rNo 2689632 1450876 1433788 2689632 1450876 1433788 2689632 1450876 1433788 2689632 1450876 1433788 2689632 1450876 1433788 2689632 1450876 1433788 2689632 1450876 1433788 2689632 1460168 1443084 plot(data$rNo,data$RSS,pch=0,type="b",col=36,axes=FALSE, ylab="", xlab="",las=2,lwd=2.5) title(" PID -

I seem to be doing something really stupid or missing something really obvious but what? I have a simple three column data.frame that I would like to reshape to wide preferably using reshape2. An example from http://stackoverflow.com/questions/9617348/reshape-three-column-data-frame-to-matrix looked perfect except I wanted a data frame but it seemed okay. I just changed acast to dcast and it

Hi Keith,, ggpairs(dat1, upper = list(continuous = "density", combo = "box")) appears to be what you want. John Kane Kingston ON Canada > -----Original Message----- > From: kw1958 at gmail.com > Sent: Tue, 11 Jun 2013 09:25:48 -0400 > To: r-help at r-project.org > Subject: Re: [R] R-help Digest, Vol 124, Issue 12 > > Folks, > > Sorry for

Dear list, I am looking for a possibility to present results in a more graphical way by adding an axis. But I have trouble relating my data to the added axis. Imagine the following example: a <- c(10, 20, 30, 40) b <- c(50, 250, 500, 600) ba <- b/a par(las=1, mar=c(5,5,.5,5)) plot(a,b, type="b", pch=22, cex=2, col=4, lwd=2, ylim=c(0,650), xlim=c(0,45)) axis(4,

hi i try to do a graph of a time series which shows in red the values > -0.05, in blue the values >0.05 and in white the values between -0.05 and 0.05 for un exemple :http://www.appinsys.com/globalwarming/enso.htm thanks !!!!! denisse -- View this message in context: http://r.789695.n4.nabble.com/how-to-do-a-graph-with-tree-different-colors-tp4635206.html Sent from the R help mailing

Folks, Sorry for butting in here. I ran the code from John Kane below and it worked fine. I did however get a deprecation message suggesting the use of ggpairs from the GGally package to make this chart. Unfortunately I haven't found the correct incantation to get the diagonal to display the density plots using the "diag" parameter. Any suggestions? Just trying to learn,

Hello all R users, My simulation function works correctly, but I have problems with plot function. You will find the following code using it. Thank you for your help ##################################################" simulation <- function(k, n){ conc <- seq(0,10,by=0.5) #choixg <- seq(1, length(conc)) choixg <- rep(0,length(conc)) for (i in 1:length(conc)){ choixg[i]